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Question Number 153430 by mnjuly1970 last updated on 07/Sep/21 Commented by mnjuly1970 last updated on 07/Sep/21 $${thanks}\:{alot}…. \\ $$ Commented by mindispower last updated on…
Question Number 87893 by jagoll last updated on 07/Apr/20 $$\int\:\sqrt{\frac{\mathrm{sin}\:\mathrm{x}}{\mathrm{sin}\:\mathrm{x}−\mathrm{cos}\:\mathrm{x}}}\:\:\mathrm{dx}\: \\ $$ Answered by jagoll last updated on 07/Apr/20 Terms of Service Privacy Policy Contact:…
Question Number 153426 by SANOGO last updated on 07/Sep/21 Answered by puissant last updated on 07/Sep/21 $$\forall{x}\in\left[−\mathrm{1};\mathrm{1}\right]\:,\:{f}\left({x}\right)=\frac{\pi}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}.. \\ $$ Commented by SANOGO last updated…
Question Number 87886 by TawaTawa1 last updated on 06/Apr/20 Commented by jagoll last updated on 07/Apr/20 $$\mathrm{x}^{\mathrm{2}} −\mathrm{4x}+\mathrm{1}\:=\:\mathrm{0} \\ $$$$\left(\mathrm{x}−\mathrm{2}\right)^{\mathrm{2}} −\mathrm{3}=\mathrm{0} \\ $$$$\mathrm{x}\:=\:\mathrm{2}\:\pm\:\sqrt{\mathrm{3}}\: \\ $$$$\mathrm{y}^{\mathrm{2}}…
Question Number 153420 by alcohol last updated on 07/Sep/21 $${how}\:{many}\:{x}\:\in\mathbb{R}\:{satisfy}\:{x}^{\mathrm{99}} −\mathrm{99}{x}+\mathrm{1}=\mathrm{0} \\ $$ Answered by mr W last updated on 07/Sep/21 $${f}'\left({x}\right)=\mathrm{99}{x}^{\mathrm{98}} −\mathrm{99}=\mathrm{0} \\ $$$${x}=\pm\mathrm{1}…
Question Number 87884 by M±th+et£s last updated on 06/Apr/20 Answered by mind is power last updated on 06/Apr/20 $$!{k}\:? \\ $$ Commented by M±th+et£s last…
Question Number 153422 by ZiYangLee last updated on 07/Sep/21 $$\underset{{x}\rightarrow{a}} {\mathrm{lim}}\:\frac{{x}^{\mathrm{3}} }{\mathrm{2}^{{x}} }\:= \\ $$ Answered by puissant last updated on 07/Sep/21 $$=\frac{{a}^{\mathrm{3}} }{\mathrm{2}^{{a}} }\:,\:{a}>\mathrm{0}…
Question Number 22348 by Tinkutara last updated on 16/Oct/17 $$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{solutions}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{equation}\:\mathrm{1}\:+\:\mathrm{2}\:\mathrm{cosec}\:{x}\:=\:−\frac{\mathrm{sec}^{\mathrm{2}} \:\frac{{x}}{\mathrm{2}}}{\mathrm{2}}\:\mathrm{in} \\ $$$$\mathrm{the}\:\mathrm{interval}\:\left[\mathrm{0},\:\mathrm{4}\pi\right]\:\mathrm{is}\:{n}\pi,\:\mathrm{where}\:{n}\:\mathrm{is} \\ $$$$\mathrm{equal}\:\mathrm{to} \\ $$ Answered by ajfour last updated on…