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Author: Tinku Tara

prove-that-the-sum-2-2-2-2-3-2-4-2-2019-2-2020-is-divisible-by-30-

Question Number 154401 by mathdanisur last updated on 18/Sep/21 $$\mathrm{prove}\:\mathrm{that}\:\mathrm{the}\:\mathrm{sum} \\ $$$$\mathrm{2}+\mathrm{2}^{\mathrm{2}} +\mathrm{2}^{\mathrm{3}} +\mathrm{2}^{\mathrm{4}} +…+\mathrm{2}^{\mathrm{2019}} +\mathrm{2}^{\mathrm{2020}} \\ $$$$\mathrm{is}\:\mathrm{divisible}\:\:\mathrm{by}\:\:\mathrm{30} \\ $$ Answered by talminator2856791 last updated…

x-y-y-x-82-x-x-y-y-83-9-5-x-y-

Question Number 154400 by mathdanisur last updated on 18/Sep/21 $$\mathrm{x}\sqrt{\mathrm{y}}\:-\:\mathrm{y}\sqrt{\mathrm{x}}\:=\:\mathrm{82} \\ $$$$\mathrm{x}\sqrt{\mathrm{x}}\:+\:\mathrm{y}\sqrt{\mathrm{y}}\:=\:\mathrm{83} \\ $$$$\frac{\mathrm{9}}{\mathrm{5}}\:\centerdot\:\left(\mathrm{x}\:+\:\mathrm{y}\right)\:=\:? \\ $$ Answered by TheHoneyCat last updated on 20/Sep/21 $$\mathrm{just}\:\mathrm{so}\:\mathrm{you}\:\mathrm{understand}\:\mathrm{my}\:\mathrm{mess}\:\left(\mathrm{1}\right)\:\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{first}\:\mathrm{equation}\:\mathrm{and}\:\left(\mathrm{2}\right)\:\mathrm{the}\:\mathrm{other} \\…

The-number-of-ordered-pair-s-x-y-satisfying-the-equations-sinx-cosy-1-and-x-2-y-2-9pi-2-is-are-

Question Number 23330 by Tinkutara last updated on 28/Oct/17 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{ordered}\:\mathrm{pair}\left(\mathrm{s}\right)\:\left({x},\:{y}\right) \\ $$$$\mathrm{satisfying}\:\mathrm{the}\:\mathrm{equations}\:\mathrm{sin}{x}.\mathrm{cos}{y}\:=\:\mathrm{1} \\ $$$$\mathrm{and}\:{x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \:\leqslant\:\mathrm{9}\pi^{\mathrm{2}} \:\mathrm{is}/\mathrm{are} \\ $$ Terms of Service Privacy Policy Contact:…

dear-tinku-tara-can-you-stop-this-guy-who-continuously-misuses-the-forum-for-his-own-purposes-but-not-for-exchanging-with-others-he-doesn-t-answer-any-request-of-other-people-in-english-or-even-in-

Question Number 154402 by mr W last updated on 18/Sep/21 $${dear}\:{tinku}\:{tara}: \\ $$$${can}\:{you}\:{stop}\:{this}\:{guy}\:{who}\:{continuously} \\ $$$${misuses}\:{the}\:{forum}\:{for}\:{his}\:{own} \\ $$$${purposes},\:{but}\:{not}\:{for}\:{exchanging}\:{with} \\ $$$${others}.\:{he}\:{doesn}'{t}\:{answer}\:{any}\:{request} \\ $$$${of}\:{other}\:{people}\:{in}\:{english}\:{or}\:{even}\:{in} \\ $$$${his}\:{native}\:{language}.\:{he}\:{ignores}\:{that} \\ $$$${other}\:{people}\:{red}\:{flag}\:{his}\:{posts}.…

Question-88865

Question Number 88865 by tw000001 last updated on 13/Apr/20 Commented by tw000001 last updated on 13/Apr/20 $$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{who}\:\mathrm{the}\:\mathrm{question}\:\mathrm{can}\:\mathrm{solve}. \\ $$ Terms of Service Privacy Policy Contact:…

Question-154396

Question Number 154396 by DELETED last updated on 18/Sep/21 Answered by DELETED last updated on 18/Sep/21 $$\mathrm{f}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\mathrm{3}}\mathrm{x}^{\mathrm{3}} −\mathrm{500x}^{\mathrm{2}} +\mathrm{6000}.\mathrm{000} \\ $$$$\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{x}^{\mathrm{2}} −\mathrm{1000x} \\ $$$$\mathrm{syarat}\:\mathrm{maximum}\:,\:\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{0} \\…

8cos-3-x-8-sin-3-2x-dx-

Question Number 88863 by M±th+et£s last updated on 13/Apr/20 $$\int\frac{\mathrm{8}{cos}^{\mathrm{3}} \left({x}\right)}{\mathrm{8}+{sin}^{\mathrm{3}} \mathrm{2}{x}}{dx} \\ $$$$ \\ $$ Commented by MJS last updated on 13/Apr/20 $$\mathrm{I}\:\mathrm{tried}\:\mathrm{everything}\:\mathrm{I}\:\mathrm{know},\:\mathrm{seems}\:\mathrm{impossible} \\…

Question-154398

Question Number 154398 by DELETED last updated on 18/Sep/21 Answered by DELETED last updated on 18/Sep/21 $$\left.\mathrm{2}\right).\:\overset{\mathrm{6}} {\:}\mathrm{P}_{\mathrm{3}} \:=\:\frac{\mathrm{6}!}{\left(\mathrm{6}−\mathrm{3}\right)!}\:=\:\frac{\mathrm{6}!}{\mathrm{3}!}\:=\frac{\mathrm{6}×\mathrm{5}×\mathrm{4}×\mathrm{3}!}{\mathrm{3}!} \\ $$$$\:\:\:\:\:\:\:\:\:\:=\mathrm{6}×\mathrm{5}×\mathrm{4} \\ $$$$\:\:\:\:\:\mathrm{yg}\:>\mathrm{400}\:\mathrm{ada}:\:\mathrm{3}×\mathrm{5}×\mathrm{4}=\mathrm{60}\:\mathrm{buah} \\ $$$$\:\mathrm{Jawaban}:\:\mathrm{B}…