Question Number 88101 by Rio Michael last updated on 08/Apr/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 88098 by ar247 last updated on 08/Apr/20 $$\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\left(\frac{\mathrm{1}}{{x}}−\frac{\mathrm{1}}{\mathrm{sin}\:{x}}\right) \\ $$ Commented by ar247 last updated on 08/Apr/20 $${please}\:{explaint}\:{to}\:{me} \\ $$ Commented…
Question Number 22562 by anoop7760@gmail.com last updated on 20/Oct/17 $${solve}\overset{\mathrm{1}} {\int}_{\mathrm{0}} {ln}\left({x}\right){dx}/{x}^{\mathrm{2}} −{x}−\mathrm{1}\:{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 22561 by Bruce Lee last updated on 20/Oct/17 $$\boldsymbol{\mathrm{Solve}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{all}}\:\boldsymbol{\mathrm{integer}}\:\boldsymbol{{x}},\boldsymbol{{y}}\:\in\boldsymbol{{Z}} \\ $$$$\:\:\:\:\:\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} =\mathrm{19} \\ $$ Answered by $@ty@m last updated on 20/Oct/17 $${Case}−\mathrm{1}.\:{Let}\:{x}=\mathrm{0}…
Question Number 88097 by sahnaz last updated on 08/Apr/20 $$\int\frac{\mathrm{dx}}{\left(\mathrm{2x}−\mathrm{3}\right)^{\frac{\mathrm{2}}{\mathrm{3}}} } \\ $$ Answered by john santu last updated on 08/Apr/20 $$\int\:{t}^{−\mathrm{2}/\mathrm{3}} ×\frac{\mathrm{1}}{\mathrm{2}}{dt}\:\:\:\left[\:{t}\:=\:\mathrm{2}{x}−\mathrm{3}\:\right] \\ $$$$=\:\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{3}\:×\:\sqrt[{\mathrm{3}\:\:}]{{t}}\:+\:{c}\:…
Question Number 153629 by mathdanisur last updated on 08/Sep/21 Commented by benhamimed last updated on 09/Sep/21 $$\mathrm{1}+{x}+…+{x}^{{n}} =\frac{\mathrm{1}−{x}^{{n}} }{\mathrm{1}−{x}}=\frac{\frac{{t}^{{n}} −\mathrm{1}}{{t}^{{n}} }}{\frac{{t}−\mathrm{1}}{{t}}}=\frac{\left({t}^{{n}} −\mathrm{1}\right)}{{t}^{{n}−\mathrm{1}} \left({t}−\mathrm{1}\right)}\:\:\:\:{tq}\:{x}=\frac{\mathrm{1}}{{t}} \\ $$$${si}\:{x}=\frac{\mathrm{1}}{\mathrm{2021}}\:\:;{t}=\mathrm{2021}…
Question Number 153628 by otchereabdullai@gmail.com last updated on 08/Sep/21 $$\mathrm{A}\:\mathrm{ball}\:\mathrm{is}\:\mathrm{thrown}\:\mathrm{vertically}\:\mathrm{upwards}. \\ $$$$\mathrm{Its}\:\mathrm{hight}\left(\mathrm{h}\right)\mathrm{meters}\:\mathrm{at}\:\mathrm{time}\left(\:\mathrm{t}\right)\mathrm{seconds} \\ $$$$\mathrm{is}\:\mathrm{given}\:\mathrm{by}\:\mathrm{h}=\:\mathrm{5}+\mathrm{30t}−\mathrm{5t}^{\mathrm{2}} .\:\mathrm{Find}\:\mathrm{the} \\ $$$$\mathrm{maximum}\:\mathrm{hight}\:\mathrm{reached}\:\mathrm{by}\:\mathrm{the}\:\mathrm{ball}. \\ $$ Answered by mr W last updated…
Question Number 88092 by ar247 last updated on 08/Apr/20 $$\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\left(\frac{\mathrm{1}}{{x}}−\frac{\mathrm{1}}{\mathrm{sin}\:{x}}\right) \\ $$ Commented by ar247 last updated on 08/Apr/20 $${please}\:{help} \\ $$ Commented…
Question Number 22554 by *D¬ B£$T* last updated on 20/Oct/17 $${find}\:{the}\:{eqution}\:{of}\:{normal}\:{to} \\ $$$${the}\:{circle} \\ $$$$\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}{y}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{4}{y}−\mathrm{32}=\mathrm{0}\:{at}\left(\mathrm{2},\mathrm{3}\right) \\ $$ Answered by ajfour last updated on…
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