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Question Number 212609 by hardmath last updated on 18/Oct/24 $$\mathrm{If}\:\:\:\mathrm{0}\leqslant\mathrm{x}\leqslant\mathrm{2} \\ $$$$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\mathrm{2}^{\boldsymbol{\mathrm{x}}} \:+\:\mathrm{1}\:−\:\sqrt{\mathrm{10},\mathrm{5x}\:+\:\mathrm{4}}\:\leqslant\:\mathrm{0} \\ $$ Answered by Frix last updated on 18/Oct/24 $${f}\left({x}\right)=\mathrm{2}^{{x}}…
Question Number 212573 by hardmath last updated on 17/Oct/24 $$\mathrm{Prove}\:\mathrm{that}:\:\:\:\frac{\mathrm{5m}^{\mathrm{2}} \:−\:\mathrm{n}}{\mathrm{n}^{\mathrm{2}} \:+\:\mathrm{3m}}\:=\:\mathrm{1} \\ $$ Commented by Frix last updated on 18/Oct/24 $$\mathrm{Prove}\:\mathrm{what}\:\mathrm{exactly}? \\ $$ Commented…
Question Number 212569 by a.lgnaoui last updated on 17/Oct/24 $$\mathrm{Axis}\:\mathrm{of}\:\mathrm{C},\mathrm{P},\mathrm{N}\:\mathrm{then}\:\mathrm{concluat}\:\mathrm{for} \\ $$$$\mathrm{Area}\left[\:\mathrm{OPN}\right]\:;\:\mathrm{ON}:\mathrm{tangente}\:\mathrm{au}\:\mathrm{cercle} \\ $$ Commented by a.lgnaoui last updated on 17/Oct/24 Terms of Service Privacy…
Question Number 212560 by ajfour last updated on 17/Oct/24 $${Exact}\:{solution}\:{just}\:{to}\:{this}\:{please}: \\ $$$$\mathrm{9}{x}^{\mathrm{2}} \left({x}+\mathrm{1}\right)^{\mathrm{3}} =\mathrm{3}\left(\mathrm{3}{x}^{\mathrm{2}} −\mathrm{1}\right)\left(\mathrm{3}{x}^{\mathrm{2}} +\mathrm{3}{x}+\mathrm{1}\right) \\ $$ Commented by Frix last updated on 18/Oct/24…
Question Number 212556 by MrGaster last updated on 17/Oct/24 $$\mathrm{Q}:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{most}\:\mathrm{disgusting}\:\mathrm{mathm} \\ $$$$\mathrm{proble}\:\mathrm{you}\:\mathrm{have}\:\mathrm{ever}\:\mathrm{done}.? \\ $$ Commented by MATHEMATICSAM last updated on 17/Oct/24 $$\mathrm{1}+\mathrm{1}=? \\ $$ Answered…
Question Number 212557 by tri26112004 last updated on 17/Oct/24 Answered by Ghisom last updated on 17/Oct/24 $$\mathrm{cos}\:{x}\:={c} \\ $$$$\mathrm{sin}\:{x}\:=\sqrt{\mathrm{1}−{c}^{\mathrm{2}} } \\ $$$$\left(\sqrt{\mathrm{1}−{c}^{\mathrm{2}} }\right)^{\mathrm{8}} +{c}^{\mathrm{8}} =…
Question Number 212552 by mnjuly1970 last updated on 17/Oct/24 $$ \\ $$$$\:\overset{\mathrm{Q}:} {\:}\:\mathrm{In}\:\mathrm{A}\overset{\Delta} {\mathrm{B}C}\::\:\:\:{cos}\left(\mathrm{A}\right)\:+{cos}\left(\mathrm{B}\:\right)+\:\mathrm{2}{cos}\left(\mathrm{C}\:\right)=\:\mathrm{2} \\ $$$$\:\:\: \\ $$$$\:\:\:\:\:\:\mathrm{show}\:\mathrm{that}\::\:\:\:{a}\:+\:{b}\:=\:\mathrm{2}{c}\:\:\:\:\:\:\:\:\:\:\:\blacksquare\: \\ $$$$ \\ $$ Answered by Ghisom…
Question Number 212553 by MrGaster last updated on 17/Oct/24 $$ \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{\sqrt[{{n}}]{\mathrm{2}}−\mathrm{1}}{\:\sqrt[{{n}}]{\mathrm{2}{n}+\mathrm{1}}}\mid\int_{\mathrm{1}} ^{\frac{\mathrm{1}}{\mathrm{2}{n}}} {e}^{−{y}^{\mathrm{2}} } {dy}+\ldots+\int^{\frac{\mathrm{2}{n}+\mathrm{1}}{\mathrm{2}{n}}} {e}^{−{y}^{\mathrm{2}} } {dy}\mid=? \\ $$$$ \\ $$ Terms…