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Author: Tinku Tara

Question-220700

Question Number 220700 by universe last updated on 17/May/25 Answered by Frix last updated on 17/May/25 $${a}_{\mathrm{0}} =\sqrt{\mathrm{6}}+\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}} \\ $$$${a}_{\mathrm{1}} =\sqrt{\mathrm{3}} \\ $$$${a}_{\mathrm{2}} =−\mathrm{2}+\sqrt{\mathrm{3}} \\…

example-x-t-C-s-2-s-2-4s-6-e-st-ds-Res-s-2-2-i-s-2-s-2-2-i-e-st-Res-s-2-2-i-s-2-s-2-2-i-e-st-because-Res-s-z-j-f-s-e-st-x-t-2-i-2-

Question Number 220664 by SdC355 last updated on 17/May/25 $$\:\mathrm{example}.. \\ $$$${x}\left({t}\right)=\oint_{\:{C}} \:\:\frac{{s}−\mathrm{2}}{{s}^{\mathrm{2}} −\mathrm{4}{s}+\mathrm{6}}\:{e}^{{st}} \:\mathrm{d}{s} \\ $$$$\mathrm{Res}_{{s}=\mathrm{2}+\sqrt{\mathrm{2}}\boldsymbol{{i}}} \left\{\frac{{s}−\mathrm{2}}{{s}−\mathrm{2}+\sqrt{\mathrm{2}}\boldsymbol{{i}}}\right\}{e}^{{st}} +\mathrm{Res}_{{s}=\mathrm{2}−\sqrt{\mathrm{2}}\boldsymbol{{i}}} \left\{\frac{{s}−\mathrm{2}}{{s}−\mathrm{2}−\sqrt{\mathrm{2}}\boldsymbol{{i}}}\right\}{e}^{{st}} \\ $$$$\mathrm{because}\:\Sigma\:\mathrm{Res}_{{s}={z}_{{j}} } \left\{{f}\left({s}\right)\right\}{e}^{{st}} \\…

Hmmm-can-you-guys-explain-Let-u-dx-v-dy-be-a-1-form-defined-over-R-2-By-applying-the-above-formula-to-each-terms-consider-x-1-u-x-2-v-d-u-x-i-dx-i-dx-u-x-i-dx-i-dy

Question Number 220660 by SdC355 last updated on 17/May/25 $$\mathrm{Hmmm}…… \\ $$$$\mathrm{can}\:\mathrm{you}\:\mathrm{guys}\:\mathrm{explain}?? \\ $$$$\mathrm{Let}\:\boldsymbol{\omega}={u}\:\mathrm{d}{x}+{v}\:\mathrm{d}{y}\:\mathrm{be}\:\mathrm{a}\:\mathrm{1}-\mathrm{form}\:\mathrm{defined}\:\mathrm{over}\:\mathbb{R}^{\mathrm{2}} \\ $$$$\mathrm{By}\:\mathrm{applying}\:\mathrm{the}\:\mathrm{above}\:\mathrm{formula}\:\mathrm{to}\:\mathrm{each}\:\mathrm{terms} \\ $$$$\mathrm{consider}\:{x}^{\mathrm{1}} ={u}\:,\:{x}^{\mathrm{2}} ={v} \\ $$$$\mathrm{d}\boldsymbol{\omega}=\left(\Sigma\:\frac{\partial{u}}{\partial{x}^{{i}} }\:\mathrm{d}{x}^{{i}} \wedge\mathrm{d}{x}\right)+\left(\Sigma\:\frac{\partial{u}}{\partial{x}^{{i}} }\:\mathrm{d}{x}^{{i}}…

Question-220625

Question Number 220625 by Spillover last updated on 17/May/25 Answered by mr W last updated on 17/May/25 $${for}\:{the}\:{remaining}\:\mathrm{4}\:{doors}\:{he}\:{needs} \\ $$$${additional}\:{paint}\:{which}\:{can}\:{only}\:{be}\: \\ $$$${blue},\:{green}\:{or}\:{yellow}. \\ $$$$\left.\mathrm{1}\right)\:{color}\:{for}\:{addtional}\:{paint}\:{is}\:{blue} \\…