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tan-1-x-sec-x-1-sec-x-sec-x-dx-

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Question Number 221203 by Nicholas666 last updated on 27/May/25 $$ \\ $$$$\:\:\:\:\:\int\:\mathrm{tan}\left(\frac{\frac{\mathrm{1}}{{x}}}{\mathrm{sec}\left({x}\right)}\right)\:+\:\frac{\mathrm{1}\:−\:\mathrm{sec}\left({x}\right)}{\mathrm{sec}\left({x}\right)}\:\mathrm{d}{x} \\ $$$$ \\ $$ Answered by SdC355 last updated on 27/May/25 $$\int\:\:\left[\mathrm{tan}\left(\frac{\mathrm{cos}\left({z}\right)}{{z}}\right)+\mathrm{cos}\left({z}\right)−\mathrm{1}\right]\:\mathrm{d}{z}=?? \\…

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Question-221188

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Question Number 221188 by ajfour last updated on 26/May/25 Commented by Frix last updated on 27/May/25 $$\left(\mathrm{1}\right)\:\mathrm{We}'\mathrm{re}\:\mathrm{looking}\:\mathrm{at}\:\mathrm{the}\:\mathrm{cube}\:\mathrm{diagonally} \\ $$$$\mathrm{because}\:\mathrm{the}\:\mathrm{vertexes}\:\mathrm{touch}\:\mathrm{both}\:\mathrm{the}\:\mathrm{sphere} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{cone} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{I}\:\mathrm{think}\:\mathrm{we}\:\mathrm{need}\:\mathrm{1}\:\mathrm{more}\:\mathrm{information} \\ $$…

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