Question Number 21628 by Tinkutara last updated on 29/Sep/17 $$\mathrm{One}\:\mathrm{end}\:\mathrm{of}\:\mathrm{a}\:\mathrm{massless}\:\mathrm{spring}\:\mathrm{of}\:\mathrm{constant} \\ $$$$\mathrm{100}\:\mathrm{N}/\mathrm{m}\:\mathrm{and}\:\mathrm{natural}\:\mathrm{length}\:\mathrm{0}.\mathrm{5}\:\mathrm{m}\:\mathrm{is} \\ $$$$\mathrm{fixed}\:\mathrm{and}\:\mathrm{the}\:\mathrm{other}\:\mathrm{end}\:\mathrm{is}\:\mathrm{connected}\:\mathrm{to} \\ $$$$\mathrm{a}\:\mathrm{particle}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{0}.\mathrm{5}\:\mathrm{kg}\:\mathrm{lying}\:\mathrm{on}\:\mathrm{a} \\ $$$$\mathrm{frictionless}\:\mathrm{horizontal}\:\mathrm{table}.\:\mathrm{The}\:\mathrm{spring} \\ $$$$\mathrm{remains}\:\mathrm{horizontal}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{mass}\:\mathrm{is}\:\mathrm{made} \\ $$$$\mathrm{to}\:\mathrm{rotate}\:\mathrm{at}\:\mathrm{an}\:\mathrm{angular}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{2} \\ $$$$\mathrm{rad}/{s},\:\mathrm{find}\:\mathrm{the}\:\mathrm{elongation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{spring}. \\…
Question Number 152697 by mathdanisur last updated on 31/Aug/21 $$\mathrm{In}\:\:\bigtriangleup\mathrm{ABC}\:\:\mathrm{prove}\:\mathrm{that}: \\ $$$$\Sigma\:\frac{\left(\mathrm{r}_{\boldsymbol{\mathrm{a}}} +\mathrm{r}_{\boldsymbol{\mathrm{b}}} \right)\left(\mathrm{r}_{\boldsymbol{\mathrm{a}}} +\mathrm{r}_{\boldsymbol{\mathrm{c}}} \right)}{\mathrm{h}_{\boldsymbol{\mathrm{b}}} +\mathrm{h}_{\boldsymbol{\mathrm{c}}} }\:\geqslant\:\frac{\mathrm{9r}}{\mathrm{2}} \\ $$ Terms of Service Privacy Policy…
Question Number 21626 by etchemin last updated on 29/Sep/17 $$\mathrm{Is}\:\mathrm{it}\:\mathrm{also}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{import}\:\mathrm{text}\:\mathrm{or}\:\mathrm{fomulars} \\ $$$$\mathrm{from}\:\mathrm{other}\:\mathrm{apps}\:\mathrm{using}\:\mathrm{the}\:\mathrm{android}−\mathrm{clipboard}? \\ $$ Commented by Joel577 last updated on 30/Sep/17 $$\mathrm{No},\:\mathrm{it}\:\mathrm{isn}'\mathrm{t}. \\ $$$$\mathrm{You}\:\mathrm{should}\:\mathrm{convert}\:\mathrm{it}\:\mathrm{to}\:\mathrm{picture}\:\mathrm{or}\:\mathrm{screenshot}\:\mathrm{it} \\…
Question Number 152692 by ZiYangLee last updated on 31/Aug/21 $$\mathrm{If}\:{b}\:\mathrm{and}\:{h}\:\mathrm{are}\:\mathrm{two}\:\mathrm{integers}\:\mathrm{with}\:{b}>{h}, \\ $$$$\mathrm{and}\:{b}^{\mathrm{2}} +{h}^{\mathrm{2}} ={b}\left({a}+{h}\right)+{ah}, \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{b}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 21622 by Joel577 last updated on 29/Sep/17 $$\mathrm{If}\:\mathrm{sec}\:{x}\:+\:\mathrm{tan}\:{x}\:=\:\mathrm{2012} \\ $$$$\mathrm{then}\:\mathrm{2011}\left(\mathrm{cosec}\:{x}\:+\:\mathrm{cot}\:{x}\right)\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$$$\left({A}\right)\:\mathrm{2011} \\ $$$$\left({B}\right)\:\mathrm{2012} \\ $$$$\left({C}\right)\:\mathrm{2013} \\ $$$$\left({D}\right)\:\frac{\mathrm{2011}}{\mathrm{2013}} \\ $$$$\left({E}\right)\:\frac{\mathrm{2013}}{\mathrm{2012}} \\ $$ Answered…
Question Number 152691 by ZiYangLee last updated on 31/Aug/21 $$\mathrm{If}\:{a},{p},{q}\:\mathrm{are}\:\mathrm{primes}\:\mathrm{with}\:{a}<{p},\:\mathrm{and} \\ $$$${a}+{p}={q},\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{a}. \\ $$ Answered by Rasheed.Sindhi last updated on 01/Sep/21 $${odd}+{odd}={even} \\ $$$$\Rightarrow{odd}\:{prime}+{odd}\:{prime}={even} \\…
Question Number 87153 by jagoll last updated on 03/Apr/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{e}^{\mathrm{x}} +\mathrm{e}^{−\mathrm{x}} −\mathrm{2}}{\mathrm{x}^{\mathrm{2}} } \\ $$ Commented by john santu last updated on 03/Apr/20 $$\underset{{x}\rightarrow\mathrm{0}}…
Question Number 21612 by x² – y²@gmail.com last updated on 29/Sep/17 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 87146 by john santu last updated on 03/Apr/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{region}\: \\ $$$$\mathrm{enclosed}\:\mathrm{by}\:\mathrm{the}\:\mathrm{polar}\:\mathrm{curve}\: \\ $$$$\mathrm{r}\:=\:\mathrm{4}\:+\:\mathrm{2}\:\mathrm{cos}\:\theta\:? \\ $$ Answered by jagoll last updated on 03/Apr/20 Commented…
Question Number 21611 by Nayon last updated on 29/Sep/17 $$\mathrm{Sin5}°\:=? \\ $$ Answered by $@ty@m last updated on 29/Sep/17 Terms of Service Privacy Policy Contact:…