Question Number 218418 by Nicholas666 last updated on 09/Apr/25 Answered by MrGaster last updated on 10/Apr/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 218410 by Spillover last updated on 09/Apr/25 Answered by Nicholas666 last updated on 09/Apr/25 $$\:{given};{AB},{CD}\:{tangents}\:{to}\:{circle}\:{O}: \\ $$$${M}\:{midpoint}\:{of}\:{BC};\:{AD}\mid\mid{BC};\:{BD}={x},{AB}={y},{CD}={z} \\ $$$${prove}\:{x}^{\mathrm{2}} ={y}.{z} \\ $$$${solution} \\…
Question Number 218411 by Spillover last updated on 09/Apr/25 Answered by mr W last updated on 09/Apr/25 Commented by mr W last updated on 09/Apr/25…
Question Number 218400 by SdC355 last updated on 09/Apr/25 $$\mathrm{Hard}\:\mathrm{problem}….. \\ $$$$\:\mathrm{prove}. \\ $$$$\:\mathrm{for}\:\mathrm{all}\:\alpha\in\mathbb{Z} \\ $$$$\alpha^{\mathrm{37}} \equiv\alpha\:\mathrm{Mod}\left(\mathrm{1729}\right) \\ $$$$\mathrm{pls}\:\mathrm{help}\::\left(\right. \\ $$ Answered by Nicholas666 last…
Question Number 218364 by hardmath last updated on 08/Apr/25 $$\mathrm{Let}\:\:\:\boldsymbol{\lambda}>\mathrm{0}\:\:\:\mathrm{fixed} \\ $$$$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}\:\mathrm{the}\:\mathrm{system}:\:\:\:\begin{cases}{\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{yz}\:=\:\lambda^{\mathrm{2}} }\\{\mathrm{y}^{\mathrm{2}} \:−\:\mathrm{zx}\:=\:\mathrm{7}\lambda^{\mathrm{2}} }\\{\mathrm{z}^{\mathrm{2}} \:−\:\mathrm{xy}\:=\:−\mathrm{5}\lambda^{\mathrm{2}} }\end{cases} \\ $$ Answered by vnm last updated…
Question Number 218365 by hardmath last updated on 08/Apr/25 $$\mathrm{Find}:\:\:\:\boldsymbol{\Omega}\:=\underset{\boldsymbol{\mathrm{n}}\rightarrow\infty} {\mathrm{lim}}\:\underset{\boldsymbol{\mathrm{k}}=\mathrm{1}} {\overset{\boldsymbol{\mathrm{n}}} {\sum}}\:\left[\:\underset{\boldsymbol{\mathrm{i}}=\mathrm{1}} {\overset{\boldsymbol{\mathrm{k}}} {\sum}}\:\mathrm{i}\:\left(\mathrm{k}\:−\:\mathrm{i}\:+\:\frac{\mathrm{1}}{\mathrm{3}}\right)\right]^{−\mathrm{1}} =\:? \\ $$ Answered by vnm last updated on 08/Apr/25…
Question Number 218366 by Mingma last updated on 08/Apr/25 Commented by Mingma last updated on 08/Apr/25 Find the dimensions Commented by zetamaths last updated on 08/Apr/25 $${the}\:{dimension}\:{is}\:\mathrm{2}\:\:\Leftrightarrow{dim}\left({W}\right)=\mathrm{2}\:{because}…
Question Number 218388 by Nicholas666 last updated on 08/Apr/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 218356 by Spillover last updated on 08/Apr/25 Answered by Nicholas666 last updated on 09/Apr/25 $$\mathrm{8} \\ $$ Answered by Spillover last updated on…
Question Number 218357 by Spillover last updated on 08/Apr/25 Answered by Spillover last updated on 16/Apr/25 Answered by Spillover last updated on 17/Apr/25 Answered by…