Question Number 87817 by M±th+et£s last updated on 06/Apr/20 $${f}\left(\frac{{x}−\mathrm{3}}{{x}+\mathrm{1}}\right)+{f}\left(\frac{{x}+\mathrm{3}}{{x}−\mathrm{1}}\right)={x} \\ $$$${find}\:{f}\left({x}\right) \\ $$ Commented by M±th+et£s last updated on 06/Apr/20 $${like}\:\mathrm{87755}\:{question}\:{but}\:{here}\:\left({x}−\mathrm{1}\right) \\ $$ Commented…
Question Number 22279 by A1B1C1D1 last updated on 14/Oct/17 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 87815 by jagoll last updated on 06/Apr/20 $$\mathrm{I}\:=\:\underset{\mathrm{0}} {\overset{\frac{\pi}{\mathrm{2}}} {\int}}\:\mathrm{cos}\:\mathrm{2x}\left(\mathrm{cos}\:^{\mathrm{4}} \mathrm{x}+\mathrm{sin}\:^{\mathrm{4}} \mathrm{x}\right)\:\mathrm{dx} \\ $$ Commented by john santu last updated on 06/Apr/20 $$\mathrm{cos}\:^{\mathrm{4}}…
Question Number 22276 by kasiulka202 last updated on 14/Oct/17 Answered by Joel577 last updated on 14/Oct/17 $$\mathrm{9}\:+\:\left(\mathrm{7}\:×\:\mathrm{2}\right)\:−\:\left(\mathrm{10}\:×\:\mathrm{4}\right)\:−\:\mathrm{5} \\ $$$$=\:\mathrm{9}\:+\:\mathrm{14}\:−\:\mathrm{40}\:−\:\mathrm{5} \\ $$$$=\:\mathrm{23}\:−\:\mathrm{40}\:−\:\mathrm{5} \\ $$$$=\:−\mathrm{17}\:−\:\mathrm{5} \\ $$$$=\:−\mathrm{22}…
Question Number 153345 by Jonathanwaweh last updated on 06/Sep/21 Answered by puissant last updated on 08/Sep/21 $$\rightarrow\:{premiere}\:{ligne}\:{on}\:{a}\:{une}\:{suite}\:{geometrique} \\ $$$${de}\:{raison}\:\mathrm{2}\:{donc}\:?=\mathrm{8} \\ $$$$\rightarrow\:{deuxieme}\:{ligne}\:{on}\:{a}\:{une}\:{succession}\: \\ $$$${de}\:\mathrm{1}\:{donc}\:?=\mathrm{1} \\ $$$$\rightarrow\:{troisieme}\:{ligne}\:{permutation}\:{de}\:\mathrm{0}\:{et}\:\mathrm{1}…
Question Number 22273 by kasiulka202 last updated on 14/Oct/17 $${Ant}\:{rided}\:\mathrm{30}\:{meters}\:{in}\:\mathrm{12}\:{seconds}.\:{How}\:{fast}\:{are}\:{rided}\:{ant}? \\ $$ Commented by Rasheed.Sindhi last updated on 14/Oct/17 $$\:\mathrm{Speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{ant}=\frac{\mathrm{30}}{\mathrm{12}}\:\:=\mathrm{2}.\mathrm{5}\:\mathrm{m}/\mathrm{s}. \\ $$ Terms of Service…
Question Number 153346 by mathlove last updated on 06/Sep/21 Answered by liberty last updated on 06/Sep/21 $$\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\frac{{f}\left({x}\right)−\mathrm{4}}{{x}−\mathrm{2}}=\mathrm{15}\:\rightarrow\begin{cases}{{f}\left(\mathrm{2}\right)=\mathrm{4}}\\{{f}\:'\left(\mathrm{2}\right)=\mathrm{15}}\end{cases} \\ $$$$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\frac{\mathrm{2}{x}^{\mathrm{2}} −{f}\left({x}\right)}{{x}−\mathrm{2}}\:=\infty \\ $$ Answered…
Question Number 153340 by mnjuly1970 last updated on 06/Sep/21 $$ \\ $$$$\:\:\:\:\:\mathrm{Solve}\:.. \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:,\:\mathrm{y}\:,\:\mathrm{z}\:\in\:\mathbb{R}^{\:+} \:\&\:\:\mathrm{x}+\:\mathrm{y}=\:\mathrm{z} \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{K}\::=\:\mathrm{Min}_{\:} \:\left(\frac{\:\mathrm{x}^{\:\mathrm{4}} \:+\:\mathrm{y}^{\:\mathrm{4}} +\:\mathrm{z}^{\:\mathrm{4}} }{\mathrm{x}^{\:\mathrm{2}} \mathrm{y}^{\:\mathrm{2}} }\:\right)\:=\:?\:\:\:\:\:\:\:\:\:\:\blacksquare\:\:\:\:\:\:\:\:\:…
Question Number 22269 by kasiulka202 last updated on 14/Oct/17 $${Product}\:{costs}\:\mathrm{599}.\mathrm{99}\:{zloty}.\:{Person}\:{have}\:\mathrm{433}.\mathrm{94}\:{zloty}. \\ $$$${How}\:{muh}\:{zloty}\:{is}\:{a}\:{rest}\:{or}\:{missing}? \\ $$ Answered by FilupS last updated on 14/Oct/17 $$\mathrm{599}.\mathrm{99}={x}+\mathrm{433}.\mathrm{94} \\ $$$${x}=\mathrm{599}.\mathrm{99}−\mathrm{433}.\mathrm{94} \\…
Question Number 153342 by Rankut last updated on 06/Sep/21 Commented by Rankut last updated on 06/Sep/21 $${help}\:\:{please} \\ $$ Answered by liberty last updated on…