Question Number 219935 by fantastic last updated on 03/May/25 Answered by MrGaster last updated on 04/May/25 Commented by MrGaster last updated on 04/May/25 $$\left(\mathrm{2}\right):\mathrm{Let}\:{b}_{{j}} =\sqrt{{a}_{{j}}…
Question Number 219871 by SdC355 last updated on 03/May/25 $${F}\left({s}\right)=\int_{\mathrm{0}} ^{\:\infty} \:\frac{\mathrm{sin}\left({t}\right)}{{t}^{\mathrm{2}} +\alpha^{\mathrm{2}} }{e}^{−{st}} \:\mathrm{d}{t} \\ $$$$\mathrm{F}\left(\mathrm{3}\right)=?? \\ $$ Answered by MrGaster last updated on…
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Question Number 219921 by Spillover last updated on 03/May/25 Answered by mr W last updated on 04/May/25 Commented by mr W last updated on 04/May/25…
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Question Number 219918 by Spillover last updated on 03/May/25 Commented by Spillover last updated on 04/May/25 Commented by Spillover last updated on 04/May/25 Answered by…
Question Number 219919 by Spillover last updated on 03/May/25 Answered by Spillover last updated on 04/May/25 Answered by Spillover last updated on 04/May/25 Answered by…
Question Number 219911 by Nicholas666 last updated on 03/May/25 $$ \\ $$$$\:\:\:\:\int_{\:\mathrm{0}} ^{\:\infty} \left(\underset{{n}\geqslant\mathrm{1}} {\sum}\:\frac{{sin}\left(\mathrm{2}\pi{nx}\right)}{{n}}\right)\frac{{dx}}{{x}^{{s}+\mathrm{1}} } \\ $$$$ \\ $$ Commented by MrGaster last updated…
Question Number 219839 by Lekhraj last updated on 02/May/25 Answered by golsendro last updated on 03/May/25 $$\:\mathrm{sin}\:\mathrm{2}\theta\:=\:\mathrm{2}\left(\frac{\sqrt{\mathrm{4}−\sqrt{\mathrm{5}}}\:+\sqrt{\sqrt{\mathrm{5}}−\mathrm{2}}}{\mathrm{2}}\:\right)\left(\frac{\sqrt{\mathrm{4}−\sqrt{\mathrm{5}}}−\sqrt{\sqrt{\mathrm{5}}−\mathrm{2}}}{\mathrm{2}}\:\right) \\ $$$$\:=\:\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{4}−\sqrt{\mathrm{5}}\:−\sqrt{\mathrm{5}}\:+\mathrm{2}\:\right) \\ $$$$\:=\:\mathrm{3}−\sqrt{\mathrm{5}}\: \\ $$ Terms of…
Question Number 219832 by mnjuly1970 last updated on 02/May/25 $$ \\ $$$$\:\:\:\:\:{lim}_{{n}\rightarrow\infty} \:{n}\left(\frac{\mathrm{1}}{\mathrm{1}+{n}}\:+\frac{\mathrm{1}}{\mathrm{2}+{n}}\:+…+\frac{\mathrm{1}}{\mathrm{2}{n}}\:−{ln}\left(\mathrm{2}\right)\right)=? \\ $$$$ \\ $$ Answered by universe last updated on 03/May/25 Commented…