Question Number 155130 by mathdanisur last updated on 25/Sep/21 Answered by mr W last updated on 26/Sep/21 Commented by mathdanisur last updated on 26/Sep/21 $$\mathrm{Thank}\:\mathrm{you}\:\boldsymbol{\mathrm{S}}\mathrm{er},\:\mathrm{how}\:\mathrm{proved}\:\mathrm{please}…
Question Number 89593 by M±th+et£s last updated on 19/Apr/20 $${show}\:{that} \\ $$$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {ln}\left({sec}\left({x}\right)\right)\:{ln}\left({csc}\left({x}\right)\right)\:{dx}=\frac{\pi^{\mathrm{2}} \:{ln}^{\mathrm{2}} \left(\mathrm{2}\right)}{\mathrm{2}}−\frac{\pi^{\mathrm{4}} }{\mathrm{48}} \\ $$ Commented by maths mind last updated…
Question Number 24055 by NECx last updated on 12/Nov/17 $${Any}\:{Architect}\:{in}\:{the}\:{house}? \\ $$$$ \\ $$$${please}\:{i}\:{need}\:{your}\:{help} \\ $$ Commented by Joel577 last updated on 12/Nov/17 $${I}\:{didnt}\:{understand}\:{what}\:{you}\:{are}\:{asking} \\…
Question Number 24054 by Tinkutara last updated on 12/Nov/17 $$\mathrm{Compare}\:\mathrm{the}\:\mathrm{bond}\:\mathrm{strength}\:\mathrm{of}\:\mathrm{S}\:−\:\mathrm{O} \\ $$$$\mathrm{bond}\:\mathrm{in}\:\mathrm{SO}_{\mathrm{3}} ^{−\mathrm{2}} \:\mathrm{and}\:\mathrm{SO}_{\mathrm{4}} ^{−\mathrm{2}} \:\mathrm{ion}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 155126 by tabata last updated on 25/Sep/21 $$\int_{\mathrm{0}} ^{\:\infty} \:{e}^{−\:\beta\:\left(\mathrm{2}{x}+{b}\right)^{\frac{\mathrm{1}}{\boldsymbol{{a}}}} } \:{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 89586 by Asif Hypothesis last updated on 18/Apr/20 $$ \\ $$$$\mathrm{2018}^{\mathrm{2019}} −\mathrm{2019}^{\mathrm{2018}\:} \equiv?\:\left({mod}\:\mathrm{4}\right) \\ $$ Answered by Asif Hypothesis last updated on 18/Apr/20…
Question Number 155120 by mnjuly1970 last updated on 25/Sep/21 $$ \\ $$$$\:\:\:{lim}_{\:{x}\:\rightarrow\mathrm{0}} \left(\frac{\mathrm{1}}{{x}^{\:\mathrm{2}} }\:−\:{cot}^{\:\mathrm{2}} \left({x}\right)\right)=? \\ $$$$ \\ $$ Answered by john_santu last updated on…
Question Number 89584 by jagoll last updated on 18/Apr/20 $$\int\:\frac{\mathrm{sin}\:^{\mathrm{4}} \left(\mathrm{x}\right)\:\mathrm{dx}}{\mathrm{4}+\mathrm{cos}\:^{\mathrm{2}} \left(\mathrm{x}\right)} \\ $$ Commented by mathmax by abdo last updated on 18/Apr/20 $${I}\:=\int\:\:\frac{{sin}^{\mathrm{4}} {xdx}}{\mathrm{4}+{cos}^{\mathrm{2}}…
Question Number 155122 by saly last updated on 25/Sep/21 Commented by benhamimed last updated on 25/Sep/21 $$/{x}−\mathrm{3}/+\mathrm{3}−{x}\neq\mathrm{0} \\ $$$$/{x}−\mathrm{3}/=\begin{cases}{{x}−\mathrm{3}\:\:\:;{x}\geqslant\mathrm{3}}\\{\mathrm{3}−{x}\:\:\:\:;{x}\leqslant\mathrm{3}}\end{cases} \\ $$$$/{x}−\mathrm{3}/+\mathrm{3}−{x}=\begin{cases}{\mathrm{0}\:\:\:;{x}\geqslant\mathrm{3}}\\{\mathrm{6}−\mathrm{2}{x}\:\:\:;{x}\leqslant\mathrm{0}}\end{cases} \\ $$$$\left.{D}=\right]−\infty;\mathrm{3}\left[\right. \\ $$…
Question Number 89580 by jagoll last updated on 18/Apr/20 Answered by $@ty@m123 last updated on 18/Apr/20 $$\frac{{BD}}{\mathrm{sin}\:{x}}=\frac{{AD}}{\mathrm{sin}\:\left\{\mathrm{180}−\left({x}+\mathrm{84}+\mathrm{42}\right)\right\}} \\ $$$$\frac{{BD}}{\mathrm{sin}\:{x}}=\frac{{AD}}{\mathrm{sin}\:\left(\mathrm{54}−{x}\right)}\:…\left(\mathrm{1}\right) \\ $$$$\frac{{BD}}{\mathrm{sin}\:\mathrm{84}}=\frac{{BC}}{\mathrm{sin}\:\left\{\mathrm{180}−\left(\mathrm{84}+\mathrm{42}\right)\right\}} \\ $$$$\frac{{BD}}{\mathrm{sin}\:\mathrm{84}}=\frac{{AD}}{\mathrm{sin}\:\mathrm{54}}\:…\left(\mathrm{2}\right) \\ $$$${From}\:\left(\mathrm{1}\right)\:\&\left(\mathrm{2}\right),…