Question Number 219520 by OmoloyeMichael last updated on 27/Apr/25 $$\boldsymbol{{find}}\:\boldsymbol{{the}}\:\boldsymbol{{laplace}}\:\boldsymbol{{transform}}\:\boldsymbol{{of}} \\ $$$$\boldsymbol{{f}}\left(\boldsymbol{{t}}\right)=\int_{\mathrm{0}} ^{\boldsymbol{{t}}} \frac{\boldsymbol{{sint}}}{\boldsymbol{{t}}}\boldsymbol{{dt}} \\ $$ Answered by SdC355 last updated on 27/Apr/25 $$\int_{\mathrm{0}} ^{\:{T}}…
Question Number 219521 by OmoloyeMichael last updated on 27/Apr/25 Commented by OmoloyeMichael last updated on 27/Apr/25 $$\boldsymbol{{help}}\:\boldsymbol{{me}}\:\boldsymbol{{with}}\:\boldsymbol{{question}}\:\mathrm{4} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 219522 by Nicholas666 last updated on 27/Apr/25 $$ \\ $$$$\:\:\:\underset{\:\mathrm{0}} {\int}^{\:\infty} \:\frac{\mathrm{10}{x}^{\mathrm{17}} {e}^{\mathrm{2}{x}} \left({e}^{\mathrm{2}{x}} −\mathrm{1}\right)+{x}^{\mathrm{17}} {e}^{{x}} \left({e}^{\mathrm{4}{x}} −\mathrm{1}\right)}{\left({e}^{{x}} −\mathrm{1}\right)^{\mathrm{6}} }\:{dx}\:\:\: \\ $$$$ \\…
Question Number 219486 by OmoloyeMichael last updated on 26/Apr/25 Commented by OmoloyeMichael last updated on 26/Apr/25 $$\boldsymbol{{please}}\:\boldsymbol{{help}}\:\boldsymbol{{me}}\:\boldsymbol{{with}}\:\boldsymbol{{question}}\:\mathrm{4} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 219481 by SdC355 last updated on 26/Apr/25 $$\mathrm{pls}\:\mathrm{Help}…. \\ $$$$\mathrm{1}.\:−\frac{\mathrm{1}}{\boldsymbol{{i}}\pi}\:\int_{\:−\infty+\boldsymbol{{i}\zeta}_{\mathrm{0}} } ^{\:\infty+\boldsymbol{{i}\zeta}_{\mathrm{0}} } \:\frac{{e}^{{st}} \left(\mathrm{ln}\left({t}\right)+\boldsymbol{\gamma}\right)}{{t}}\:\mathrm{d}{t}\: \\ $$$$\mathrm{2}.\:\int_{\mathrm{0}} ^{\:\infty} \:\:{t}\centerdot{J}_{\nu} \left({t}\right){J}_{\nu} \left({rt}\right)\:\mathrm{d}{t} \\ $$$$\mathrm{3}.\:\int_{\mathrm{0}}…
Question Number 219482 by Nicholas666 last updated on 26/Apr/25 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\int\:\:\frac{{e}^{−{x}^{\mathrm{2}} } \mathrm{cos}\:\left({x}\right)}{{x}^{\mathrm{2}} +\mathrm{1}}\:{dx} \\ $$$$ \\ $$ Commented by Nicholas666 last updated on…
Question Number 219476 by universe last updated on 26/Apr/25 $$\:\mathrm{let}\:\mathrm{a}_{\mathrm{1}} \:=\:\mathrm{1}\:;\:\left(\mathrm{n}+\mathrm{1}\right)\mathrm{a}_{\mathrm{n}+\mathrm{1}} +\mathrm{na}_{\mathrm{n}} \:=\:\mathrm{2n}−\mathrm{3}\: \\ $$$$\:\:\mathrm{find}\:\:\mathrm{nth}\:\mathrm{term}\:\mathrm{of}\:\mathrm{a}_{\mathrm{n}\:} \\ $$ Commented by universe last updated on 26/Apr/25 $${yes}\:{sir}\:…
Question Number 219465 by SdC355 last updated on 26/Apr/25 $${prove} \\ $$$$\int_{\mathrm{0}} ^{\:\infty} \:\:\sqrt{{r}^{\mathrm{2}} −{t}^{\mathrm{2}} }{e}^{−{pt}} \mathrm{d}{t}=\frac{−{r}\pi\boldsymbol{\mathrm{L}}_{\mathrm{1}} \left({rp}\right)+\pi{rI}_{\mathrm{1}} \left({up}\right)+\mathrm{2}\boldsymbol{{i}}{rK}_{\mathrm{1}} \left({rp}\right)}{\mathrm{2}{p}} \\ $$$$\boldsymbol{\mathrm{L}}_{\nu} \left({x}\right)\:\mathrm{is}\:\mathrm{Modified}\:\mathrm{Struve}\:\mathrm{function} \\ $$$${I}_{\nu}…
Question Number 219492 by hardmath last updated on 26/Apr/25 $$\mathrm{a}\:+\:\mathrm{b}\:=\:\mathrm{1} \\ $$$$\mathrm{a}^{\mathrm{2}} \:+\:\mathrm{b}^{\mathrm{2}} \:=\:\mathrm{2} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{a}^{\mathrm{11}} \:+\:\mathrm{b}^{\mathrm{11}} \:=\:? \\ $$ Answered by mr W last…
Question Number 219488 by OmoloyeMichael last updated on 26/Apr/25 $$\boldsymbol{{solve}}\:\boldsymbol{{the}}\:\boldsymbol{{initial}}\:\boldsymbol{{value}}\:\boldsymbol{{problem}}\: \\ $$$$\boldsymbol{{y}}'−\mathrm{2}\boldsymbol{{e}}^{−\boldsymbol{{t}}^{\mathrm{2}} } +\mathrm{2}\boldsymbol{{ty}}=\mathrm{0}\:\:\boldsymbol{{y}}\left(\mathrm{0}\right)=\mathrm{1} \\ $$ Answered by SdC355 last updated on 26/Apr/25 $$\frac{\mathrm{d}{y}}{\mathrm{d}{t}}+\mathrm{2}{ty}\left({t}\right)=\mathrm{2}{e}^{−{t}^{\mathrm{2}} }…