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Question Number 218384 by Spillover last updated on 08/Apr/25 Answered by Nicholas666 last updated on 09/Apr/25 $${percentage}\:{of}\:{red}\:{area}: \\ $$$$\frac{\mathrm{15}\pi\sqrt{\mathrm{3}}}{\mathrm{32}.\mathrm{3}}.\mathrm{100\%}=\frac{\mathrm{5}\pi\sqrt{\mathrm{3}}}{\mathrm{32}}=\mathrm{100\%} \\ $$$$=\frac{\mathrm{5}.\pi.\mathrm{1},\mathrm{732}}{\mathrm{32}}.\mathrm{100\%}=\frac{\mathrm{27},\mathrm{206}}{\mathrm{32}}.\mathrm{100\%}=\mathrm{85},\mathrm{02\%} \\ $$$$ \\ $$…
Question Number 218385 by Spillover last updated on 08/Apr/25 Answered by Nicholas666 last updated on 09/Apr/25 $${ratio}=\frac{\mathrm{3}.\mathrm{2}}{\mathrm{2}.\mathrm{5}}=\mathrm{6}/\mathrm{10}=\mathrm{3}/\mathrm{5}=\mathrm{0}.\mathrm{6} \\ $$ Answered by Spillover last updated on…
Question Number 218383 by Nicholas666 last updated on 08/Apr/25 Commented by Nicholas666 last updated on 08/Apr/25 $${please}\:{check}\:{where}\:{My}\:{mistakes},{friend} \\ $$ Commented by vnm last updated on…
Question Number 218376 by Nicholas666 last updated on 08/Apr/25 $$ \\ $$$$\:\:\int_{\mathrm{0}} ^{\infty} \frac{\boldsymbol{{J}}_{\boldsymbol{\alpha}} \left(\boldsymbol{{ar}}\right)}{\left(\boldsymbol{{r}}^{\mathrm{2}} +\boldsymbol{{k}}^{\mathrm{2}} \right)\boldsymbol{\mu}}\boldsymbol{{dr}}\: \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 218374 by Nicholas666 last updated on 08/Apr/25 $$\: \\ $$$$\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\infty} \boldsymbol{{J}}_{\alpha} \left(\sqrt{\boldsymbol{{ar}}}\right)\boldsymbol{{e}}^{−\boldsymbol{{r}}} \boldsymbol{{dr}}\: \\ $$$$\: \\ $$ Terms of Service Privacy Policy…
Question Number 218375 by Nicholas666 last updated on 08/Apr/25 $$ \\ $$$$\:\:\int\frac{\sqrt{\boldsymbol{{tan}}\:\boldsymbol{{x}}}}{\boldsymbol{{sin}}^{\mathrm{3}} \boldsymbol{{x}}\:\boldsymbol{{cos}}\:\boldsymbol{{x}}}\boldsymbol{{dx}} \\ $$$$ \\ $$ Answered by Ghisom last updated on 08/Apr/25 $$\int\frac{\sqrt{\mathrm{tan}\:{x}}}{\mathrm{sin}^{\mathrm{3}}…
Question Number 218349 by Hanuda354 last updated on 07/Apr/25 Answered by vnm last updated on 07/Apr/25 $$ \\ $$$$\varphi\left(\theta\right)=\theta−\mathrm{sin}^{−\mathrm{1}} \frac{\mathrm{sin}\:\theta}{\mathrm{5}} \\ $$$${s}\left(\alpha\right)=\frac{\mathrm{5}}{\mathrm{2}}\left(\mathrm{5}\alpha−\mathrm{sin}\alpha\right) \\ $$$${S}={s}\left(\varphi\left(\frac{\pi}{\mathrm{3}}\right)\right)−{s}\left(\varphi\left(\frac{\pi}{\mathrm{2}}\right)\right)+\frac{\mathrm{19}\pi}{\mathrm{2}}= \\…
Question Number 218344 by Spillover last updated on 07/Apr/25 Commented by mr W last updated on 07/Apr/25 $$\mathrm{12}\leqslant{d}\leqslant\mathrm{10}+\mathrm{4}\sqrt{\mathrm{6}} \\ $$ Terms of Service Privacy Policy…
Question Number 218345 by Spillover last updated on 07/Apr/25 Answered by som(math1967) last updated on 07/Apr/25 $${let}\:{AF}={AE}={x} \\ $$$$\:\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{3}×\left(\mathrm{6}+{x}\right)+\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{3}×\left(\mathrm{8}+{x}\right)+\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{3}×\mathrm{14}=\mathrm{63} \\ $$$$\Rightarrow\frac{\mathrm{3}}{\mathrm{2}}×\left(\mathrm{28}+\mathrm{2}{x}\right)=\mathrm{63} \\ $$$$\mathrm{28}+\mathrm{2}{x}=\mathrm{42} \\ $$$$\:\therefore{x}=\mathrm{7}…