Question Number 23566 by NECx last updated on 01/Nov/17 $$\left(\frac{{a}}{{b}}\right)^{\mathrm{log}\:{c}} .\left(\frac{{b}}{{c}}\right)^{\mathrm{log}\:{a}} .\left(\frac{{c}}{{a}}\right)^{\mathrm{log}\:{b}} =\mathrm{1}. \\ $$$$ \\ $$$${make}\:\frac{{logc}}{{c}}\:{the}\:{subject}\:{of}\:{formula} \\ $$ Commented by NECx last updated on…
Question Number 23564 by NECx last updated on 01/Nov/17 $${The}\:{curved}\:{surface}\:{area}\:{of}\:{a}\:{cone} \\ $$$${is}\:\mathrm{21}{cm}^{\mathrm{2}} \:.{Calculate}\:{the}\:{curved} \\ $$$${surface}\:{area}\:{of}\:{a}\:{similar}\:{cone} \\ $$$${whose}\:{height}\:{is}\:\mathrm{4}\:{times}\:{the}\:{other}. \\ $$ Commented by NECx last updated on…
Question Number 89098 by askask last updated on 15/Apr/20 $${x}=^{\:\:{c}−\mathrm{1}} \sqrt{\frac{{ay}−{bz}}{{cdy}}} \\ $$$$ \\ $$$$\mathrm{If}\:{a}\:\mathrm{increases},\:\mathrm{what}\:\mathrm{happens}\:\mathrm{to}\:{x}? \\ $$$$\mathrm{Explain}\:\mathrm{your}\:\mathrm{answer}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 89099 by naka3546 last updated on 15/Apr/20 Commented by naka3546 last updated on 15/Apr/20 $${If}\:\:{AB}\:=\:{AF}\:=\:{AC}\:=\:\mathrm{1} \\ $$$${Area}\:\:{of}\:\:{region}\:\:{that}\:\:{bordered}\:\:{by}\:\:{red}\:\:{line}\:\:{is}\:\:… \\ $$ Answered by mr W…
Question Number 89097 by TawaTawa1 last updated on 15/Apr/20 Commented by mr W last updated on 15/Apr/20 $$\sqrt{\mathrm{5}^{\mathrm{2}} +\left(\mathrm{10}+\mathrm{5}\right)^{\mathrm{2}} }=\mathrm{5}\sqrt{\mathrm{10}} \\ $$$${s}=\mathrm{5}\sqrt{\mathrm{10}}−\frac{\mathrm{5}}{\mathrm{5}\sqrt{\mathrm{10}}}\left(\mathrm{15}+\mathrm{5}\right)=\mathrm{3}\sqrt{\mathrm{10}} \\ $$$${area}\:={s}^{\mathrm{2}} =\mathrm{9}×\mathrm{10}=\mathrm{90}…
Question Number 23559 by ajfour last updated on 01/Nov/17 Commented by ajfour last updated on 01/Nov/17 $${For}\:{the}\:{situation}\:{shown},\:{find}\: \\ $$$${the}\:\boldsymbol{{tension}}\:\boldsymbol{{T}}_{\mathrm{0}} \:{at}\:{midpoint}\:{P}. \\ $$$${Also}\:{find}\:{the}\:{length}\:\boldsymbol{{l}}\:{of}\:{rope}\:{in} \\ $$$${terms}\:{of}\:\boldsymbol{{a}}.\:{Given}\:{mass}\:{of}\:{rope} \\…
Question Number 89092 by 174 last updated on 15/Apr/20 $${Evaluate}\::\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:{e}^{−{n}} \:\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\frac{{n}^{{k}} }{{k}!} \\ $$ Commented by abdomathmax last updated on 15/Apr/20 $${we}\:{have}\:\:{e}^{{n}}…
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Question Number 23556 by Tinkutara last updated on 01/Nov/17 $$\mathrm{A}\:\mathrm{ball}\:\mathrm{falls}\:\mathrm{vertically}\:\mathrm{on}\:\mathrm{to}\:\mathrm{a}\:\mathrm{floor},\:\mathrm{with} \\ $$$$\mathrm{momentum}\:{p},\:\mathrm{and}\:\mathrm{then}\:\mathrm{bounces} \\ $$$$\mathrm{repeatedly},\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{restitution} \\ $$$$\mathrm{is}\:{e}.\:\mathrm{The}\:\mathrm{total}\:\mathrm{momentum}\:\mathrm{imparted}\:\mathrm{by} \\ $$$$\mathrm{the}\:\mathrm{ball}\:\mathrm{to}\:\mathrm{the}\:\mathrm{floor}\:\mathrm{is} \\ $$ Answered by ajfour last updated…
Question Number 89089 by Abhinav Sonker last updated on 15/Apr/20 $$\mathrm{16}^{\mathrm{3}/\mathrm{4}} \:+\mathrm{2} \\ $$ Answered by Joel578 last updated on 15/Apr/20 $$\mathrm{16}\:=\:\mathrm{2}^{\mathrm{4}} \\ $$$$\Rightarrow\:\left(\mathrm{2}^{\mathrm{4}} \right)^{\mathrm{3}/\mathrm{4}}…