Question Number 23823 by tawa tawa last updated on 06/Nov/17 $$\mathrm{The}\:\mathrm{period}\:\mathrm{of}\:\mathrm{a}\:\mathrm{simple}\:\mathrm{pendulum}\:\mathrm{A}\:\mathrm{is}\:\mathrm{6}\:\mathrm{secs}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{period}\:\mathrm{of}\:\mathrm{a}\:\mathrm{simple} \\ $$$$\mathrm{pendulum}\:\mathrm{B},\:\mathrm{if}\:\mathrm{A}\:\mathrm{makes}\:\mathrm{30}\:\mathrm{oscillation}\:\mathrm{in}\:\mathrm{the}\:\mathrm{time}\:\mathrm{it}\:\mathrm{takes}\:\mathrm{B}\:\mathrm{to}\:\mathrm{make}\:\mathrm{70} \\ $$$$\mathrm{oscillation}. \\ $$ Answered by mrW1 last updated on 07/Nov/17 $$\mathrm{30}{T}_{{A}}…
Question Number 154892 by mathdanisur last updated on 22/Sep/21 $$\mathrm{Find}: \\ $$$$\mathrm{cos}\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right)\:+\:\mathrm{cos}\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right)\:\sqrt{\mathrm{2}\:-\:\mathrm{2cos}\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right)}\:=\:? \\ $$ Commented by MJS_new last updated on 23/Sep/21 $$\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Commented…
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Question Number 154888 by physicstutes last updated on 22/Sep/21 Answered by mr W last updated on 23/Sep/21 Commented by physicstutes last updated on 23/Sep/21 $$\mathrm{brilliant}\:\mathrm{sir}\:\mathrm{thanks}…
Question Number 89351 by john santu last updated on 17/Apr/20 $${prove}\:\mathrm{tan}\:\mathrm{3}^{{o}} ×\mathrm{tan}\:\mathrm{39}^{{o}} ×\mathrm{tan}\:\mathrm{89}^{{o}} \:=\:\mathrm{tan}\:\mathrm{15}^{{o}} \\ $$ Commented by MJS last updated on 17/Apr/20 $$\mathrm{it}'\mathrm{s}\:\mathrm{wrong} \\…
Question Number 23814 by tawa tawa last updated on 06/Nov/17 Commented by tawa tawa last updated on 06/Nov/17 $$\mathrm{please}\:\mathrm{help}. \\ $$ Answered by mrW1 last…
Question Number 154880 by saly last updated on 22/Sep/21 Answered by Ar Brandon last updated on 22/Sep/21 $${I}_{\mathrm{1}} =\int\frac{\sqrt{{x}^{\mathrm{2}} +\mathrm{9}}}{{x}^{\mathrm{3}} }{dx},\:{x}=\mathrm{3sh}\vartheta \\ $$$$\:\:\:\:=\frac{\mathrm{1}}{\mathrm{3}}\int\frac{\mathrm{ch}^{\mathrm{2}} \vartheta}{\mathrm{sh}^{\mathrm{3}} \vartheta}{d}\vartheta=\frac{\mathrm{1}}{\mathrm{3}}\int\mathrm{cth}^{\mathrm{2}}…
Question Number 89344 by jagoll last updated on 17/Apr/20 $$\left(\mathrm{2}{x}−\mathrm{1}\right)^{\mathrm{2}} +\mathrm{8}\sqrt{\mathrm{2}{xy}}\:=\:\mathrm{4} \\ $$$$\mathrm{4}{y}−\sqrt{\mathrm{8}{xy}−\mathrm{1}}\:=\:\mathrm{1} \\ $$ Commented by john santu last updated on 17/Apr/20 $$\mathrm{8}{xy}−\mathrm{1}\:=\:\mathrm{16}{y}^{\mathrm{2}} −\mathrm{8}{y}+\mathrm{1}…
Question Number 154877 by SANOGO last updated on 22/Sep/21 $$\int_{\frac{\pi}{\mathrm{2}}} ^{\frac{\pi}{\mathrm{4}}} {sin}^{\mathrm{3}} \left({x}\right){cos}^{\mathrm{2}} \left({x}\right){dx} \\ $$ Commented by saly last updated on 24/Sep/21 $$\:{thank}\:{you} \\…
Question Number 154876 by Mr.D.N. last updated on 22/Sep/21 $$\:\:\boldsymbol{\mathrm{Integrate}}: \\ $$$$\:\:\:\int_{\mathrm{1}} ^{\:\mathrm{8}} \:\:\frac{\:\sqrt{\boldsymbol{\mathrm{x}}}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} }{\overset{\mathrm{3}} {\:}\sqrt{\boldsymbol{\mathrm{x}}}}\:\boldsymbol{\mathrm{dx}} \\ $$ Answered by MJS_new last updated on 22/Sep/21…