Question Number 219110 by universe last updated on 19/Apr/25 $${find}\:{the}\:{nth}\:{term}\:{of}\:{x}_{{n}+\mathrm{1}} \:=\:{x}_{{n}} \left(\mathrm{2}−{x}_{{n}} \right) \\ $$$${in}\:{x}_{\mathrm{1}} \\ $$ Answered by vnm last updated on 22/Apr/25 $${x}_{{n}+\mathrm{1}}…
Question Number 219098 by zetamaths last updated on 20/Apr/25 $$\zeta\left(\alpha\right)=\underset{{n}=\mathrm{1}} {\overset{+\infty} {\sum}}\frac{\mathrm{1}}{{n}^{\alpha} }\:\: \\ $$ Answered by Frix last updated on 20/Apr/25 $$\mathrm{This}\:\mathrm{is}\:\mathrm{just}\:\mathrm{the}\:\mathrm{definition}\:\mathrm{of}\:\mathrm{the}\:\zeta−\mathrm{Function}, \\ $$$$\mathrm{there}'\mathrm{s}\:\mathrm{nothing}\:\mathrm{to}\:\mathrm{solve}.…
Question Number 219093 by hardmath last updated on 19/Apr/25 Commented by hardmath last updated on 19/Apr/25 $$\mathrm{ABC}\:=\:\bigtriangleup \\ $$$$\mathrm{B}\:-\:\mathrm{acute}\:\mathrm{angle} \\ $$$$\angle\mathrm{B}\:=\:\mathrm{2}\:\centerdot\:\angle\mathrm{C} \\ $$$$\mathrm{AB}\:=\:\mathrm{10} \\ $$$$\mathrm{BC}\:=\:\mathrm{22}…
Question Number 219088 by Spillover last updated on 19/Apr/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 219090 by depressiveshrek last updated on 19/Apr/25 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{the}\:\mathrm{sequence}\:{a}_{{n}} =\frac{\mathrm{1}}{\:\sqrt[{{n}}]{{n}!}}\:\mathrm{is}\:\mathrm{decreasing}. \\ $$ Answered by Frix last updated on 19/Apr/25 $${n}\rightarrow\infty\:\Rightarrow\:{n}!\approx\left(\frac{{n}}{\mathrm{e}}\right)^{{n}} \sqrt{\mathrm{2}\pi{n}}\:\Rightarrow \\ $$$$\frac{\mathrm{1}}{\:\sqrt[{{n}}]{{n}!}}\approx\frac{\mathrm{e}}{\left(\mathrm{2}\pi{x}\right)^{\frac{\mathrm{1}}{\mathrm{2}{x}}} {x}}…
Question Number 219084 by Spillover last updated on 19/Apr/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 219085 by Spillover last updated on 19/Apr/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 219086 by Spillover last updated on 19/Apr/25 Answered by Spillover last updated on 19/Apr/25 v= [axbxsin60°]l V=[2x5xsin 60°]×10 cm^3 Answered by mr W…
Question Number 219087 by fantastic last updated on 19/Apr/25 Answered by mahdipoor last updated on 19/Apr/25 $${DE}=\mathrm{2}{r}−{AD}−{EB}=\mathrm{2}{r}−\left({d}\right)−\left({r}−{d}\right)={r} \\ $$$$\frac{\pi}{\mathrm{2}}\left(\left(\mathrm{2}{r}\right)^{\mathrm{2}} −\left({r}\right)^{\mathrm{2}} \right)=\mathrm{1}.\mathrm{5}\pi{r}^{\mathrm{2}} \\ $$ Commented by…
Question Number 219083 by Spillover last updated on 19/Apr/25 Terms of Service Privacy Policy Contact: info@tinkutara.com