Question Number 213201 by ajfour last updated on 01/Nov/24 Commented by ajfour last updated on 01/Nov/24 $${Find}\:{R} \\ $$ Answered by A5T last updated on…
Question Number 213234 by ajfour last updated on 01/Nov/24 Commented by Ghisom last updated on 01/Nov/24 $$\mathrm{let}\:{r}=\mathrm{1} \\ $$$${P}\in\mathrm{circle}:\:{P}=\begin{pmatrix}{\mathrm{cos}\:\theta}\\{\mathrm{1}+\mathrm{sin}\:\theta}\end{pmatrix} \\ $$$$\mathrm{parabola}:\:{y}=\left(\frac{\mathrm{2}+\mathrm{sin}\:\theta}{\mathrm{cos}\:\theta}−\frac{{x}}{\mathrm{cos}^{\mathrm{2}} \:\theta}\right){x} \\ $$$$\mathrm{tan}\:\alpha=\frac{\mathrm{2}+\mathrm{sin}\:\theta}{\mathrm{cos}\:\theta} \\…
Question Number 213203 by golsendro last updated on 01/Nov/24 $$\:\:\:\:\:\:\cancel{\underline{\underbrace{\mathscr{G}}}} \\ $$ Answered by lepuissantcedricjunior last updated on 01/Nov/24 $$\boldsymbol{{f}}\left(\boldsymbol{{xy}}\right)=\boldsymbol{{f}}\left(\boldsymbol{{x}}\right)+\boldsymbol{{f}}\left(\boldsymbol{{y}}\right) \\ $$$$\boldsymbol{{f}}\left(\mathrm{10}\right)=\mathrm{14};\boldsymbol{{f}}\left(\mathrm{20}\right)=\mathrm{40} \\ $$$$\boldsymbol{{calculons}}\:\boldsymbol{{f}}\left(\mathrm{500}\right) \\…
Question Number 213198 by Ismoiljon_008 last updated on 01/Nov/24 Answered by mr W last updated on 01/Nov/24 Commented by mr W last updated on 01/Nov/24…
Question Number 213221 by mr W last updated on 01/Nov/24 Commented by mr W last updated on 01/Nov/24 $${Q}\mathrm{212936} \\ $$ Commented by ajfour last…
Question Number 213216 by Spillover last updated on 01/Nov/24 Answered by MrGaster last updated on 01/Nov/24 $$=\int_{\mathrm{0}} ^{\infty} \frac{{x}^{\mathrm{3}} }{\left({x}+\mathrm{1}\right)^{\mathrm{2}} \left({x}^{\mathrm{2}} +\mathrm{1}\right)\left({x}^{\mathrm{3}} +\mathrm{1}\right)}{dx}+\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{log}^{\mathrm{2}}…
Question Number 213217 by Spillover last updated on 01/Nov/24 Answered by MrGaster last updated on 01/Nov/24 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\begin{pmatrix}{\mathrm{2}{n}}\\{{n}}\end{pmatrix}+{n}}{\mathrm{4}^{{n}} \left(\mathrm{2}{n}+\mathrm{1}\right)^{\mathrm{2}} }=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\begin{pmatrix}{\mathrm{2}{n}}\\{{n}}\end{pmatrix}}{\mathrm{4}^{{n}} \left(\mathrm{2}{n}+\mathrm{1}\right)^{\mathrm{2}} }+\underset{{n}=\mathrm{1}}…
Question Number 213250 by ajfour last updated on 01/Nov/24 Answered by a.lgnaoui last updated on 02/Nov/24 $$\mathrm{Calcul}\:\mathrm{de}\:\mathrm{l}\:\mathrm{aire} \\ $$$$ \\ $$$$\mathrm{BC}=\mathrm{a}\sqrt{\mathrm{2}}\:\:\:\:\:\:\:\mathrm{DM}=\mathrm{a}\sqrt{\mathrm{2}}\:+\frac{\mathrm{a}}{\mathrm{2}}. \\ $$$$\boldsymbol{\mathrm{S}}\left(\boldsymbol{\mathrm{ABDMC}}\right)=\mathrm{S}\left(\boldsymbol{\mathrm{ABC}}\right)+\mathrm{2}\boldsymbol{\mathrm{S}}\left(\boldsymbol{\mathrm{BDE}}\right)+\boldsymbol{\mathrm{S}}\left(\boldsymbol{\mathrm{BCEF}}\right) \\ $$$$…
Question Number 213173 by ajfour last updated on 31/Oct/24 Commented by ajfour last updated on 31/Oct/24 $${Find}\:{r} \\ $$ Answered by ajfour last updated on…
Question Number 213175 by Davidtim last updated on 31/Oct/24 $${we}\:{can}\:{find}\:{tan}\mathrm{120}\:{by}\:{tan}\left(\mathrm{180}−\mathrm{60}\right) \\ $$$${but}\:{can}\:{not}\:{find}\:{by}\:{tan}\left(\mathrm{90}+\mathrm{30}\right)\:{why}? \\ $$ Answered by efronzo1 last updated on 31/Oct/24 $$\:\mathrm{tan}\:\mathrm{120}°=\:\mathrm{tan}\:\left(\mathrm{90}°+\mathrm{30}°\right)\:=−\:\mathrm{cot}\:\mathrm{30}°=−\sqrt{\mathrm{3}} \\ $$ Answered…