Question Number 208693 by Frix last updated on 21/Jun/24 $$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{area}\:\mathrm{enclosed}\:\mathrm{by}\:\mathrm{the}\:\mathrm{curve} \\ $$$$\left(\frac{\mathrm{1}}{{x}}−\mathrm{2}\right)^{\mathrm{2}} +\left(\frac{\mathrm{1}}{{y}}−\mathrm{2}\right)^{\mathrm{2}} =\mathrm{1} \\ $$ Answered by mr W last updated on 21/Jun/24 $$\frac{\mathrm{1}}{{x}}−\mathrm{2}={u}\:\Rightarrow{x}=\frac{\mathrm{1}}{\mathrm{2}+{u}}…
Question Number 208690 by Tawa11 last updated on 21/Jun/24 Answered by mr W last updated on 21/Jun/24 $$\left(\mathrm{2}{r}−\mathrm{3}\right)×\mathrm{3}=\mathrm{2}^{\mathrm{2}} \\ $$$$\Rightarrow{r}=\frac{\mathrm{13}}{\mathrm{6}} \\ $$$${shaded}\:{area}=\frac{\pi}{\mathrm{2}}\left(\frac{\mathrm{13}}{\mathrm{6}}\right)^{\mathrm{2}} −\left(\frac{\mathrm{13}}{\mathrm{6}}\right)×\mathrm{2}\approx\mathrm{3}.\mathrm{04} \\ $$…
Question Number 208685 by hardmath last updated on 21/Jun/24 $$\mathrm{25}\:\mathrm{tan}\:\mathrm{x}\:=\:\mathrm{3} \\ $$$$\mathrm{x}\:=\:? \\ $$ Answered by Rasheed.Sindhi last updated on 21/Jun/24 $$\mathrm{tan}\:\mathrm{x}=\frac{\mathrm{3}}{\mathrm{25}} \\ $$$$\mathrm{x}=\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{3}}{\mathrm{25}}\right)…
Question Number 208686 by hardmath last updated on 21/Jun/24 $$\mathrm{cos}^{\mathrm{2}} \:\mathrm{2x}\:=\:\mathrm{sin}^{\mathrm{2}} \:\mathrm{2x}\:+\:\frac{\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$$\mathrm{x}\:=\:? \\ $$ Answered by MM42 last updated on 21/Jun/24 $${cos}^{\mathrm{2}} \mathrm{2}{x}−{sin}^{\mathrm{2}}…
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Question Number 208733 by Frix last updated on 22/Jun/24 $$\mathrm{2}\underset{\frac{\mathrm{1}}{\mathrm{3}}} {\overset{\mathrm{1}} {\int}}\frac{{x}\sqrt{−\mathrm{3}{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{1}}}{\mathrm{7}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{1}}{dx}=? \\ $$$$\mathrm{Exact}\:\mathrm{solution}\:\mathrm{needed}. \\ $$ Answered by Ghisom last updated on 24/Jun/24…
Question Number 208704 by hardmath last updated on 21/Jun/24 $$\mathrm{Find}: \\ $$$$\mathrm{arccos}\:\left(\mathrm{arctg}\:\frac{\mathrm{5}}{\mathrm{12}}\:\:+\:\:\mathrm{arcsin}\:\frac{\mathrm{4}}{\mathrm{5}}\right)\:=\:? \\ $$ Commented by mr W last updated on 21/Jun/24 $${non}−{sense}. \\ $$$${arccos}\:\left({x}\right)\:{is}\:{only}\:{defined}\:{for}\:…
Question Number 208637 by efronzo1 last updated on 20/Jun/24 $$\:\:\:{s} \\ $$ Answered by Berbere last updated on 20/Jun/24 $${find}\:{fractin}\:{that}\:{one}\:{man}\:{can}\:{compete}\:{per}\:{day}\:{V}_{{m}} \\ $$$${and}\:{women}\:{V}_{{w}} \\ $$$${V}_{{m}} =\frac{\mathrm{1}}{\mathrm{16}.\mathrm{24}}…
Question Number 208670 by hardmath last updated on 20/Jun/24 $$\mathrm{Find}:\:\:\:\int_{\mathrm{0}} ^{\:\mathrm{5}} \:\sqrt{\frac{\mathrm{1}}{\mathrm{2}}\:\left(\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{2x}\:+\:\mathrm{1}\right)}\:\mathrm{dx}\:\:=\:\:? \\ $$ Commented by essaad last updated on 20/Jun/24 Answered by Berbere…
Question Number 208638 by lmcp1203 last updated on 20/Jun/24 Terms of Service Privacy Policy Contact: info@tinkutara.com