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Author: Tinku Tara

Question-154100

Question Number 154100 by solihin last updated on 14/Sep/21 Answered by peter frank last updated on 14/Sep/21 $$\sqrt{\mathrm{a}}\:+\sqrt{\mathrm{b}}\:=\sqrt{\mathrm{c}} \\ $$$$\left(\sqrt{\mathrm{a}}\:+\sqrt{\mathrm{b}}\right)^{\mathrm{2}} =\left(\sqrt{\mathrm{c}}\:\right)^{\mathrm{2}} \\ $$$$\mathrm{a}+\mathrm{2}\sqrt{\mathrm{ab}}\:+\mathrm{b}=\mathrm{c} \\ $$$$\mathrm{5x}+\mathrm{1}+\mathrm{2}\sqrt{\left(\mathrm{5x}+\mathrm{1}\right)\left(\mathrm{x}−\mathrm{2}\right)}\:=\mathrm{8x}+\mathrm{1}…

1-cos-pi-11-1-cos-3pi-11-1-cos-5pi-11-1-cos-7pi-11-1-cos-9pi-11-

Question Number 88567 by jagoll last updated on 11/Apr/20 $$\left(\mathrm{1}+\mathrm{cos}\:\frac{\pi}{\mathrm{11}}\right)\left(\mathrm{1}+\mathrm{cos}\:\frac{\mathrm{3}\pi}{\mathrm{11}}\right)\left(\mathrm{1}+\mathrm{cos}\:\frac{\mathrm{5}\pi}{\mathrm{11}}\right)\left(\mathrm{1}+\mathrm{cos}\:\frac{\mathrm{7}\pi}{\mathrm{11}}\right)\left(\mathrm{1}+\mathrm{cos}\:\frac{\mathrm{9}\pi}{\mathrm{11}}\right) \\ $$ Commented by jagoll last updated on 11/Apr/20 $$\mathrm{T}=\:\left(\mathrm{2cos}\:^{\mathrm{2}} \left(\frac{\pi}{\mathrm{22}}\right)\right)\left(\mathrm{2cos}^{\mathrm{2}} \:\left(\frac{\mathrm{3}\pi}{\mathrm{22}}\right)\right)\left(\mathrm{2cos}\:^{\mathrm{2}} \left(\frac{\mathrm{5}\pi}{\mathrm{22}}\right)\right) \\ $$$$\left(\mathrm{2cos}\:^{\mathrm{2}}…

x-2-y-xy-72-y-2-x-xy-36-

Question Number 154099 by EDWIN88 last updated on 14/Sep/21 $$\:\begin{cases}{{x}^{\mathrm{2}} +{y}\sqrt{{xy}}\:=\:\mathrm{72}}\\{{y}^{\mathrm{2}} +{x}\sqrt{{xy}}\:=\:\mathrm{36}}\end{cases} \\ $$ Answered by EDWIN88 last updated on 14/Sep/21 $$\:\begin{cases}{{x}^{\mathrm{2}} +{y}\sqrt{{xy}}\:=\mathrm{72}}\\{\mathrm{2}{y}^{\mathrm{2}} +\mathrm{2}{x}\sqrt{{xy}}\:=\mathrm{72}}\end{cases} \\…

pi-6-3pi-4-tanx-1-tanx-dx-

Question Number 88559 by 675480065 last updated on 11/Apr/20 $$\int_{\frac{−\pi}{\mathrm{6}}} ^{\frac{\mathrm{3}\pi}{\mathrm{4}}} \frac{\sqrt{{tanx}}}{\mathrm{1}+\sqrt{{tanx}}}{dx} \\ $$ Commented by MJS last updated on 11/Apr/20 $$\mathrm{t}=\sqrt{\mathrm{tan}\:{x}}\:\rightarrow\:{dx}=\mathrm{2cos}^{\mathrm{2}} \:{x}\:\sqrt{\mathrm{tan}\:{x}}{dt} \\ $$$$\mathrm{this}\:\mathrm{leads}\:\mathrm{to}…

what-are-the-conditions-necessary-for-a-body-of-mass-mkg-on-an-incline-plane-at-angle-to-the-horizontal-to-remain-at-rest-

Question Number 23022 by NECx last updated on 25/Oct/17 $${what}\:{are}\:{the}\:{conditions}\:{necessary} \\ $$$${for}\:{a}\:{body}\:{of}\:{mass}\:{mkg}\:{on}\:{an}\:{incline}\:{plane} \\ $$$${at}\:{angle}\:\theta\:{to}\:{the}\:{horizontal}\:{to} \\ $$$${remain}\:{at}\:{rest}? \\ $$ Commented by NECx last updated on 25/Oct/17…

1-3-4x-1-2x-2-x-2-dx-

Question Number 23020 by ANTARES_VY last updated on 25/Oct/17 $$\underset{\mathrm{1}} {\overset{\mathrm{3}} {\int}}\frac{\mathrm{4}\boldsymbol{\mathrm{x}}+\mathrm{1}}{\mathrm{2}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{x}}−\mathrm{2}}\boldsymbol{\mathrm{dx}}=? \\ $$ Commented by Joel577 last updated on 25/Oct/17 $${it}'{s}\:{already}\:{done} \\ $$…