Question Number 143168 by Cwesi last updated on 10/Jun/21
Commented by mr W last updated on 10/Jun/21
$${x}=\mathrm{42}+\mathrm{40}+\mathrm{32}=\mathrm{114}° \\ $$
Commented by mr W last updated on 10/Jun/21
Answered by Cwesi last updated on 11/Jun/21
$$\angle{BOC}=\mathrm{42}+\mathrm{40}+\mathrm{32} \\ $$$$\angle{BOC}=\mathrm{82}+\mathrm{32} \\ $$$$\angle{BOC}=\mathrm{114}° \\ $$
Answered by JDamian last updated on 10/Jun/21
$$\hat {{A}}+\hat {{B}}+\hat {{C}}=\mathrm{180}° \\ $$$$\mathrm{40}°+\left(\mathrm{32}°+{b}\right)+\left(\mathrm{42}°+{c}\right)=\mathrm{180}° \\ $$$${b}+{c}=\mathrm{180}°−\mathrm{114}° \\ $$$${x}+{b}+{c}=\mathrm{180}° \\ $$$${x}=\mathrm{180}°−\left({b}+{c}\right) \\ $$$${x}=\mathrm{180}°−\left({b}+{c}\right)=\mathrm{180}°−\left(\mathrm{180}°−\mathrm{114}°\right) \\ $$$$\boldsymbol{{x}}=\mathrm{114}° \\ $$
Commented by Frederick last updated on 11/Jun/21
$$\mathrm{correc}\:\mathrm{answer} \\ $$