Question Number 88492 by jagoll last updated on 11/Apr/20 $$\mathrm{y}''\:−\mathrm{4y}'+\mathrm{5y}\:=\:\mathrm{1}+\mathrm{8cos}\:\mathrm{x}+\mathrm{e}^{\mathrm{2x}} \\ $$ Commented by niroj last updated on 11/Apr/20 $$\:\:\frac{\boldsymbol{\mathrm{d}}^{\mathrm{2}} \boldsymbol{\mathrm{y}}}{\boldsymbol{\mathrm{dx}}^{\mathrm{2}} }−\mathrm{4}\frac{\boldsymbol{\mathrm{dy}}}{\boldsymbol{\mathrm{dx}}}+\mathrm{5}\boldsymbol{\mathrm{y}}=\:\mathrm{1}+\mathrm{8}\boldsymbol{\mathrm{cos}}\:\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{e}}^{\mathrm{2}\boldsymbol{\mathrm{x}}} \\ $$$$\:\:\left(\mathrm{D}^{\mathrm{2}} −\mathrm{4D}+\mathrm{5}\right)\mathrm{y}=\:\mathrm{1}+\mathrm{8cos}\:\mathrm{x}\:+\mathrm{e}^{\mathrm{2x}}…
Question Number 22956 by Physics lover last updated on 24/Oct/17 Commented by Physics lover last updated on 24/Oct/17 $${find}\:{angular}\:{velocity}\:{after}\: \\ $$$${collision}\:{and}\:{loss}\:{in}\:{kinetic} \\ $$$${energy}? \\ $$…
Question Number 88490 by M±th+et£s last updated on 11/Apr/20 $$\int_{\mathrm{1}} ^{\infty} \:\frac{{x}^{\mathrm{4}} }{\mathrm{4}^{{x}} }{dx}=? \\ $$ Commented by jagoll last updated on 11/Apr/20 Commented by…
Question Number 88491 by M±th+et£s last updated on 11/Apr/20 $$\boldsymbol{{solve}} \\ $$$${cos}\left({x}\right)={k} \\ $$ Answered by mr W last updated on 11/Apr/20 $${if}\:\mid{k}\mid\leqslant\mathrm{1}: \\ $$$$\Rightarrow{x}=\mathrm{2}{n}\pi\pm\mathrm{cos}^{−\mathrm{1}}…
Question Number 154020 by mnjuly1970 last updated on 13/Sep/21 Commented by mr W last updated on 13/Sep/21 $${i}\:{think}\:{there}\:{is}\:{not}\:{enough}\:{info}. \\ $$ Commented by mr W last…
Question Number 88487 by I want to learn more last updated on 11/Apr/20 Commented by I want to learn more last updated on 11/Apr/20 $$\mathrm{Please}\:\mathrm{help}.…
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Question Number 22947 by ajfour last updated on 26/Oct/17 $$\underset{{x}\rightarrow\pi/\mathrm{2}} {\mathrm{lim}}\:\left(\mathrm{1}^{\mathrm{sec}\:^{\mathrm{2}} {x}} +\mathrm{2}^{\mathrm{sec}\:^{\mathrm{2}} {x}} +\mathrm{3}^{\mathrm{sec}\:^{\mathrm{2}} {x}} +….\right. \\ $$$$\left.\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…+{n}^{\mathrm{sec}\:^{\mathrm{2}} {x}} \right)^{\mathrm{cos}\:^{\mathrm{2}} {x}} \:=\:? \\ $$$$…
Question Number 22946 by ANTARES_VY last updated on 24/Oct/17 $$\underset{\mathrm{1}} {\overset{\mathrm{3}} {\int}}\frac{\mathrm{4}\boldsymbol{\mathrm{x}}+\mathrm{1}}{\mathrm{2}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{x}}−\mathrm{2}}\boldsymbol{\mathrm{dx}}\:\:\:?\boldsymbol{\mathrm{solve}} \\ $$ Answered by ajfour last updated on 24/Oct/17 $$=\mathrm{ln}\:\mathrm{19}\: \\ $$…