Question Number 220820 by SdC355 last updated on 19/May/25 Commented by SdC355 last updated on 19/May/25 $$\mathrm{Q220800} \\ $$ Answered by MathematicalUser2357 last updated on…
Question Number 220790 by SdC355 last updated on 19/May/25 $$\mathrm{Complex}\:\mathrm{integral} \\ $$$$\oint_{\:\mathrm{C}} \:\frac{\mathrm{d}{z}}{{z}^{\mathrm{3}} +\mathrm{1}}=??\:,\:{C};{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{4} \\ $$$$\oint_{\:{C}} \:\frac{\mathrm{1}}{{z}}{e}^{{z}} \:\mathrm{d}{z},\:{C};\begin{cases}{{y}=\mathrm{1}\:,\:−\mathrm{1}\leq{x}\leq\mathrm{1}}\\{{y}=−\mathrm{1}\:,\:−\mathrm{1}\leq{x}\leq\mathrm{1}}\\{{x}=\mathrm{1}\:,\:−\mathrm{1}\leq{y}\leq\mathrm{1}}\\{{x}=−\mathrm{1}\:,\:−\mathrm{1}\leq{y}\leq\mathrm{1}}\end{cases}\: \\ $$ Answered by vnm…
Question Number 220791 by Nicholas666 last updated on 19/May/25 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{\:\mathrm{0}} ^{\:\mathrm{1}} \:\frac{{x}^{\mathrm{2}} }{\boldsymbol{\mathrm{sin}}\:{x}\:+\:\mathrm{1}}\:{dx} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 220800 by SdC355 last updated on 19/May/25 $$\mathrm{To}\:\mathrm{Tinkutara} \\ $$$$\begin{bmatrix}{\mathrm{a}}\\{\mathrm{b}}\end{bmatrix},\begin{vmatrix}{\mathrm{a}}\\{\mathrm{b}}\end{vmatrix},\begin{pmatrix}{\mathrm{a}}\\{\mathrm{b}}\end{pmatrix}\:,\begin{cases}{\mathrm{a}}\\{\mathrm{b}}\end{cases}\:,\:\:\left.\begin{matrix}{\mathrm{a}}\\{\mathrm{b}}\end{matrix}\right\}\:,\begin{array}{|c|c|}{\mathrm{abcdefg}}\\{\mathrm{pqrstvw}}\\\hline\end{array}\:\mathrm{is}\:\mathrm{work}\:\mathrm{well} \\ $$$$\mathrm{but}\:\mathrm{invisible}\:\mathrm{line}\:\mathrm{matrix}\left(?\right)\:\mathrm{dosen}'\mathrm{t}\:\mathrm{work} \\ $$$$\mathrm{pls}\:\mathrm{Fix}\:\mathrm{bug} \\ $$ Answered by SdC355 last updated on 19/May/25…
Question Number 220764 by Nicholas666 last updated on 18/May/25 $$ \\ $$$$\:\:\boldsymbol{\mathrm{L}}=\:\boldsymbol{\mathrm{lim}}\underset{\:\boldsymbol{{n}}\rightarrow\infty} {\:}\left(\underset{\boldsymbol{{k}}=\mathrm{1}} {\overset{\boldsymbol{{n}}} {\sum}}\:\frac{\boldsymbol{{k}}}{\boldsymbol{{n}}^{\mathrm{2}} +\boldsymbol{{k}}^{\mathrm{2}} }\right).\left(\underset{\:\mathrm{0}} {\int}^{\:\mathrm{1}} \boldsymbol{{e}}^{−\boldsymbol{{x}}^{\mathrm{2}} } \boldsymbol{{dx}}\overset{−\mathrm{1}} {\right)}.\left(\underset{\boldsymbol{{m}}=\mathrm{0}} {\overset{\infty} {\sum}}\:\frac{\left(−\mathrm{1}\right)^{\boldsymbol{{m}}} }{\left(\mathrm{2}\boldsymbol{{m}}+\mathrm{1}\right)\mathrm{3}^{\boldsymbol{{m}}}…
Question Number 220730 by Nicholas666 last updated on 18/May/25 $$ \\ $$$$\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \:\frac{\mathrm{1}}{\:\sqrt{{x}\left(\mathrm{1}\:−\:{x}\right)\left(\mathrm{1}\:+\:{kx}\right)}}\:{dx}\:,\:\left(−\mathrm{1}\:<\:{k}\:<\:\mathrm{1}\right)\:\:\: \\ $$$$ \\ $$ Answered by SdC355 last updated on 18/May/25…
Question Number 220726 by mr W last updated on 18/May/25 Commented by mr W last updated on 18/May/25 $${an}\:{other}\:{method}\:{for}\:{Q}\mathrm{220630} \\ $$$${without}\:{trigonometry} \\ $$ Commented by…
Question Number 220755 by SdC355 last updated on 18/May/25 $$ \\ $$$$\mathrm{Hmm}….\mathrm{i}\:\mathrm{need}\:\mathrm{a}\:\mathrm{help}… \\ $$$$\mathrm{generalize}\: \\ $$$$\mathcal{L}_{{z}} ^{−\mathrm{1}} \left\{\frac{\mathrm{1}}{{z}^{{n}} +\mathrm{1}}\right\}=\:\oint_{\:{C}} \:\:\frac{{e}^{{zt}} }{{z}^{{n}} +\mathrm{1}}\:\mathrm{d}{z} \\ $$ Terms…
Question Number 220744 by Spillover last updated on 18/May/25 Answered by mr W last updated on 18/May/25 $${each}\:{match}\:{has}\:{three}\:{possible} \\ $$$${results} \\ $$$$\mathrm{12}\:{matches}\:{have}\:\mathrm{3}^{\mathrm{12}} =\mathrm{531}\:\mathrm{441} \\ $$$$\:{possible}\:{results}…
Question Number 220712 by Nicholas666 last updated on 18/May/25 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{prove}: \\ $$$$\:\:\frac{\mathrm{2}\:{tan}\:\mathrm{2}{A}\:+\:{tan}\:{A}}{\mathrm{4}\:{tan}\:\mathrm{3}{A}\:−\:{tan}\:\mathrm{2}{A}}\:=\:{sin}^{\mathrm{2}} \:{A} \\ $$$$\: \\ $$ Terms of Service Privacy Policy Contact:…