Question Number 208632 by necx122 last updated on 19/Jun/24 $$\int{e}^{−{x}^{\mathrm{2}} } {dx} \\ $$$${could}\:{this}\:{be}\:{integrated}\:{by}\:{part}?\:{What} \\ $$$${approach}\:{would}\:{most}\:{likely}\:{be}\:{suitable} \\ $$$${for}\:{this}\:{integral}? \\ $$$$ \\ $$ Commented by Tinku…
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Question Number 208624 by vipin last updated on 19/Jun/24 Answered by Berbere last updated on 19/Jun/24 $$\frac{\mathrm{1}}{{cosec}^{−} \left(−\sqrt{\mathrm{2}}\right)}=\mathrm{sin}^{−\mathrm{1}} \left(−\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\right)=−\frac{\pi}{\mathrm{4}} \\ $$$${f}\left({x}\right).\mathrm{tan}^{−\mathrm{1}} \left(\frac{\sqrt{\mathrm{1}+{x}}−\sqrt{\mathrm{1}−{x}}}{\:\sqrt{\mathrm{1}+{x}}+\sqrt{\mathrm{1}−{x}}}\right)=\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{1}−\sqrt{\frac{\mathrm{1}−{x}}{\mathrm{1}+{x}}}}{\mathrm{1}+\sqrt{\frac{\mathrm{1}−{x}}{\mathrm{1}+{x}}}}\right)…{E} \\ $$$${g}\left({y}\right)=\mathrm{tan}^{−\mathrm{1}}…
Question Number 208569 by pticantor last updated on 18/Jun/24 $$\boldsymbol{{help}}\:\boldsymbol{{me}}\:\boldsymbol{{to}}\:\boldsymbol{{solve}}\:\boldsymbol{{this}}\:\boldsymbol{{please}} \\ $$$$\:\:\boldsymbol{{y}}''−\sqrt{\mathrm{1}+\boldsymbol{{y}}'^{\mathrm{2}} }=\boldsymbol{{x}}^{\mathrm{2}} \\ $$$$\boldsymbol{{solve}}\:\boldsymbol{{this}}\:\boldsymbol{{differential}}\:\boldsymbol{{equation}} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$ Terms of…
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Question Number 208567 by Tawa11 last updated on 18/Jun/24 Answered by kgmxdd last updated on 18/Jun/24 Commented by Tawa11 last updated on 18/Jun/24 $$\mathrm{Any}\:\mathrm{workings}\:\mathrm{sir}? \\…
Question Number 208594 by Jimenez000 last updated on 18/Jun/24 $${Find} \\ $$$${x}+\mathrm{3}^{{x}} <\mathrm{4} \\ $$ Answered by mr W last updated on 18/Jun/24 $$\mathrm{3}^{{x}} <\mathrm{4}−{x}…
Question Number 208591 by RoseAli last updated on 18/Jun/24 Answered by A5T last updated on 18/Jun/24 $$\mathrm{0}\leqslant\mathrm{3}\mid{sinx}\mid\leqslant\mathrm{3};\:−\mathrm{4}\leqslant−\mathrm{4}\mid{cosx}\mid\leqslant\mathrm{0} \\ $$$$\Rightarrow−\mathrm{4}\leqslant\mathrm{3}\mid{sinx}\mid−\mathrm{4}\mid{cosx}\mid\leqslant\mathrm{3} \\ $$$$\Rightarrow{y}\in\left[−\mathrm{4},\mathrm{3}\right] \\ $$ Terms of…
Question Number 208617 by abdomath last updated on 18/Jun/24 Answered by efronzo1 last updated on 19/Jun/24 $$\:\:\begin{cases}{\:\downharpoonleft}\end{cases} \\ $$ Terms of Service Privacy Policy Contact:…