Question Number 225788 by ajfour last updated on 11/Nov/25 $$\int_{\:\sqrt{\mathrm{2}}−\mathrm{1}} ^{\:{y}} \sqrt{\left(\mathrm{2}\sqrt{\mathrm{2}}\right){y}−\mathrm{1}}{dy} \\ $$ Commented by ajfour last updated on 11/Nov/25 https://youtu.be/2E_r3bZjp9c?si=0LUX6BjrjMJShm6Z Commented by mr…
Question Number 225786 by mr W last updated on 11/Nov/25 Answered by mr W last updated on 12/Nov/25 Commented by mr W last updated on…
Question Number 225776 by fantastic last updated on 10/Nov/25 Commented by mr W last updated on 10/Nov/25 $${a}_{{x}} \left(\rightarrow\right)={a}_{{y}} \left(\downarrow\right)=\frac{{g}}{\mathrm{2}+{k}+\frac{{M}}{{m}}} \\ $$ Commented by fantastic…
Question Number 225756 by ajfour last updated on 09/Nov/25 Commented by mr W last updated on 11/Nov/25 $${applying}\:{descartes}\:{theorem}\:{twice}: \\ $$$$\frac{\mathrm{1}}{\:\sqrt{{r}}}=\frac{\mathrm{1}}{\:\sqrt{{R}}}+\frac{\mathrm{1}}{\:\sqrt{{R}}}=\frac{\mathrm{2}}{\:\sqrt{{R}}}\:\Rightarrow{r}=\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$\frac{\mathrm{1}}{\:\sqrt{{a}}}=\frac{\mathrm{1}}{\:\sqrt{{r}}}+\frac{\mathrm{1}}{\:\sqrt{{R}}}=\frac{\mathrm{3}}{\:\sqrt{{R}}} \\ $$$$\Rightarrow{a}=\frac{{R}}{\mathrm{9}} \\…
Question Number 225758 by mr W last updated on 09/Nov/25 Commented by mr W last updated on 09/Nov/25 Answered by ajfour last updated on 09/Nov/25…
Question Number 225768 by Lara2440 last updated on 09/Nov/25 $$\mathrm{WeinGarten}\:\mathrm{Equation} \\ $$$$\:\boldsymbol{\mathrm{r}}_{{u}} \centerdot\boldsymbol{\mathrm{r}}_{{u}} ={E}\:,\:\boldsymbol{\mathrm{r}}_{{u}} \centerdot\boldsymbol{\mathrm{r}}_{{v}} ={F}\:,\:\boldsymbol{\mathrm{r}}_{{v}} \centerdot\boldsymbol{\mathrm{r}}_{{v}} ={G} \\ $$$$\hat {\boldsymbol{\mathrm{N}}}\centerdot\hat {\boldsymbol{\mathrm{N}}}=\mathrm{1} \\ $$$$\frac{\partial\left(\hat {\boldsymbol{\mathrm{N}}}\centerdot\hat…
Question Number 225767 by mr W last updated on 09/Nov/25 Commented by fantastic last updated on 09/Nov/25 $${i}\:{got}\:\frac{{m}}{{M}}=\frac{\mathrm{sin}\:\alpha}{\left(\mathrm{1}−\mathrm{sin}\:\alpha\right)^{\mathrm{2}} } \\ $$ Commented by fantastic last…
Question Number 225740 by fantastic last updated on 08/Nov/25 Answered by fantastic last updated on 08/Nov/25 $$\gamma=\mathrm{sin}^{−\mathrm{1}} \left(\frac{{r}}{\mathrm{1}−{r}}\right) \\ $$$$\alpha=\mathrm{cos}^{−\mathrm{1}} \left(\frac{\mathrm{1}−\mathrm{3}{r}}{\mathrm{1}−{r}}\right) \\ $$$$\beta=\mathrm{sin}^{−\mathrm{1}} \left(\frac{\mathrm{1}−\mathrm{2}{r}}{\mathrm{1}}\right) \\…
Question Number 225726 by mr W last updated on 08/Nov/25 Commented by mr W last updated on 08/Nov/25 Answered by mr W last updated on…
Question Number 225730 by Lara2440 last updated on 08/Nov/25 Terms of Service Privacy Policy Contact: info@tinkutara.com