Question Number 87993 by abdomathmax last updated on 07/Apr/20 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{dx}}{\left({x}+\mathrm{1}\right)^{\mathrm{2}} \left({x}+\mathrm{2}\right)^{\mathrm{2}} \left({x}+\mathrm{3}\right)^{\mathrm{2}} } \\ $$ Commented by mathmax by abdo last updated on…
Question Number 22456 by Tinkutara last updated on 18/Oct/17 $$\mathrm{A}\:\mathrm{long}\:\mathrm{plank}\:\mathrm{begins}\:\mathrm{to}\:\mathrm{move}\:\mathrm{at}\:{t}\:=\:\mathrm{0} \\ $$$$\mathrm{and}\:\mathrm{accelerates}\:\mathrm{along}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{track} \\ $$$$\mathrm{with}\:\mathrm{a}\:\mathrm{speed}\:\mathrm{given}\:\mathrm{by}\:{v}\:=\:\mathrm{2}{t}^{\mathrm{2}} \:\mathrm{for}\:\mathrm{0}\:\leqslant\:{t} \\ $$$$\leqslant\:\mathrm{2}.\:\mathrm{After}\:\mathrm{2}\:\mathrm{s},\:\mathrm{the}\:\mathrm{plank}\:\mathrm{continues}\:\mathrm{to} \\ $$$$\mathrm{move}\:\mathrm{at}\:\mathrm{the}\:\mathrm{constant}\:\mathrm{speed}\:\mathrm{acquired}. \\ $$$$\mathrm{A}\:\mathrm{small}\:\mathrm{block}\:\mathrm{initially}\:\mathrm{at}\:\mathrm{rest}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{plank}\:\mathrm{begins}\:\mathrm{to}\:\mathrm{slip}\:\mathrm{at}\:{t}\:=\:\mathrm{1}\:\mathrm{s}\:\mathrm{and}\:\mathrm{stops} \\ $$$$\mathrm{sliding}\:\mathrm{at}\:{t}\:=\:\mathrm{3}\:\mathrm{s}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}…
Question Number 87991 by necxxx last updated on 07/Apr/20 Commented by necxxx last updated on 07/Apr/20 $${please}\:{help} \\ $$ Answered by mr W last updated…
Question Number 87988 by M±th+et£s last updated on 07/Apr/20 $${solve}\:{the}\:{PDE} \\ $$$$\mathrm{1}−{Z}={px}+{py}−{q}\sqrt{{pq}} \\ $$$$\mathrm{2}−{Z}={px}+{qy}+{sin}\left({p}+{q}\right) \\ $$$$\mathrm{3}−{p}\left(\mathrm{1}+{q}^{\mathrm{2}} \right)={q}\left({Z}−{a}\right) \\ $$$$\mathrm{4}−{Z}={xyp}^{\mathrm{2}} \\ $$ Terms of Service Privacy…
Question Number 87989 by john santu last updated on 07/Apr/20 $$\mathrm{find}\:\mathrm{maximum}\:\mathrm{value} \\ $$$$\mathrm{2x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} \:\mathrm{with}\:\mathrm{constraint} \\ $$$$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} −\mathrm{4x}+\mathrm{2y}+\mathrm{1}=\mathrm{0}\: \\ $$$$ \\ $$ Answered by…
Question Number 153517 by liberty last updated on 08/Sep/21 $$\:\:{L}=\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{\sqrt{\mathrm{2019}{x}−\mathrm{2018}}−\mathrm{1}}{\:\sqrt[{\mathrm{2018}}]{{x}^{\mathrm{2019}} }−\mathrm{1}} \\ $$$$\:{then}\:\mathrm{2}×{L}\:=? \\ $$ Commented by MJS_new last updated on 08/Sep/21 $$\mathrm{just}\:“\mathrm{hospitalize}''\:\mathrm{it}\:\Rightarrow\:{L}=\mathrm{1009} \\…
Question Number 22447 by Tinkutara last updated on 18/Oct/17 $$\mathrm{The}\:\mathrm{standard}\:\mathrm{heats}\:\mathrm{of}\:\mathrm{formation}\:\mathrm{of}\:\mathrm{at} \\ $$$$\mathrm{298}\:\mathrm{K}\:\mathrm{for}\:\mathrm{CCl}_{\mathrm{4}} \left(\mathrm{g}\right),\:\mathrm{H}_{\mathrm{2}} \mathrm{O}\left(\mathrm{g}\right),\:\mathrm{CO}_{\mathrm{2}} \left(\mathrm{g}\right)\:\mathrm{and} \\ $$$$\mathrm{HCl}\left(\mathrm{g}\right)\:\mathrm{are}\:−\mathrm{25}.\mathrm{5},\:−\mathrm{57}.\mathrm{8},\:−\mathrm{94}.\mathrm{1}\:\mathrm{and} \\ $$$$−\mathrm{22}.\mathrm{1}\:\mathrm{kcal}\:\mathrm{mol}^{−\mathrm{1}} \:\mathrm{respectively}.\:\mathrm{Calculate} \\ $$$$\Delta_{\mathrm{r}} \mathrm{H}^{\circleddash} \:\mathrm{for}\:\mathrm{the}\:\mathrm{reaction} \\…
Question Number 22446 by Tinkutara last updated on 18/Oct/17 $$\mathrm{Select}\:\mathrm{the}\:\mathrm{species}\:\mathrm{which}\:\mathrm{has}\:\mathrm{the}\:\mathrm{smallest} \\ $$$$\mathrm{radius}\:\mathrm{stating}\:\mathrm{appropriate}\:\mathrm{reason}. \\ $$$$\mathrm{K}^{+} ,\:\mathrm{Sr}^{\mathrm{2}+} ,\:\mathrm{Ar} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 153518 by Tawa11 last updated on 08/Sep/21 $$\mathrm{Show}\:\mathrm{whether}\:\:\:\underset{\mathrm{n}\:\:=\:\:\mathrm{1}} {\overset{\infty} {\sum}}\:\left(\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{3}\:\:\:\:+\:\:\:\mathrm{n}^{\mathrm{2}} \mathrm{x}^{\mathrm{2}} }\right)\:\:\:\:\:\mathrm{is}\:\mathrm{uniformly}\:\mathrm{convegence}\:\mathrm{for}\:\mathrm{real} \\ $$$$\mathrm{value}\:\mathrm{of}\:\mathrm{x}. \\ $$ Answered by puissant last updated on…
Question Number 153513 by yeti123 last updated on 08/Sep/21 $$\left(\frac{{x}}{\mathrm{5}}\:+\:\frac{{y}}{\mathrm{3}}\right)\left(\frac{\mathrm{5}}{{x}}\:+\:\frac{\mathrm{3}}{{y}}\right)\:=\:\mathrm{139},\:\forall{x},{y}\:\in\:\mathbb{R}_{>\mathrm{0}} \\ $$$$\mathrm{find}\:\mathrm{maximum}\:\mathrm{and}\:\mathrm{minimum}\:\mathrm{of}\:\:\frac{{x}\:+\:{y}}{\:\sqrt{{xy}}} \\ $$ Answered by liberty last updated on 08/Sep/21 $$\Rightarrow\frac{{x}+{y}}{\:\sqrt{{xy}}}\:=\:\sqrt{\frac{{x}}{{y}}}+\sqrt{\frac{{y}}{{x}}}=\sqrt{\frac{\mathrm{5}\lambda}{\mathrm{3}}}+\sqrt{\frac{\mathrm{3}}{\mathrm{5}\lambda}} \\ $$$${from}\:{condition} \\…