Question Number 214220 by Ari last updated on 01/Dec/24 Answered by mr W last updated on 01/Dec/24 $${say}\:{a}>{b} \\ $$$${a}^{\mathrm{2}} +{b}^{\mathrm{2}} ={c}^{\mathrm{2}} \:\:\:…\left({i}\right) \\ $$$${a}−{b}=\mathrm{6}\:\:\:…\left({ii}\right)…
Question Number 214205 by MathematicalUser2357 last updated on 01/Dec/24 $${f}\left({x}+\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}\right)={x}−\sqrt{{x}^{\mathrm{2}} +\mathrm{1}} \\ $$$${f}\left(\mathrm{2}\right)+{f}\left(\mathrm{3}\right)+{f}\left(\mathrm{6}\right)=? \\ $$ Answered by golsendro last updated on 01/Dec/24 $$\:\:\:\:\underline{\underbrace{\:}} \underline{…
Question Number 214191 by golsendro last updated on 01/Dec/24 $$\:\:\:\:\:\:\begin{cases}{\mathrm{y}^{\mathrm{3}} =\:\mathrm{x}^{\mathrm{x}+\mathrm{y}} }\\{\mathrm{y}^{\mathrm{x}+\mathrm{y}} \:=\:\mathrm{x}^{\mathrm{6}} \mathrm{y}^{\mathrm{3}} }\end{cases} \\ $$$$\:\:\:\:\cancel{\underline{ }} \\ $$ Answered by TonyCWX08 last updated…
Question Number 214216 by MathematicalUser2357 last updated on 01/Dec/24 $${a}_{{n}} ={a}_{{n}−\mathrm{1}} +\frac{{x}−{a}_{{n}−\mathrm{1}} }{{t}} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}{a}_{{n}} =? \\ $$ Answered by mr W last updated…
Question Number 214199 by mr W last updated on 01/Dec/24 Commented by mr W last updated on 01/Dec/24 $$\left[{see}\:{Q}\mathrm{214176}\right] \\ $$$${find}\:{the}\:{radius}\:{of}\:{the}\:{maximal} \\ $$$${circle}\:{inscribed}\:{between}\:{the}\:{curves} \\ $$$${f}\left({x}\right)\:{and}\:{g}\left({x}\right)\:{as}\:{shown}.…
Question Number 214186 by hardmath last updated on 30/Nov/24 $$\mathrm{If}\:\:\:\mathrm{x}\:+\:\frac{\mathrm{1}}{\mathrm{x}}\:=\:\mathrm{1}\:\:\:\mathrm{find}\:\:\:\mathrm{x}^{\mathrm{61}} \:+\:\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{61}} }+\:\mathrm{4}\:\:=\:? \\ $$ Answered by Rasheed.Sindhi last updated on 30/Nov/24 $${x}+\frac{\mathrm{1}}{{x}}=\mathrm{1};\:{x}^{\mathrm{61}} +\frac{\mathrm{1}}{{x}^{\mathrm{61}} }+\mathrm{4}=? \\…
Question Number 214181 by golsendro last updated on 30/Nov/24 $$\:\:\:\:\underbrace{\:} \\ $$ Answered by efronzo1 last updated on 30/Nov/24 $$\:\:\:\cancel{\nprec} \\ $$ Terms of Service…
Question Number 214183 by jlewis last updated on 30/Nov/24 $$\left.\mathrm{a}\right)\:\mathrm{The}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{elevation}\:\mathrm{from}\:\mathrm{a}\:\mathrm{point}\:\mathrm{A}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{top}\:\mathrm{of}\:\mathrm{building}\:\mathrm{5m}\:\mathrm{away}\:\mathrm{is}\:\mathrm{45}°.\:\mathrm{Another}\:\mathrm{point} \\ $$$$\mathrm{B}\:\mathrm{is}\:\mathrm{4m}\:\mathrm{from}\:\mathrm{A}.\:\mathrm{By}\:\mathrm{scale}\:\mathrm{drawing}\:\mathrm{determine}. \\ $$$$\left.\mathrm{i}\right)\:\mathrm{the}\:\mathrm{angles}\:\mathrm{of}\:\mathrm{elevation}\:\mathrm{from}\:\mathrm{point}\:\mathrm{B} \\ $$$$\left.\mathrm{ii}\right)\mathrm{the}\:\mathrm{height}\:\mathrm{of}\:\mathrm{the}\:\mathrm{building} \\ $$$$\left.\mathrm{b}\right)\:\mathrm{A}\:\mathrm{man}\:\mathrm{who}\:\mathrm{is}\:\mathrm{in}\:\mathrm{the}\:\mathrm{elevator}\:\mathrm{half}\:\mathrm{way}\:\mathrm{the} \\ $$$$\mathrm{building}\:\mathrm{notices}\:\mathrm{a}\:\mathrm{lorry}\:\mathrm{approaching}\:\mathrm{the} \\ $$$$\mathrm{building}\:\mathrm{at}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{depression}\:\mathrm{20}°.\:\mathrm{How} \\…
Question Number 214176 by a.lgnaoui last updated on 30/Nov/24 $$\mathrm{find}\:\mathrm{the}\:\mathrm{vslue}\:\mathrm{of}\:\boldsymbol{\mathrm{R}}\left(\mathrm{radius}\:\boldsymbol{\mathrm{o}}\mathrm{f}\:\mathrm{circle}\:\mathrm{betwen}\:\mathrm{two}\:\right. \\ $$$$\:\mathrm{diagrame}\:\mathrm{curves}\:\boldsymbol{\mathrm{f}}\left(\boldsymbol{\mathrm{x}}\right)\mathrm{and}\:\boldsymbol{\mathrm{g}}\left(\boldsymbol{\mathrm{x}}\right)\:\mathrm{as}\:\mathrm{showen}. \\ $$$$\mathrm{you}\:\mathrm{can}\:\mathrm{use}\:\mathrm{the}\:\mathrm{programer}\:\mathrm{calculator}. \\ $$ Commented by a.lgnaoui last updated on 30/Nov/24 Commented by…
Question Number 214178 by ajfour last updated on 30/Nov/24 Commented by ajfour last updated on 01/Dec/24 $${Q}.\:\mathrm{214132}\:\:{But}\:{with}\:{left}\:{roller}\:{fixed}. \\ $$ Answered by ajfour last updated on…