Question Number 24294 by ajfour last updated on 15/Nov/17 $${Find}\:{value}\left({s}\right)\:{of}\:\boldsymbol{{x}}\:{if} \\ $$$$\:\:\mathrm{sin}\:\left[\mathrm{2cos}^{−\mathrm{1}} \left\{\mathrm{cot}\:\left(\mathrm{2tan}^{−\mathrm{1}} {x}\right)\right\}\right]=\mathrm{0}\:. \\ $$ Answered by mrW1 last updated on 15/Nov/17 $$\:\mathrm{sin}\:\left[\mathrm{2cos}^{−\mathrm{1}} \left\{\mathrm{cot}\:\left(\mathrm{2tan}^{−\mathrm{1}}…
Question Number 24293 by Tinkutara last updated on 15/Nov/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{centre}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{a}\:\mathrm{uniform} \\ $$$$\left({a}\right)\:\mathrm{half}-\mathrm{disc},\:\left({b}\right)\:\mathrm{quarter}-\mathrm{disc}. \\ $$ Commented by ajfour last updated on 15/Nov/17 Commented by ajfour last…
Question Number 89829 by student work last updated on 19/Apr/20 Commented by MJS last updated on 19/Apr/20 English please / Français s'il vous plaît Commented by student work last updated on…
Question Number 155361 by Fikret last updated on 29/Sep/21 $${x}−\mathrm{4}{z}+\mathrm{8}{y}=\mathrm{7} \\ $$$$\mathrm{8}×+\mathrm{7}{z}−{y}=\mathrm{4} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} −{z}^{\mathrm{2}} =? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 89826 by I want to learn more last updated on 19/Apr/20 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}: \\ $$$$\:\:\:\:\:\:\mathrm{x}^{\mathrm{2}} \:\:+\:\:\mathrm{xy}\:\:+\:\:\mathrm{y}^{\mathrm{2}} \:\:\:=\:\:\:\mathrm{7}\:\:\:\:\:\:\:\:\:……\:\left(\mathrm{i}\right) \\ $$$$\:\:\:\:\:\:\mathrm{y}^{\mathrm{2}} \:\:+\:\:\mathrm{yz}\:\:+\:\:\mathrm{z}^{\mathrm{2}} \:\:\:=\:\:\:\mathrm{3}\:\:\:\:\:\:\:\:\:\:……\:\left(\mathrm{ii}\right) \\ $$$$\:\:\:\:\:\:\mathrm{z}^{\mathrm{2}} \:\:+\:\:\mathrm{xz}\:\:+\:\:\mathrm{x}^{\mathrm{2}}…
Question Number 155360 by mathlove last updated on 29/Sep/21 Answered by puissant last updated on 30/Sep/21 $$\psi\left(\frac{\mathrm{3}}{\mathrm{2}}\right)=\psi\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}\right)=\psi\left(\frac{\mathrm{1}}{\mathrm{2}}\right)+\frac{\mathrm{1}}{\frac{\mathrm{1}}{\mathrm{2}}}=\psi\left(\frac{\mathrm{1}}{\mathrm{2}}\right)+\mathrm{2} \\ $$$${or}\:\psi\left(\frac{\mathrm{1}}{\mathrm{2}}\right)=−\mathrm{2}{ln}\mathrm{2}−\gamma \\ $$$$\Rightarrow\:\psi\left(\frac{\mathrm{3}}{\mathrm{2}}\right)\:=\:−\mathrm{2}{ln}\mathrm{2}−\gamma+\mathrm{2}\:=\:\mathrm{2}+{ln}\frac{\mathrm{1}}{\mathrm{4}}−\gamma \\ $$ Terms of…
Question Number 155362 by mathdanisur last updated on 29/Sep/21 $$\mathrm{if}\:\:\mathrm{a};\mathrm{b}\geqslant\mathrm{0}\:\:\mathrm{and}\:\:\mathrm{a}^{\mathrm{4}} \:+\:\mathrm{b}^{\mathrm{4}} \:=\:\mathrm{17}\:\:\mathrm{prove}\:\mathrm{that}: \\ $$$$\mathrm{15}\left(\mathrm{a}\:+\:\mathrm{b}\right)\:\geqslant\:\mathrm{17}\:+\:\mathrm{14}\sqrt{\mathrm{2ab}} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 155357 by mathlove last updated on 29/Sep/21 Commented by mathlove last updated on 30/Sep/21 $${pleas}\:{answer} \\ $$ Answered by qaz last updated on…
Question Number 24287 by Tinkutara last updated on 15/Nov/17 $$\mathrm{In}\:\mathrm{a}\:\mathrm{fuel}\:\mathrm{cell},\:\mathrm{methanol}\:\mathrm{is}\:\mathrm{used}\:\mathrm{as}\:\mathrm{a}\:\mathrm{fuel} \\ $$$$\mathrm{and}\:\mathrm{O}_{\mathrm{2}} \:\mathrm{is}\:\mathrm{used}\:\mathrm{as}\:\mathrm{oxidizer}.\:\mathrm{The}\:\mathrm{standard} \\ $$$$\mathrm{enthalpy}\:\mathrm{of}\:\mathrm{combustion}\:\mathrm{of}\:\mathrm{methanol}\:\mathrm{is} \\ $$$$−\mathrm{726}\:\mathrm{kJ}\:\mathrm{mol}^{−\mathrm{1}} .\:\mathrm{The}\:\mathrm{standard}\:\mathrm{free} \\ $$$$\mathrm{energies}\:\mathrm{of}\:\mathrm{formation}\:\mathrm{of}\:\mathrm{CH}_{\mathrm{3}} \mathrm{OH}\left(\mathrm{l}\right), \\ $$$$\mathrm{CO}_{\mathrm{2}} \left(\mathrm{g}\right)\:\mathrm{and}\:\mathrm{H}_{\mathrm{2}} \mathrm{O}\left(\mathrm{l}\right)\:\mathrm{are}\:−\mathrm{166}.\mathrm{3},\:−\mathrm{394}.\mathrm{4}…
Question Number 155356 by qaz last updated on 29/Sep/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{term}\:“\:\mathrm{a}^{\mathrm{m}} \mathrm{b}^{\mathrm{2m}} \:''\:\mathrm{in}\:\left(\mathrm{1}+\mathrm{a}\right)^{\mathrm{m}} \left(\mathrm{1}+\mathrm{b}\right)^{\mathrm{n}+\mathrm{m}} \left(\mathrm{1}+\mathrm{a}+\mathrm{b}\right)^{\mathrm{m}} . \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com