Question Number 216958 by abdi last updated on 25/Feb/25 Answered by A5T last updated on 25/Feb/25 Commented by A5T last updated on 26/Feb/25 $$\left.\mathrm{2}\right) \\…
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Question Number 216953 by mustaphapelumi last updated on 25/Feb/25 Commented by Ghisom last updated on 26/Feb/25 $$\mathrm{or}\:\mathrm{use}\:\mathrm{l}'\mathrm{H}\hat {\mathrm{o}pital} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{sin}\:{x}}{{x}}\:=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\frac{{d}\left[\mathrm{sin}\:{x}\right]}{{dx}}}{\frac{{d}\left[{x}\right]}{{dx}}}\:=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{cos}\:{x}}{\mathrm{1}}\:=\mathrm{1} \\ $$…
Question Number 216974 by issac last updated on 25/Feb/25 $$\mathrm{Q216887} \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\mathrm{n}} {\prod}}\:\mathrm{cos}\left(\mathrm{2}^{−{n}} {x}\right)=\frac{\mathrm{si}\cancel{\mathrm{n}}{x}}{\cancel{{n}}}={six}=\mathrm{6} \\ $$$${p}_{{n}} \left({x}\right)=\mathrm{6} \\ $$$${Q}.{E}.{D} \\ $$ Terms of Service…
Question Number 216969 by issac last updated on 25/Feb/25 $$\mathrm{6}\frac{\mathrm{1}}{\mathrm{4}}\%=\mathrm{6}×\frac{\mathrm{1}}{\mathrm{4}}×\frac{\mathrm{0}}{\mathrm{0}}=\frac{\mathrm{3}}{\mathrm{2}} \\ $$ Commented by issac last updated on 25/Feb/25 $$\mathrm{Q216913} \\ $$ Terms of Service…
Question Number 216971 by issac last updated on 25/Feb/25 $$ \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{sinx}}{\mathrm{x}}=\frac{\mathrm{sin}\cancel{\mathrm{x}}}{\cancel{\mathrm{x}}}=\mathrm{sin} \\ $$$$\mathrm{Q}.\mathrm{E}.\mathrm{D} \\ $$ Answered by issac last updated on 25/Feb/25 $$\mathrm{Q216953}…
Question Number 216934 by MathematicalUser2357 last updated on 25/Feb/25 $${see}\:\underline{{q}#\mathrm{216900}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 216925 by Engr_Jidda last updated on 24/Feb/25 Answered by mehdee7396 last updated on 24/Feb/25 $${s}=\int_{\mathrm{0}} ^{\mathrm{1}} \left(\mathrm{4}{u}+\mathrm{1}\right){du}+\int_{\mathrm{0}} ^{\mathrm{2}} \left(\mathrm{4}{u}+\mathrm{1}\right){du}+…+\int_{\mathrm{0}} ^{\mathrm{10}} \left(\mathrm{4}{u}+\mathrm{1}\right){du} \\ $$$$\left.=\left.\left(\left.\mathrm{2}{u}^{\mathrm{2}}…
Question Number 216926 by Engr_Jidda last updated on 24/Feb/25 $${Evaluate}\:\mathrm{5}^{\mathrm{2}} \underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\mathrm{2}}\left(\underset{{m}=\mathrm{2}} {\overset{\infty} {\sum}}\frac{\mathrm{2}}{{m}^{\mathrm{2}} +\mathrm{2}{m}}\right)^{{n}−\mathrm{1}} \\ $$ Answered by Wuji last updated on 25/Feb/25…