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Question-86627

Question Number 86627 by Omer Alattas last updated on 29/Mar/20 Commented by abdomathmax last updated on 29/Mar/20 $${x}\rightarrow\frac{{tanx}}{\mathrm{1}+{x}^{\mathrm{2}} \:+{x}^{\mathrm{4}} }\:{is}\:{odd}\:\Rightarrow\int_{−\mathrm{1}} ^{\mathrm{1}} \:\frac{{tanx}}{\mathrm{1}+{x}^{\mathrm{2}} \:+{x}^{\mathrm{4}} }{dx}=\mathrm{0} \\…

ABC-is-an-isocel-triangle-such-as-AB-AC-3-and-BC-4-and-are-its-angles-Show-that-cos-2-sin-2-Hi-sirs-

Question Number 86614 by mathocean1 last updated on 29/Mar/20 $${ABC}\:{is}\:{an}\:{isocel}\:{triangle}\:{such}\:{as} \\ $$$${AB}={AC}=\mathrm{3}\:\:{and}\:{BC}=\mathrm{4} \\ $$$$\alpha\:,\:\beta\:,\:{and}\:\gamma\:{are}\:{its}\:{angles}. \\ $$$${Show}\:{that}\:{cos}\left(\frac{\alpha+\beta}{\mathrm{2}}\right)={sin}\left(\frac{\gamma}{\mathrm{2}}\right) \\ $$$${Hi}\:{sirs}… \\ $$ Answered by TANMAY PANACEA. last…

tan-x-dx-

Question Number 86615 by ar247 last updated on 29/Mar/20 $$\int\sqrt{{tan}\:{x}\:}{dx} \\ $$ Commented by Ar Brandon last updated on 29/Mar/20 $${let}\:\:{t}^{\mathrm{2}} ={tan}\:{x}\:\:\Rightarrow\mathrm{2}{tdt}={sec}^{\mathrm{2}} {xdx} \\ $$$$\Rightarrow{dx}=\frac{\mathrm{2}{t}}{\mathrm{1}+{t}^{\mathrm{4}}…

Question-152151

Question Number 152151 by john_santu last updated on 26/Aug/21 Answered by Rasheed.Sindhi last updated on 26/Aug/21 $${f}\left({x}\right)=\frac{{ax}+{b}}{{cx}+{d}} \\ $$$$\bullet{f}\left({f}\left({x}\right)\right)=\frac{{a}\left(\frac{{ax}+{b}}{{cx}+{d}}\right)+{b}}{{c}\left(\frac{{ax}+{b}}{{cx}+{d}}\right)+{d}}={x} \\ $$$$\:\:\:=\frac{{a}\left({ax}+{b}\right)+{b}\left({cx}+{d}\right)}{{c}\left({ax}+{b}\right)+{d}\left({cx}+{d}\right)}={x} \\ $$$${x}=\mathrm{0}:\:\frac{{ab}+{bd}}{{bc}+{d}^{\mathrm{2}} }=\mathrm{0} \\…

Question-152150

Question Number 152150 by timila1127 last updated on 26/Aug/21 Answered by puissant last updated on 26/Aug/21 $$\left({AB}\right){C}=\begin{bmatrix}{\mathrm{4}\:\:\:\:\:\:\mathrm{3}}\\{\mathrm{8}\:\:\:\:\:\:\mathrm{7}}\end{bmatrix}\begin{bmatrix}{\mathrm{3}\:\:\:\:\:\:\mathrm{1}}\\{\mathrm{1}\:\:\:\:\:\:\mathrm{2}}\end{bmatrix} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\begin{bmatrix}{\mathrm{12}+\mathrm{8}\:\:\:\:\:\:\:\:\mathrm{9}+\mathrm{7}}\\{\mathrm{4}+\mathrm{16}\:\:\:\:\:\:\mathrm{3}+\mathrm{14}}\end{bmatrix} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\begin{bmatrix}{\mathrm{20}\:\:\:\:\:\mathrm{16}}\\{\mathrm{20}\:\:\:\:\:\mathrm{17}}\end{bmatrix} \\ $$ Terms of…

Question-86610

Question Number 86610 by TawaTawa1 last updated on 29/Mar/20 Commented by TawaTawa1 last updated on 29/Mar/20 $$\mathrm{X}\:\:\mathrm{and}\:\:\mathrm{Y}\:\:\mathrm{are}\:\mathrm{two}\:\mathrm{cylindrical}\:\mathrm{tanks}\:\mathrm{with}\:\mathrm{base}\:\:\mathrm{2r}\:\mathrm{cm}\:\:\mathrm{and}\:\:\mathrm{r}\:\mathrm{cm} \\ $$$$\mathrm{respectively}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{water}\:\mathrm{level}\:\mathrm{in}\:\mathrm{Y}\:\mathrm{is}\:\mathrm{10}\:\mathrm{cm}.\:\mathrm{What}\:\mathrm{level}\:\mathrm{will} \\ $$$$\mathrm{the}\:\mathrm{same}\:\mathrm{quantity}\:\mathrm{of}\:\mathrm{water}\:\mathrm{be}\:\mathrm{in}\:\:\mathrm{X}.\:\:\left(\pi\:\:=\:\:\frac{\mathrm{22}}{\mathrm{7}}\right) \\ $$ Commented by…