Question Number 220353 by Tawa11 last updated on 11/May/25 Commented by fantastic last updated on 11/May/25 Commented by fantastic last updated on 11/May/25 $${Here}\:\bigtriangleup{DEC}\:{is}\:{a}\:{eqilateral}\:{triangle} \\…
Question Number 220321 by SdC355 last updated on 11/May/25 Commented by MathematicalUser2357 last updated on 11/May/25 한국인이세요? 대답하실거면 제 댓글 위에 있는 점 세 개를 누르고 Plain Text Comment 이라는 버튼을 눌러서 대답해 주세요 Commented by SdC355 last updated on 11/May/25 네 한국인이요 ㅋㅋㅋ방가요…
Question Number 220323 by SdC355 last updated on 11/May/25 $$\mathrm{Q1}.\:\boldsymbol{\Omega};=\left\{\left({x},{y}\right);{x}^{\mathrm{2}} +{y}^{\mathrm{2}} \leq\mathrm{1}\right\} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\:\oint_{\:\partial\boldsymbol{\Omega}} \:{x}\centerdot\mathrm{d}{y}−{y}\centerdot\mathrm{d}{y}=?? \\ $$$$\mathrm{Q2}.\:\boldsymbol{\mathcal{S}};\:\mathbb{R}^{\mathrm{2}} \rightarrow\mathbb{R}^{\mathrm{3}} \\ $$$$\boldsymbol{\mathcal{S}}\left({u},{v}\right)={r}\mathrm{sin}\left({u}\right)\mathrm{cos}\left({v}\right)\overset{\rightarrow} {\boldsymbol{\mathrm{e}}}_{\mathrm{1}} +{r}\mathrm{sin}\left({u}\right)\mathrm{sin}\left({v}\right)\overset{\rightarrow} {\boldsymbol{\mathrm{e}}}_{\mathrm{2}} +{r}\mathrm{cos}\left({u}\right)\overset{\rightarrow} {\boldsymbol{\mathrm{e}}}_{\mathrm{3}}…
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Question Number 220286 by Tawa11 last updated on 10/May/25 Commented by Tawa11 last updated on 10/May/25 $$\mathrm{perimeter}\:\mathrm{of}\:\mathrm{semi}\:\mathrm{circle}\:\mathrm{interms}\:\mathrm{of}\:\pi \\ $$ Commented by fantastic last updated on…
Question Number 220248 by Spillover last updated on 10/May/25 Answered by Spillover last updated on 12/May/25 Answered by Spillover last updated on 12/May/25 Answered by…
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Question Number 220250 by Spillover last updated on 10/May/25 Answered by mr W last updated on 10/May/25 $${as}\:{proved}\:{in}\:{Q}\mathrm{220231}: \\ $$$${R}={a}+{b} \\ $$$${S}=\frac{\pi}{\mathrm{2}}\left({R}^{\mathrm{2}} −{a}^{\mathrm{2}} −{b}^{\mathrm{2}} \right)=\pi{ab}…
Question Number 220244 by Spillover last updated on 10/May/25 Answered by Spillover last updated on 12/May/25 Answered by Spillover last updated on 12/May/25 Answered by…
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