Question Number 209433 by essaad last updated on 10/Jul/24 Answered by A5T last updated on 10/Jul/24 $${S}_{{p}} =\frac{\mathrm{1}×\mathrm{2}×\mathrm{3}×\mathrm{4}×…×\left(\mathrm{2}{p}\right)}{\mathrm{2}×\mathrm{4}×\mathrm{6}×…×\mathrm{2}{p}}=\frac{\left(\mathrm{2}{p}\right)!}{\mathrm{2}^{{p}} \left(\mathrm{1}×\mathrm{2}×…×{p}\right)} \\ $$$$=\frac{\left(\mathrm{2}{p}\right)!}{\mathrm{2}^{{p}} {p}!}\Rightarrow{C} \\ $$ Terms…
Question Number 209434 by justenspi last updated on 10/Jul/24 $${Help} \\ $$ Commented by justenspi last updated on 10/Jul/24 Commented by Berbere last updated on…
Question Number 209460 by Shubha51343 last updated on 10/Jul/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 209456 by peter frank last updated on 10/Jul/24 Answered by Ghisom last updated on 10/Jul/24 $${c}=\mathrm{cos}\:\alpha\:\:\:\:\:{s}=\mathrm{sin}\:\alpha\:\:\:\:\:{t}=\mathrm{tan}\:\alpha\:=\frac{{s}}{{c}} \\ $$$${c}=\sqrt{\mathrm{1}−{s}^{\mathrm{2}} }=\frac{\mathrm{1}}{\:\sqrt{{t}^{\mathrm{2}} +\mathrm{1}}} \\ $$$${s}=\sqrt{\mathrm{1}−{c}^{\mathrm{2}} }=\frac{{t}}{\:\sqrt{{t}^{\mathrm{2}}…
Question Number 209458 by SonGoku last updated on 10/Jul/24 Commented by SonGoku last updated on 10/Jul/24 $$\mathrm{l}\:=\:?\: \\ $$$$\mathrm{BC}\:=\:\:\mathrm{l}\:+\:\mathrm{200m} \\ $$$$\mathrm{B}\hat {\mathrm{A}C}\:=\:\mathrm{120}° \\ $$$$\mathrm{A}\hat {\mathrm{B}C}\:=\:\mathrm{38}°\mathrm{12}'\mathrm{48}''…
Question Number 209452 by peter frank last updated on 10/Jul/24 Answered by Ghisom last updated on 10/Jul/24 $$\mathrm{12}\:\mathrm{units} \\ $$$$−\mathrm{4}\:\mathrm{units}\:\left(\mathrm{12}/\mathrm{3}\right)\:\mathrm{for}\:\mathrm{sugar}\:=\:\mathrm{8}\:\mathrm{units} \\ $$$$−\mathrm{2}\:\mathrm{units}\:\left(\mathrm{8}/\mathrm{4}\right)\:\mathrm{for}\:\mathrm{soap}\:=\:\mathrm{6}\:\mathrm{units} \\ $$$$\mathrm{6}\:\mathrm{units}\:=\:\mathrm{6000} \\…
Question Number 209453 by peter frank last updated on 10/Jul/24 Commented by peter frank last updated on 10/Jul/24 $$\mathrm{help}\:\mathrm{B} \\ $$ Answered by mr W…
Question Number 209455 by peter frank last updated on 10/Jul/24 Answered by Spillover last updated on 10/Jul/24 Commented by peter frank last updated on 11/Jul/24…
Question Number 209450 by RoseAli last updated on 10/Jul/24 Answered by Spillover last updated on 10/Jul/24 $${f}\left({x}\right)=\mathrm{3}{x}^{\mathrm{2}} \\ $$$${g}\left({x}\right)=\sqrt{{x}−\mathrm{2}} \\ $$$$\left({fog}\right)\left({x}\right)=? \\ $$$$\left({gof}\right)\left({x}\right)=? \\ $$$${fog}\left({x}\right)={f}\left[{g}\left({x}\right)\right]…
Question Number 209474 by Ismoiljon_008 last updated on 10/Jul/24 Commented by Ismoiljon_008 last updated on 10/Jul/24 $${help}\:{me}\:{please} \\ $$ Answered by Frix last updated on…