Question Number 216263 by AROUNAMoussa last updated on 01/Feb/25 Commented by AROUNAMoussa last updated on 02/Feb/25 $${Veillez}\:{m}'{aider}:\: \\ $$$${mesDAE}=?\:\:{et}\:\:{mesDFB}=? \\ $$ Terms of Service Privacy…
Question Number 216242 by ajfour last updated on 01/Feb/25 $$\left({x}−{a}\right)^{\mathrm{2}} +\left({x}^{\mathrm{2}} −{a}\right)^{\mathrm{2}} ={a}^{\mathrm{2}} \\ $$$${Find}\:{x},\:{given}\:{a}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 216230 by MATHEMATICSAM last updated on 31/Jan/25 Answered by mahdipoor last updated on 31/Jan/25 $$\frac{{sec}^{\mathrm{2}} −{tan}}{{sec}^{\mathrm{2}} +{tan}}×\frac{{cos}^{\mathrm{2}} }{{cos}^{\mathrm{2}} }=\frac{\mathrm{1}−{sin}.{cos}}{\mathrm{1}+{sin}.{cos}}=\frac{\mathrm{2}−{sin}\left(\mathrm{2}{x}\right)}{\mathrm{2}+{sin}\left(\mathrm{2}{x}\right)} \\ $$$$=\frac{{A}}{{B}}\:\:\:\:\:\mathrm{1}<{A},{B}<\mathrm{3}\:\Rightarrow\:\:{min}\:,\:{max}=\frac{\mathrm{1}}{\mathrm{3}}\:,\:\frac{\mathrm{3}}{\mathrm{1}} \\ $$…
Question Number 216226 by klipto last updated on 31/Jan/25 $$\mathrm{please}\:\mathrm{check}\:\mathrm{the}\:\mathrm{qurstion}\:\mathrm{out}\:\mathrm{guys} \\ $$ Commented by klipto last updated on 31/Jan/25 Terms of Service Privacy Policy Contact:…
Question Number 216207 by MATHEMATICSAM last updated on 30/Jan/25 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{any}\:\mathrm{kind}\:\mathrm{of}\:\mathrm{equation}\:\mathrm{should} \\ $$$$\mathrm{have}\:\mathrm{atleast}\:\mathrm{one}\:\mathrm{root}.\:\left(\mathrm{Algebric}\:\right. \\ $$$$\left.\mathrm{fundamental}\:\mathrm{theorem}\right) \\ $$ Commented by Ghisom last updated on 30/Jan/25 $$\mathrm{not}\:{any}\:{kind}\:{of}\:{equation}.\:\mathrm{for}\:\mathrm{example} \\…
Question Number 216219 by mr W last updated on 30/Jan/25 Commented by mr W last updated on 31/Jan/25 $${a}\:{ladder}\:{with}\:{length}\:{L}\:{and}\:{mass}\:{m} \\ $$$${is}\:{released}\:{from}\:{rest}\:{at}\:{the}\:{position} \\ $$$${as}\:{shown}.\:{find}\:{the}\:{time}\:{the}\:{ladder} \\ $$$${takes}\:{to}\:{fall}\:{onto}\:{the}\:{floor}\:{completely}.…
Question Number 216188 by BaliramKumar last updated on 29/Jan/25 Answered by som(math1967) last updated on 29/Jan/25 $$\:{AC}:{BC}=\mathrm{5}:\mathrm{12} \\ $$$${if}\:{AC}=\mathrm{5}{cm}\:{BC}=\mathrm{12}{cm} \\ $$$${then}\:{AC}+{BC}=\mathrm{17}={AB} \\ $$$${not}\:{possible} \\ $$$${AC}=\mathrm{10}{cm}…
Question Number 216201 by BaliramKumar last updated on 29/Jan/25 Answered by dionigi last updated on 30/Jan/25 $${the}\:{largest}\:{possible}\:{area}\:{is}\: \\ $$$${that}\:{of}\:{an}\:{equilateral}\:{triangle} \\ $$$${with}\:{side}\:\mathrm{60}/\mathrm{3}\:=\:\mathrm{20}\:{cm} \\ $$$${A}\:\leqslant\:\frac{\mathrm{1}}{\mathrm{2}}\:×\:\mathrm{20}\:×\:\mathrm{20}\:×\:\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:=\:\mathrm{173}.\mathrm{205}…<\mathrm{174} \\ $$…
Question Number 216202 by mahdipoor last updated on 29/Jan/25 $${prove}\::\: \\ $$$${sin}\left({a}+{b}\right)={sin}\left({a}\right){cos}\left({b}\right)+{sin}\left({b}\right){cos}\left({a}\right) \\ $$ Answered by dionigi last updated on 30/Jan/25 $${e}^{{i}\:\left({a}+{b}\right)\:} =\:\mathrm{cos}\left({a}+{b}\right)\:+\:{i}\:\mathrm{sin}\left({a}+{b}\right) \\ $$$${e}^{{i}\:\left({a}+{b}\right)\:}…
Question Number 216180 by mr W last updated on 29/Jan/25 Answered by AntonCWX last updated on 29/Jan/25 Commented by AntonCWX last updated on 29/Jan/25 $${FG}^{\mathrm{2}}…