Question Number 211849 by Spillover last updated on 22/Sep/24 Commented by Spillover last updated on 22/Sep/24 $$ \\ $$write the stricture of the major organic…
Question Number 211817 by Spillover last updated on 22/Sep/24 Answered by Spillover last updated on 22/Sep/24 $$ \\ $$IUPAC name is Methanoic acid, while Trivial…
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Question Number 211851 by Ari last updated on 22/Sep/24 Commented by Ari last updated on 22/Sep/24 $${how}\:{many}\:\:{triangles}\:{are}\:{formed}? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 211819 by Spillover last updated on 22/Sep/24 Answered by TonyCWX08 last updated on 22/Sep/24 $${i}. \\ $$$${Benzene}\:{can}\:{be}\:{prepared}\:{from}\:{Phenol}\:{through}\:{reduction}. \\ $$$${Vapour}\:{of}\:{Phenol}\:{passes}\:{over}\:{heated}\:{Zinc}\:{Dust}. \\ $$$${Zinc}\:{Dust}\:{will}\:{reduces}\:{them}\:{into}\:{Benzene} \\ $$$$…
Question Number 211845 by Spillover last updated on 22/Sep/24 Answered by Spillover last updated on 22/Sep/24
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Question Number 211873 by Spillover last updated on 22/Sep/24 Answered by IbtisamAdnan last updated on 23/Sep/24 $$\:\:\:\boldsymbol{\mathrm{lim}}_{\boldsymbol{\mathrm{x}}\rightarrow\mathrm{4}} \frac{\left(\boldsymbol{\mathrm{cos}\alpha}\right)^{\mathrm{x}} −\left(\mathrm{sin}\alpha\right)^{\mathrm{x}} −\mathrm{cos}\:\mathrm{2}\alpha}{\mathrm{x}−\mathrm{4}} \\ $$$$\boldsymbol{\mathrm{lim}}_{\boldsymbol{\mathrm{x}}\rightarrow\mathrm{4}} \:\frac{\left(\boldsymbol{\mathrm{cos}\alpha}\right)^{\mathrm{x}} .\:\mathrm{ln}\:\mathrm{cos}\alpha\:\:−\:\left(\mathrm{sin}\:\alpha\right)^{\mathrm{x}} .\mathrm{ln}\:\mathrm{sin}\alpha}{\mathrm{1}}\left[\mathrm{L}\:\mathrm{hospital}\:\mathrm{rule}\right]…
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Question Number 211800 by MrGaster last updated on 21/Sep/24 $$ \\ $$$$\boldsymbol{{set}}\:\boldsymbol{\Omega}=\left\{\left(\boldsymbol{{x}},\boldsymbol{{y}},\boldsymbol{{z}}\right)\mid\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} +\boldsymbol{{z}}^{\mathrm{2}} \leq\mathrm{1}\right\}, \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{{certificat}}\mathrm{e}: \\ $$$$\:\:\frac{\mathrm{4}\boldsymbol{\pi}}{\mathrm{3}}\sqrt[{\mathrm{3}}]{\mathrm{2}}\leq\int\underset{\boldsymbol{\Omega}} {\int}\int\sqrt[{\mathrm{3}}]{\boldsymbol{{x}}+\mathrm{2}\boldsymbol{{y}}−\mathrm{2}\boldsymbol{{z}}+\mathrm{5}}\boldsymbol{{dv}}\leq\frac{\mathrm{8}\boldsymbol{\pi}}{\mathrm{3}} \\ $$$$ \\ $$$$ \\…