Question Number 155023 by ajfour last updated on 24/Sep/21 Commented by ajfour last updated on 24/Sep/21 $${The}\:{blue}\:{area}\:{is}\:{equal}\:{to}\:{the} \\ $$$${brown}\:{area}.\:{Find}\:{x}\:{in}\:{terms} \\ $$$${of}\:{c}. \\ $$ Commented by…
Question Number 155017 by SANOGO last updated on 24/Sep/21 $$\int_{\mathrm{0}} ^{\frac{\mathrm{3}}{\mathrm{2}}} {E}\left({x}^{\mathrm{2}} \right){dx};\:{avec}\:{E}\left({x}\right)\:{la}\:{partie}\:{entiere} \\ $$ Answered by puissant last updated on 24/Sep/21 $${K}=\int_{\mathrm{0}} ^{\frac{\mathrm{3}}{\mathrm{2}}} {E}\left({x}^{\mathrm{2}}…
Question Number 89482 by mr W last updated on 18/Apr/20 $${URGENT}\:! \\ $$$${to}\:{TINKUTARA}\:{developers}: \\ $$$${because}\:{i}\:{didn}'{t}\:{get}\:{notification},\:{i} \\ $$$${have}\:{updated}\:{the}\:{app}.\:{but}\:{since}\:{the} \\ $$$${update},\:{i}\:{can}'{t}\:{either}\:{edit}\:{my}\:{own} \\ $$$${posts}\:{or}\:{delete}\:{them}. \\ $$$${i}\:{am}\:{using}\:{a}\:{Huawei}\:{P}\mathrm{20},\:{Android}\:\mathrm{9}. \\ $$…
Question Number 155016 by ArielVyny last updated on 24/Sep/21 $$\int_{\mathrm{0}} ^{\infty} {tan}^{\mathrm{2}} {u}\left(\mathrm{1}−\frac{\mathrm{1}}{\left({u}+\mathrm{1}\right)^{\mathrm{2}} }\right){du} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 155013 by amin96 last updated on 24/Sep/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} {ln}\left(−{lnx}\right)\frac{{x}^{\mu−\mathrm{1}} }{\:\sqrt{−{ln}\left({x}\right)}}{dx}=? \\ $$ Answered by mnjuly1970 last updated on 24/Sep/21 $$\:\:\:−{ln}\left({x}\right)={t}^{\:\mathrm{2}} \:\Rightarrow\:{x}={e}^{\:−{t}^{\mathrm{2}} }…
Question Number 23940 by Tinkutara last updated on 10/Nov/17 $$\mathrm{When}\:\mathrm{the}\:\mathrm{gas}\:\mathrm{is}\:\mathrm{ideal}\:\mathrm{and}\:\mathrm{process}\:\mathrm{is} \\ $$$$\mathrm{isothermal},\:\mathrm{then} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{P}_{\mathrm{1}} \mathrm{V}_{\mathrm{1}} \:=\:\mathrm{P}_{\mathrm{2}} \mathrm{V}_{\mathrm{2}} \\ $$$$\left(\mathrm{2}\right)\:\Delta\mathrm{U}\:=\:\mathrm{0} \\ $$$$\left(\mathrm{3}\right)\:\Delta\mathrm{W}\:=\:\mathrm{0} \\ $$$$\left(\mathrm{4}\right)\:\Delta\mathrm{H}_{\mathrm{1}} \:=\:\Delta\mathrm{H}_{\mathrm{2}} \\…
Question Number 23939 by Mayor Tee last updated on 10/Nov/17 $${In}\:{a}\:{school}\:{of}\:\mathrm{500}\:{students},\mathrm{150}\:{played}\:{hockey} \\ $$$$\mathrm{250}\:{played}\:{football},\mathrm{120}\:{played}\:{table}\:{tennis}\:{and} \\ $$$$\mathrm{100}\:{played}\:{one}\:{of}\:{the}\:{three}\:{games}.{If}\:\mathrm{50}\: \\ $$$${played}\:{both}\:{hockey}\:{and}\:{football},{how}\:{many} \\ $$$${played}\:{table}\:{tennis}\:{only}?{pls}\:{show}\:{workings}\:{with} \\ $$$${diagram} \\ $$$$ \\ $$…
Question Number 23937 by ajfour last updated on 10/Nov/17 Commented by ajfour last updated on 10/Nov/17 $${A}\:{thin}\:{rod}\:{placed}\:{perpendicular} \\ $$$${on}\:{a}\:{rough}\:{horizontal}\:{surface} \\ $$$${and}\:{released}\:{at}\:{rest}.\:{Find}\:{angle} \\ $$$$\boldsymbol{\alpha}\:{at}\:{which}\:{its}\:{bottom}\:{end}\:{starts} \\ $$$${slipping}.\:{The}\:{coefficient}\:{of}…
Question Number 23932 by Tinkutara last updated on 10/Nov/17 $$\mathrm{A}\:\mathrm{cord}\:\mathrm{is}\:\mathrm{wound}\:\mathrm{around}\:\mathrm{the}\:\mathrm{circumference} \\ $$$$\mathrm{of}\:\mathrm{a}\:\mathrm{bicycle}\:\mathrm{wheel}\:\left(\mathrm{without}\:\mathrm{tyre}\right)\:\mathrm{of} \\ $$$$\mathrm{diameter}\:\mathrm{1}\:\mathrm{m}.\:\mathrm{A}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{2}\:\mathrm{kg}\:\mathrm{is}\:\mathrm{tied}\:\mathrm{at} \\ $$$$\mathrm{the}\:\mathrm{end}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cord}\:\mathrm{and}\:\mathrm{it}\:\mathrm{is}\:\mathrm{allowed}\:\mathrm{to} \\ $$$$\mathrm{fall}\:\mathrm{from}\:\mathrm{rest}.\:\mathrm{The}\:\mathrm{weight}\:\mathrm{falls}\:\mathrm{2}\:\mathrm{m}\:\mathrm{in}\:\mathrm{4} \\ $$$$\mathrm{s}.\:\mathrm{The}\:\mathrm{axle}\:\mathrm{of}\:\mathrm{the}\:\mathrm{wheel}\:\mathrm{is}\:\mathrm{horizontal} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{wheel}\:\mathrm{rotates}\:\mathrm{with}\:\mathrm{its}\:\mathrm{plane} \\ $$$$\mathrm{vertical}.\:\mathrm{If}\:\mathrm{g}\:=\:\mathrm{10}\:\mathrm{ms}^{−\mathrm{2}} ,\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}…
Question Number 23928 by Tinkutara last updated on 10/Nov/17 $$\mathrm{Find}\:^{{n}} {C}_{\mathrm{1}} \:−\:\frac{\mathrm{1}}{\mathrm{2}}\:^{{n}} {C}_{\mathrm{2}} \:+\:\frac{\mathrm{1}}{\mathrm{3}}\:^{{n}} {C}_{\mathrm{3}} \:−\:….\:+ \\ $$$$\left(−\mathrm{1}\right)^{{n}−\mathrm{1}} \frac{\mathrm{1}}{{n}}\:\centerdot\:^{{n}} {C}_{{n}} . \\ $$ Commented by…