Question Number 217783 by malwan last updated on 21/Mar/25 $$ \\ $$ Commented by malwan last updated on 21/Mar/25 $$ \\ $$ Commented by malwan…
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Question Number 217802 by Ismoiljon_008 last updated on 21/Mar/25 Commented by Ismoiljon_008 last updated on 21/Mar/25 $$\:\:\:{a}+{b}\:=\:{c}\:\:\:{Then}\:\:{R}\:=\:? \\ $$$$\:\:\:{Help}\:{me},\:{please}\: \\ $$$$ \\ $$ Commented by…
Question Number 217797 by Tawa11 last updated on 21/Mar/25 $$\mathrm{Solve}: \\ $$$$\:\:\:\:\:\mathrm{5x}^{\mathrm{2}} \:\mathrm{y}''\:\:+\:\:\:\mathrm{x}\left(\mathrm{1}\:\:+\:\:\mathrm{x}\right)\:\mathrm{y}'\:\:−\:\:\mathrm{y}\:\:\:=\:\:\:\mathrm{0} \\ $$ Answered by AntonCWX8 last updated on 22/Mar/25 $${I}.{F},\:\mu\left({x}\right)=\frac{\mathrm{1}}{\mathrm{5}{x}^{\mathrm{2}} }{e}^{\int\frac{{x}\left(\mathrm{1}+{x}\right)}{\mathrm{5}{x}^{\mathrm{2}} }{dx}}…
Question Number 217794 by yamane last updated on 21/Mar/25 $${I}\:{need}\:{help} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} {x}^{{n}} {e}−\frac{{x}^{\mathrm{2}} }{\mathrm{2}}\:{dx}\:\:\left({n}\in\mathbb{N}\right) \\ $$ Answered by Wuji last updated on 21/Mar/25…
Question Number 217795 by yamane last updated on 21/Mar/25 Commented by mr W last updated on 21/Mar/25 $${can}\:{you}\:{read}\:{your}\:{own}\:{question}? \\ $$ Terms of Service Privacy Policy…
Question Number 217772 by yamane last updated on 20/Mar/25 $${Where}\:{is}\:{the}\:{error} \\ $$$$\left(−\mathrm{1}\right)=\left(−\mathrm{1}\right)^{\mathrm{1}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:=\left(−\mathrm{1}\right)^{\frac{\mathrm{2}}{\mathrm{2}}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:=\left[\left(−\mathrm{1}\right)^{\mathrm{2}} \right]^{\frac{\mathrm{1}}{\mathrm{2}}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:=\left[\mathrm{1}\right]^{\frac{\mathrm{1}}{\mathrm{2}}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\sqrt{\mathrm{1}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{1} \\ $$…
Question Number 217769 by nECxx2 last updated on 20/Mar/25 $${Given}\:{a}\:{consumer}\:{with}\:{the}\:{utility} \\ $$$${function}\:{U}\:=\:{X}_{\mathrm{1}} ^{\frac{\mathrm{1}}{\mathrm{4}}} +\:{X}_{\mathrm{2}} \:{who}\:{faces} \\ $$$${a}\:{budget}\:{constraint}\:{of}\:{B}={P}_{\mathrm{1}} {X}_{\mathrm{1}} {P}_{\mathrm{2}} {X}_{\mathrm{2}} \\ $$$${Show}\:{that}\:{the}\:{expemditure}\:{function} \\ $$$${facing}\:{the}\:{consumer}\:{is} \\…
Question Number 217755 by Tawa11 last updated on 20/Mar/25 $$\int\:\frac{\mathrm{cos}\left(\mathrm{sin}^{−\:\mathrm{1}} \mathrm{x}\right)\:+\:\mathrm{cos}^{−\:\mathrm{1}} \left(\mathrm{sin}\:\mathrm{x}\right)}{\mathrm{ln}\left(\mathrm{ln}\left(\mathrm{ln}\left(\mathrm{1}\:+\:\sqrt{\mathrm{x}\:+\:\sqrt{\mathrm{x}}}\right)\right.\right.}\:\mathrm{dx} \\ $$ Commented by mr W last updated on 20/Mar/25 $${you}\:{can}\:{even}\:{make}\:{it}\:{more}\:{nice} \\ $$$${looking}…
Question Number 217764 by ArshadS last updated on 20/Mar/25 $$ \\ $$$$\mathrm{Let}\:\mathrm{a},\:\mathrm{b},\:\mathrm{c}\:\mathrm{be}\:\mathrm{distinct}\:\mathrm{real}\:\mathrm{numbers}\:\mathrm{such}\:\mathrm{that} \\ $$$$\frac{{a}}{{b}−{c}}+\frac{{b}}{{c}−{a}}+\frac{{c}}{{a}−{b}}=\mathrm{0} \\ $$$$\mathrm{then}\:\mathrm{prove}\:\mathrm{that} \\ $$$$\frac{{a}}{\left({b}−{c}\right)^{\mathrm{2}} }+\frac{{b}}{\left({c}−{a}\right)^{\mathrm{2}} }+\frac{{c}}{\left({a}−{b}\right)^{\mathrm{2}} }=\mathrm{0} \\ $$ Answered by…