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Author: Tinku Tara

Question-155866

Question Number 155866 by cherokeesay last updated on 05/Oct/21 Answered by talminator2856791 last updated on 05/Oct/21 $$\:\mathrm{2}\sqrt{\mathrm{3}}\:+\:\mathrm{2}\sqrt{\mathrm{3}}\:−\:\frac{\mathrm{9}\pi\centerdot\mathrm{arctan}\left(\frac{\mathrm{2}\sqrt{\mathrm{3}}}{\mathrm{2}}\right)}{\mathrm{2}\pi}\:−\:\frac{\pi}{\mathrm{4}}\:−\:\frac{\mathrm{arctan}\left(\frac{\mathrm{2}}{\mathrm{2}\sqrt{\mathrm{3}}}\right)}{\mathrm{2}}\:\: \\ $$$$\:=\:\mathrm{4}\sqrt{\mathrm{3}}\:−\:\frac{\mathrm{9}}{\mathrm{2}}\:\mathrm{arctan}\left(\sqrt{\mathrm{3}}\right)−\:\frac{\pi}{\mathrm{4}}\:−\:\mathrm{arctan}\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right) \\ $$$$\:=\:\mathrm{4}\sqrt{\mathrm{3}}\:−\:\frac{\mathrm{9}\pi}{\mathrm{6}}\:−\:\frac{\pi}{\mathrm{4}}\:−\:\frac{\pi}{\mathrm{6}} \\ $$$$\:=\:\mathrm{4}\sqrt{\mathrm{3}}\:−\:\frac{\mathrm{13}\pi}{\mathrm{12}} \\ $$…

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Question Number 155857 by zainaltanjung last updated on 05/Oct/21 $$\left.\mathrm{1}\right).\:\:\mathrm{Find}\:\:\frac{\mathrm{dy}}{\mathrm{dx}}\:\:,\:\mathrm{if}\:: \\ $$$$\left.\mathrm{a}\right).\:\:\:\mathrm{y}=\left(\mathrm{8x}−\mathrm{1}\right)\left(\mathrm{x}^{\mathrm{2}} +\mathrm{4x}+\mathrm{7}\right) \\ $$$$\left.\mathrm{b}\right).\:\:\:\mathrm{y}=\left(\mathrm{3x}^{\mathrm{4}} −\mathrm{10x}+\mathrm{8}\right)\left(\mathrm{2x}^{\mathrm{2}} +\mathrm{5}\right) \\ $$$$ \\ $$$$\left.\mathrm{2}\right).\:\:\mathrm{Find}\:\mathrm{an}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{tangen}\:\mathrm{line} \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{to}\:\mathrm{the}\:\mathrm{graph}\:\mathrm{of}\:\mathrm{y}=\frac{\mathrm{5}}{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }\:\mathrm{at}\:\mathrm{each}\:\mathrm{point} \\…

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Question Number 155856 by peter frank last updated on 05/Oct/21 $$\mathrm{How}\:\mathrm{many}\:\mathrm{natural}\:\mathrm{number}\:\mathrm{from} \\ $$$$\mathrm{1}\:\mathrm{to}\:\mathrm{900}\:\mathrm{which}\:\mathrm{are}\:\mathrm{not}\:\mathrm{divisible} \\ $$$$\mathrm{2},\mathrm{3}\:\mathrm{and}\:\mathrm{5} \\ $$ Answered by TheSupreme last updated on 05/Oct/21 $$\mathrm{2},\mathrm{3}\:{and}…

A-particle-of-mass-m-is-moving-in-yz-plane-with-a-uniform-velocity-v-with-its-trajectory-running-parallel-to-ve-y-axis-and-intersecting-z-axis-at-z-a-The-change-in-its-angular-momentum-about-the-

Question Number 24786 by Tinkutara last updated on 26/Nov/17 $$\mathrm{A}\:\mathrm{particle}\:\mathrm{of}\:\mathrm{mass}\:{m}\:\mathrm{is}\:\mathrm{moving}\:\mathrm{in}\:{yz}-\mathrm{plane} \\ $$$$\mathrm{with}\:\mathrm{a}\:\mathrm{uniform}\:\mathrm{velocity}\:{v}\:\mathrm{with}\:\mathrm{its} \\ $$$$\mathrm{trajectory}\:\mathrm{running}\:\mathrm{parallel}\:\mathrm{to}\:+\mathrm{ve}\:{y}- \\ $$$$\mathrm{axis}\:\mathrm{and}\:\mathrm{intersecting}\:{z}-\mathrm{axis}\:\mathrm{at}\:{z}\:=\:{a}. \\ $$$$\mathrm{The}\:\mathrm{change}\:\mathrm{in}\:\mathrm{its}\:\mathrm{angular}\:\mathrm{momentum} \\ $$$$\mathrm{about}\:\mathrm{the}\:\mathrm{origin}\:\mathrm{as}\:\mathrm{it}\:\mathrm{bounces}\:\mathrm{elastically} \\ $$$$\mathrm{from}\:\mathrm{a}\:\mathrm{wall}\:\mathrm{at}\:{y}\:=\:\mathrm{constant}\:\mathrm{is}\:: \\ $$$$\left(\mathrm{1}\right)\:{mva}\overset{\wedge} {{e}}_{{x}}…

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Question Number 90321 by M±th+et£s last updated on 22/Apr/20 $$\int\frac{\mathrm{1}}{{x}\sqrt[{\mathrm{3}}]{\mathrm{1}+{x}^{\mathrm{5}} }}{dx} \\ $$$$ \\ $$$$\int\frac{\mathrm{1}}{{sin}^{\mathrm{2}} \left({x}\right)+\mathrm{5}{sin}\left({x}\right)+\mathrm{6}}{dx} \\ $$$$ \\ $$$$\int\frac{\mathrm{2}{z}−\mathrm{5}}{\mathrm{4}{z}^{\mathrm{2}} +\mathrm{4}{z}+\mathrm{5}}{dz} \\ $$$$ \\ $$$$\int{sec}^{\mathrm{5}}…