Question Number 21654 by Joel577 last updated on 30/Sep/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of}\:{Q}\:\mathrm{that}\:\mathrm{satisfy}: \\ $$$$\mid{xy}\left({x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \right)\:+\:{yz}\left({y}^{\mathrm{2}} \:−\:{z}^{\mathrm{2}} \right)\:+\:{zx}\left({z}^{\mathrm{2}} \:−\:{x}^{\mathrm{2}} \right)\mid\:\leqslant\:{Q}\left({x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \:+\:{z}^{\mathrm{2}} \right)^{\mathrm{2}} \\ $$ Terms of…
Question Number 21653 by Joel577 last updated on 30/Sep/17 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{pair}\:\mathrm{of}\:\mathrm{solutions}\:\left({x},{y}\right)\:\mathrm{that}\:\mathrm{satisfy}\:\mathrm{the}\:\mathrm{equation}: \\ $$$$\sqrt[{\mathrm{3}}]{\mathrm{7}{x}^{\mathrm{2}} \:−\:\mathrm{13}{xy}\:+\:\mathrm{7}{y}^{\mathrm{2}} }\:=\:\mid{x}\:−\:{y}\mid\:+\:\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 152721 by SANOGO last updated on 31/Aug/21 Commented by SANOGO last updated on 31/Aug/21 $${ok}\:{merci}\:{bien}\:{mon}\:\:{prof}\:.{je}\:{m}'{excuse}\:{seulement}\:{je}\:{ne}\:{maitrise}\:{pas}\:{bien}\:{l}'{application}\:{c}'{est}\:{pourquoi} \\ $$ Commented by puissant last updated on…
Question Number 21651 by Tinkutara last updated on 30/Sep/17 $${How}\:{many}\:{four}-{digit}\:{numbers}\:{are} \\ $$$${there}\:{whose}\:{decimal}\:{notation}\:{contains} \\ $$$${not}\:{more}\:{than}\:{two}\:{distinct}\:{digits}? \\ $$ Commented by mrW1 last updated on 01/Oct/17 $$\mathrm{576}\:? \\…
Question Number 21650 by Glorious Man last updated on 30/Sep/17 $${The}\:{three}\:{distinct}\:{successive}\:{terms}\:{of}\:{an}\:{A}.{P}\:{are} \\ $$$${the}\:{first},{second}\:{and}\:{fourth}\:{terms}\:{of}\:{a}\:{G}.{P}.\:{If}\:{the}\: \\ $$$${sum}\:{to}\:{infinity}\:{of}\:{a}\:{G}.{P}\:{is}\:\mathrm{3}+\sqrt{\mathrm{5}}\:,\:{find}\: \\ $$$${the}\:{first}\:{term}. \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 152723 by Tawa11 last updated on 31/Aug/21 Answered by Olaf_Thorendsen last updated on 31/Aug/21 $$\mathrm{V}_{\mathrm{5}\Omega} \:=\:\mathrm{5}\Omega×\mathrm{I}_{\mathrm{5}\Omega} \:=\:\mathrm{5}\Omega×\mathrm{2A}\:=\:\mathrm{10V} \\ $$$$\mathrm{V}_{\mathrm{10}\Omega} \:=\:\mathrm{V}_{\mathrm{5}\Omega} \:=\:\mathrm{10V} \\ $$$$\mathrm{I}_{\mathrm{10}\Omega}…
Question Number 152722 by SANOGO last updated on 31/Aug/21 Answered by Olaf_Thorendsen last updated on 31/Aug/21 $$\bullet\:\mathrm{I}\:=\:\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{e}^{−\frac{\mathrm{1}}{{x}}} }{{x}^{\mathrm{2}} }\:{dx} \\ $$$$\mathrm{Let}\:{u}\:=\:\frac{\mathrm{1}}{{x}}\:: \\ $$$$\mathrm{I}\:=\:\int_{\mathrm{1}}…
Question Number 87185 by M±th+et£s last updated on 03/Apr/20 $$\int\frac{\mathrm{2}{x}−\mathrm{1}}{{x}\left({x}^{\mathrm{2}} +\mathrm{3}\right)}{dx} \\ $$ Answered by peter frank last updated on 03/Apr/20 $$\int\frac{\mathrm{2}{x}}{{x}\left({x}^{\mathrm{2}} +\mathrm{3}\right)}{dx}−\int\frac{\mathrm{1}}{{x}\left({x}^{\mathrm{2}} +\mathrm{3}\right)}{dx} \\…
Question Number 21643 by Joel577 last updated on 30/Sep/17 $$\frac{\mathrm{1}}{\mathrm{1}\:+\:\mathrm{1}^{\mathrm{2}} \:+\:\mathrm{1}^{\mathrm{4}} }\:+\:\frac{\mathrm{2}}{\mathrm{1}\:+\:\mathrm{2}^{\mathrm{2}} \:+\:\mathrm{2}^{\mathrm{4}} }\:+\:\frac{\mathrm{3}}{\mathrm{1}\:+\:\mathrm{3}^{\mathrm{2}} \:+\:\mathrm{3}^{\mathrm{4}} }\:+\:…\:+\:\frac{\mathrm{2012}}{\mathrm{1}\:+\:\mathrm{2012}^{\mathrm{2}} \:+\:\mathrm{2012}^{\mathrm{4}} } \\ $$ Commented by Joel577 last updated…
Question Number 152712 by Tawa11 last updated on 31/Aug/21 Terms of Service Privacy Policy Contact: info@tinkutara.com