Question Number 224337 by wongb1506 last updated on 04/Sep/25 Answered by BaliramKumar last updated on 04/Sep/25 $${cos}\left({A}=\mathrm{60}°\right)\:=\:\frac{\mathrm{5}^{\mathrm{2}} +\left({x}−\mathrm{6}\right)^{\mathrm{2}} −\mathrm{7}^{\mathrm{2}} }{\mathrm{2}×\mathrm{5}×\left({x}−\mathrm{6}\right)} \\ $$$${x}=\mathrm{14}\:\checkmark\:\:\:\:\:{or}\:\:\:\:\:\:\cancel{\mathrm{3}}\: \\ $$$$ \\…
Question Number 224330 by Ghisom_ last updated on 03/Sep/25 $$\mathrm{recently}\:\mathrm{I}\:\mathrm{read}\:\mathrm{a}\:\mathrm{nice}\:\mathrm{proof}\:\mathrm{to}\:\mathrm{the}\:\mathrm{following} \\ $$$$\mathrm{problem} \\ $$$$\mathrm{I}\:\mathrm{know}\:\mathrm{everybody}\:\mathrm{can}\:\mathrm{look}\:\mathrm{it}\:\mathrm{up}\:\mathrm{but}\:\mathrm{if}\:\mathrm{you}'\mathrm{re} \\ $$$$\mathrm{interested}\:\mathrm{in}\:\mathrm{learning}\:\mathrm{something}\:\mathrm{try}\:\mathrm{it}\:\mathrm{by} \\ $$$$\mathrm{yourself}\:\mathrm{first} \\ $$$$\mathrm{don}'\mathrm{t}\:\mathrm{post}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{you}\:\mathrm{found}\:\mathrm{on}\:\mathrm{the} \\ $$$${www}\:\mathrm{but}\:\mathrm{post}\:\mathrm{your}\:\mathrm{thoughts}\:\mathrm{instead} \\ $$$$ \\…
Question Number 224331 by hardmath last updated on 03/Sep/25 $$\mathrm{a},\mathrm{b},\mathrm{c}\:>\:\mathrm{0} \\ $$$$\mathrm{prove}\:\mathrm{that} \\ $$$$\Sigma\:\mathrm{a}^{\mathrm{2}} \:\geqslant\:\Sigma\:\mathrm{ab}\:+\:\frac{\mathrm{1}}{\mathrm{8}}\:\Sigma\:\left(\mid\mathrm{a}−\mathrm{c}\mid\:+\:\mid\mathrm{b}−\mathrm{c}\mid\right)^{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 224324 by fantastic last updated on 03/Sep/25 Answered by fantastic last updated on 03/Sep/25 Commented by fantastic last updated on 05/Sep/25 $${Area}\:{EFHJ}={AGHJE}−{AGHF}−{AEF} \\…
Question Number 224325 by fantastic last updated on 03/Sep/25 Commented by fantastic last updated on 03/Sep/25 $${Thank}\:{you}\:{guys}. \\ $$$${I}\:{secured}\:\mathrm{38}\:{out}\:{of}\:\mathrm{40} \\ $$$${in}\:{mathematics}. \\ $$$${It}\:{was}\:{the}\:{highest}\:{score} \\ $$$$\left.{Again}\:{thank}\:{you}\:{all}:\right)…
Question Number 224327 by gregori last updated on 03/Sep/25 $$\:\:\:\rightleftharpoons \\ $$ Commented by AdnanSalhAli last updated on 10/Sep/25 عدد الطرق ثلاثة فقط مع عدم التجاور لأي شخصين الا مرة واحدة Answered by AdnanSalhAli last updated…
Question Number 224320 by Tawa11 last updated on 02/Sep/25 Answered by mr W last updated on 02/Sep/25 Commented by mr W last updated on 02/Sep/25…
Question Number 224316 by fantastic last updated on 01/Sep/25 Commented by mr W last updated on 02/Sep/25 $$\left({A}\right) \\ $$ Terms of Service Privacy Policy…
Question Number 224312 by behi834171 last updated on 01/Sep/25 Answered by Frix last updated on 01/Sep/25 $${x}_{\mathrm{1}} ={c}+\sqrt{{a}}+\sqrt{{b}}+\sqrt{{ab}} \\ $$$${x}_{\mathrm{2}} ={c}+\sqrt{{a}}−\sqrt{{b}}−\sqrt{{ab}} \\ $$$${x}_{\mathrm{3}} ={c}−\sqrt{{a}}+\sqrt{{b}}−\sqrt{{ab}} \\…
Question Number 224314 by Matica last updated on 01/Sep/25 $${solve}\:\sqrt[{\mathrm{3}}]{\mathrm{1}−\sqrt{{x}}}=\mathrm{2} \\ $$ Commented by Ghisom_ last updated on 01/Sep/25 $$\mathrm{no}\:\mathrm{solution}\:\in\mathbb{C} \\ $$$$\mathrm{1}−\sqrt{{x}}=\mathrm{8} \\ $$$$\sqrt{{x}}=−\mathrm{7}=\mathrm{7e}^{\mathrm{i}\pi} \\…