Question Number 224502 by fantastic last updated on 15/Sep/25 $${in}\:{a}\:{rhombus}\:{the}\:{perimeter} \\ $$$${is}\:\mathrm{2}{p}\:{and}\:{the}\:{sum}\:{of}\:{its}\:{diagonals} \\ $$$${is}\:{m}. \\ $$$${the}\:{area}\:{of}\:{rhombus}\:{is}… \\ $$ Answered by som(math1967) last updated on 15/Sep/25…
Question Number 224515 by Vibhor last updated on 15/Sep/25 $$\frac{\mathrm{sin}\:\mathrm{35}}{\mathrm{tan}\:\mathrm{56}} \\ $$ Answered by fantastic last updated on 15/Sep/25 $$\frac{\mathrm{sin}\:\mathrm{35}^{\mathrm{0}} }{\mathrm{tan}\:\mathrm{56}^{\mathrm{0}} }=\mathrm{sin}\:\mathrm{35}^{\mathrm{0}} \mathrm{cot}\:\mathrm{56}^{\mathrm{0}} \\ $$…
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Question Number 224476 by Mingma last updated on 14/Sep/25 Answered by mr W last updated on 14/Sep/25 $$\left.\mathrm{9}\right) \\ $$$${when}\:{the}\:{coin}\:{is}\:{tossed}\:\mathrm{6}\:{times},\:{you} \\ $$$${might}\:{get} \\ $$$$\mathrm{6}\:{heads}\:{or} \\…
Question Number 224489 by ajfour last updated on 14/Sep/25 Commented by ajfour last updated on 14/Sep/25 $${Find}\:\theta.\:{string}\:{length}\:{is}\:{s}.\: \\ $$$${No}\:{friction}\:{at}\:{G}. \\ $$$$\left({sorry}\:{for}\:{my}\:{absence}\right) \\ $$$${Take}\:{edge}\:{lengths}\:{of}\:{cubes}=\mathrm{2}{a}. \\ $$…
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Question Number 224453 by Rojarani last updated on 13/Sep/25 Commented by fantastic last updated on 13/Sep/25 $$−\mathrm{144}? \\ $$ Commented by Rojarani last updated on…
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Question Number 224455 by AgniMath last updated on 13/Sep/25 $${If}\:{a},{b},{c}\:\neq\:\mathrm{0}\:{what}\:{is}\:{the}\:{difference} \\ $$$${between}\:{the}\:{maximum}\:{snd}\:{minimum}\: \\ $$$${value}\:{of} \\ $$$${S}\:=\:\mathrm{1}\:+\:\frac{\mid{a}\mid}{{a}}\:+\:\frac{\mathrm{2}\mid{b}\mid}{{b}}\:+\:\frac{\mathrm{3}\mid{ab}\mid}{{ab}}\:−\:\frac{\mathrm{4}\mid{c}\mid}{{c}}\:? \\ $$ Answered by mr W last updated on…
Question Number 224466 by Jubr last updated on 13/Sep/25 Commented by fantastic last updated on 14/Sep/25 $${the}\:{acceleration}\: \\ $$$${a}=\frac{\mathrm{4}{m}_{\mathrm{1}} {m}_{\mathrm{2}} +{m}_{\mathrm{0}} \left({m}_{\mathrm{1}} −{m}_{\mathrm{2}} \right)}{\mathrm{4}{m}_{\mathrm{1}} {m}_{\mathrm{2}}…