Question Number 212604 by klipto last updated on 18/Oct/24 $$\boldsymbol{\mathrm{draw}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{structural}}\:\boldsymbol{\mathrm{formula}}\:\boldsymbol{\mathrm{for}} \\ $$$$ \\ $$Spiro [2.2.2.5.8.6] compounds Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 212600 by MrGaster last updated on 18/Oct/24 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{certificate}: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{n}}{\mathrm{1}+{n}^{\mathrm{2}} {x}^{\mathrm{2}} }{e}^{{x}^{\mathrm{3}} } {dx}=\frac{\pi}{\mathrm{2}}. \\ $$ Answered by…
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Question Number 212598 by MATHEMATICSAM last updated on 18/Oct/24 $$\mathrm{Help}\:\mathrm{me}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{pls} \\ $$$$\mathrm{Q}\:\mathrm{212576}\: \\ $$ Answered by A5T last updated on 18/Oct/24 $${Lemma}:\:\frac{{a}}{{b}}=\frac{{c}}{{d}}\Rightarrow\frac{{a}}{{b}}=\frac{{c}}{{d}}=\frac{{a}\underset{−} {+}{c}}{{b}\underset{−} {+}{d}} \\…
Question Number 212593 by mr W last updated on 18/Oct/24 Commented by mr W last updated on 18/Oct/24 $${a}\:{more}\:{general}\:{case}\:{from}\:{Q}\mathrm{212514} \\ $$ Answered by mr W…
Question Number 212595 by MrGaster last updated on 18/Oct/24 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{1}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{1}}+\frac{\mathrm{2}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{2}}+\frac{\mathrm{3}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{3}}+\ldots+\frac{{n}^{\mathrm{2}} }{{n}^{\mathrm{2}} +{n}}−\frac{{n}}{\mathrm{3}}\right)=? \\ $$ Answered by Berbere last…
Question Number 212584 by MrGaster last updated on 18/Oct/24 Commented by mr W last updated on 18/Oct/24 $${it}\:{seems}\:{that}\:{you}\:{are}\:{using}\:{machine} \\ $$$${translation}\:{for}\:{your}\:{posts}.\:{can}\:{you} \\ $$$${please}\:{recheck}\:{the}\:{translation} \\ $$$${and}\:{fix}\:{the}\:{mistakes}\:{in}\:{them}\:{before} \\…
Question Number 212612 by hardmath last updated on 18/Oct/24 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{differential}\:\mathrm{equation}: \\ $$$$\frac{\mathrm{dy}}{\mathrm{dx}}\:\:=\:\:\mathrm{cos}\left(\mathrm{x}\:+\:\mathrm{y}\right) \\ $$ Answered by mr W last updated on 19/Oct/24 $${let}\:{t}={x}+{y} \\ $$$$\frac{{dt}}{{dx}}=\mathrm{1}+\frac{{dy}}{{dx}}…