Question Number 154202 by mathdanisur last updated on 15/Sep/21 $$\boldsymbol{\Omega}\:\:=\underset{\:\mathrm{0}} {\overset{\:\infty} {\int}}\:\frac{\mathrm{ln}\centerdot\left(\mathrm{1}\:+\:\mathrm{x}\right)}{\mathrm{x}\centerdot\left(\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{x}\:+\:\mathrm{1}\right)}\:\mathrm{dx}\:=\:? \\ $$ Answered by qaz last updated on 15/Sep/21 $$\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{ln}\left(\mathrm{1}+\mathrm{x}\right)}{\mathrm{x}\left(\mathrm{x}^{\mathrm{2}}…
Question Number 88663 by mary_ last updated on 12/Apr/20 $$\begin{cases}{{log}_{\mathrm{2}} {x}+{log}_{\mathrm{4}} {y}=\mathrm{4}}\\{{x}.{y}=\mathrm{8}}\end{cases} \\ $$ Answered by jagoll last updated on 28/Apr/20 $$\mathrm{log}_{\mathrm{2}} \left(\mathrm{x}\right)+\frac{\mathrm{1}}{\mathrm{2}}\mathrm{log}_{\mathrm{2}} \left(\frac{\mathrm{8}}{\mathrm{x}}\right)\:=\mathrm{4} \\…
Question Number 154192 by mnjuly1970 last updated on 15/Sep/21 $$ \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\Omega\::=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\:{x}.{sin}\left({ln}\left({x}\right)\right)}{\mathrm{1}−{x}}{dx} \\ $$$$\:\:\:\:\:\:\:\:\:{method}\:\mathrm{1} \\ $$$$\:\:\:\:\:\Omega=\:\mathrm{I}{m}\left[\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\:\:{x}^{\:{i}+\mathrm{1}} }{\mathrm{1}−{x}}\:{dx}=\Phi\right] \\ $$$$\:\:\:\:\:\:\:\:\:\Phi\:=\:\int_{\mathrm{0}}…
Question Number 23122 by math solver last updated on 26/Oct/17 Commented by math solver last updated on 26/Oct/17 $$\mathrm{q}.\mathrm{2}\:? \\ $$ Commented by math solver…
Question Number 154195 by rexford last updated on 15/Sep/21 $$\int\frac{{x}+{sinx}}{\mathrm{1}+{cosx}}{dx}\:\:\:\: \\ $$$${please},{help}\:{me} \\ $$ Answered by qaz last updated on 15/Sep/21 $$\because\:\left(\frac{\mathrm{sin}\:\mathrm{x}}{\mathrm{1}+\mathrm{cos}\:\mathrm{x}}\right)'=\frac{\mathrm{1}}{\mathrm{1}+\mathrm{cos}\:\mathrm{x}} \\ $$$$\therefore\int\frac{\mathrm{x}+\mathrm{sin}\:\mathrm{x}}{\mathrm{1}+\mathrm{cos}\:\mathrm{x}}\mathrm{dx} \\…
Question Number 88656 by ajfour last updated on 12/Apr/20 Commented by ajfour last updated on 12/Apr/20 $${If}\:\:{AB}={BC}\:,\:{find}\:{radius}\:{r}\:. \\ $$ Answered by ajfour last updated on…
Question Number 154194 by chinomso last updated on 15/Sep/21 Commented by alisiao last updated on 15/Sep/21 $$\int_{\mathrm{9}} ^{\:\mathrm{11}} \:\frac{\boldsymbol{{y}}+\mathrm{8}}{\boldsymbol{{c}}}\:\boldsymbol{{dy}}\:=\:\mathrm{1}\:\Rightarrow\:\frac{\mathrm{1}}{\boldsymbol{{c}}}\:\int_{\mathrm{9}} ^{\:\mathrm{11}} \:\left(\boldsymbol{{y}}+\mathrm{8}\right)\boldsymbol{{dy}}\:=\mathrm{1} \\ $$$$ \\ $$$$\boldsymbol{{c}}\:=\:\left(\frac{\boldsymbol{{y}}^{\mathrm{2}}…
Question Number 154186 by daus last updated on 15/Sep/21 Answered by puissant last updated on 15/Sep/21 $$\Omega=\int\frac{{x}^{\mathrm{3}} −\mathrm{7}{x}^{\mathrm{2}} +\mathrm{8}{x}+\mathrm{3}}{{x}^{\mathrm{2}} −\mathrm{7}{x}+\mathrm{12}}{dx} \\ $$$$=\int{x}−\frac{\mathrm{4}{x}−\mathrm{3}}{{x}^{\mathrm{2}} −\mathrm{7}{x}+\mathrm{12}}{dx}\:=\:\frac{\mathrm{1}}{\mathrm{2}}{x}^{\mathrm{2}} −\int\frac{\mathrm{4}{x}−\mathrm{3}}{{x}^{\mathrm{2}} −\mathrm{7}{x}+\mathrm{12}}{dx}…
Question Number 23110 by kasiulka202 last updated on 26/Oct/17 $${In}\:{which}\:{apptent}\:{give}\:{when}\:{to}\:\mathrm{10}\:{grams}\:{stop}\:{in}\:\mathrm{800}−{th}\:{apptent}\:{add}\:\:\mathrm{0}.\mathrm{1}\:{gram}\:{of}\:{copper}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 23109 by kasiulka202 last updated on 26/Oct/17 $${Concourse}\:{started}\:{in}\:\mathrm{24}\:{November}\:{and}\:{takes}\:\mathrm{12}\:{days}. \\ $$$${Which}\:{date}\:{ends}\:{Concourse}? \\ $$ Commented by Rasheed.Sindhi last updated on 26/Oct/17 $$\mathrm{5th}\:\mathrm{december} \\ $$ Terms…