Question Number 143463 by Dwaipayan Shikari last updated on 14/Jun/21
$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}{tan}\left(\frac{{k}\pi}{\mathrm{2}{n}+\mathrm{1}}\right)=\sqrt{\mathrm{2}{n}+\mathrm{1}} \\ $$
k-1-n-tan-kpi-2n-1-2n-1-