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Author: Tinku Tara

A-small-solid-spherical-ball-of-high-density-is-dropped-in-a-viscous-liquid-Its-journey-in-the-liquid-is-best-described-in-the-following-figure-by-the-curve-

Question Number 20973 by Tinkutara last updated on 09/Sep/17 $$\mathrm{A}\:\mathrm{small}\:\mathrm{solid}\:\mathrm{spherical}\:\mathrm{ball}\:\mathrm{of}\:\mathrm{high} \\ $$$$\mathrm{density}\:\mathrm{is}\:\mathrm{dropped}\:\mathrm{in}\:\mathrm{a}\:\mathrm{viscous}\:\mathrm{liquid}. \\ $$$$\mathrm{Its}\:\mathrm{journey}\:\mathrm{in}\:\mathrm{the}\:\mathrm{liquid}\:\mathrm{is}\:\mathrm{best}\:\mathrm{described} \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{following}\:\mathrm{figure}\:\mathrm{by}\:\mathrm{the}\:\mathrm{curve} \\ $$ Commented by Tinkutara last updated on 09/Sep/17…

Boyle-temperature-is-given-by-1-T-B-a-Rb-2-2-T-B-a-Rb-3-T-B-a-27b-2-4-T-B-b-aR-

Question Number 20972 by Tinkutara last updated on 09/Sep/17 $$\mathrm{Boyle}\:\mathrm{temperature}\:\mathrm{is}\:\mathrm{given}\:\mathrm{by} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{T}_{\mathrm{B}} \:=\:\frac{\mathrm{a}}{\mathrm{Rb}^{\mathrm{2}} } \\ $$$$\left(\mathrm{2}\right)\:\mathrm{T}_{\mathrm{B}} \:=\:\frac{\mathrm{a}}{\mathrm{Rb}} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{T}_{\mathrm{B}} \:=\:\frac{\mathrm{a}}{\mathrm{27b}^{\mathrm{2}} } \\ $$$$\left(\mathrm{4}\right)\:\mathrm{T}_{\mathrm{B}} \:=\:\frac{\mathrm{b}}{\mathrm{aR}} \\…

Show-that-2sin7-cos3-sin10-sin4-

Question Number 152035 by puissant last updated on 25/Aug/21 $${Show}\:{that}\:\mathrm{2}{sin}\mathrm{7}\theta{cos}\mathrm{3}\theta={sin}\mathrm{10}\theta+{sin}\mathrm{4}\theta. \\ $$ Answered by som(math1967) last updated on 25/Aug/21 $$\mathrm{2}{sinA}\boldsymbol{{cosB}}=\boldsymbol{{sin}}\left(\boldsymbol{{A}}+\boldsymbol{{B}}\right)+\boldsymbol{{sin}}\left(\boldsymbol{{A}}−\boldsymbol{{B}}\right) \\ $$$$\therefore\mathrm{2}\boldsymbol{{sin}}\mathrm{7}\boldsymbol{\theta{cos}}\mathrm{3}\boldsymbol{\theta}=\boldsymbol{{sin}}\left(\mathrm{7}\boldsymbol{\theta}+\mathrm{3}\boldsymbol{\theta}\right)+\boldsymbol{{sin}}\left(\mathrm{7}\boldsymbol{\theta}−\mathrm{3}\boldsymbol{\theta}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\boldsymbol{{sin}}\mathrm{10}\boldsymbol{\theta}+{s}\boldsymbol{{in}}\mathrm{4}\boldsymbol{\theta} \\…

3x-2-2y-17-3-y-2-6x-7-xy-

Question Number 152034 by mathdanisur last updated on 25/Aug/21 $$\begin{cases}{\mathrm{3x}^{\mathrm{2}} \:-\:\mathrm{2y}\:=\:-\:\frac{\mathrm{17}}{\mathrm{3}}}\\{\mathrm{y}^{\mathrm{2}} \:-\:\mathrm{6x}\:=\:\mathrm{7}}\end{cases}\:\:\:\Rightarrow\:\:\mathrm{xy}\:=\:? \\ $$ Answered by Rasheed.Sindhi last updated on 25/Aug/21 $$\begin{cases}{\mathrm{3x}^{\mathrm{2}} \:-\:\mathrm{2y}\:=\:-\:\frac{\mathrm{17}}{\mathrm{3}}}\\{\mathrm{y}^{\mathrm{2}} \:-\:\mathrm{6x}\:=\:\mathrm{7}}\end{cases}\:\:\:\Rightarrow\:\:\mathrm{xy}\:=\:?\: \\…

lemme-join-miss-Tawa-Tawa-here-It-takes-8-painters-working-at-the-same-rate-5-hours-to-paint-a-house-If-6-painters-are-working-at-2-3-the-rate-of-the-8-painters-how-long-would-it-take-them-to-paint

Question Number 20955 by NECx last updated on 09/Sep/17 $$\mathrm{lemme}\:\mathrm{join}\:\mathrm{miss}\:\mathrm{Tawa}\:\mathrm{Tawa}\:\mathrm{here}. \\ $$$$ \\ $$$$\mathrm{It}\:\mathrm{takes}\:\mathrm{8}\:\mathrm{painters}\:\mathrm{working}\:\mathrm{at}\:\mathrm{the} \\ $$$$\mathrm{same}\:\mathrm{rate}\:,\mathrm{5}\:\mathrm{hours}\:\mathrm{to}\:\mathrm{paint}\:\mathrm{a} \\ $$$$\mathrm{house}.\mathrm{If}\:\mathrm{6}\:\mathrm{painters}\:\mathrm{are}\:\mathrm{working}\:\mathrm{at} \\ $$$$\mathrm{2}/\mathrm{3}\:\mathrm{the}\:\mathrm{rate}\:\mathrm{of}\:\mathrm{the}\:\mathrm{8}\:\mathrm{painters},\mathrm{how} \\ $$$$\mathrm{long}\:\mathrm{would}\:\mathrm{it}\:\mathrm{take}\:\mathrm{them}\:\mathrm{to}\:\mathrm{paint} \\ $$$$\mathrm{the}\:\mathrm{same}\:\mathrm{house}? \\…

x-2-1-x-4-1-dx-

Question Number 86491 by john santu last updated on 29/Mar/20 $$\int\:\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}{\mathrm{x}^{\mathrm{4}} +\mathrm{1}}\:\mathrm{dx}\:?\: \\ $$ Commented by john santu last updated on 29/Mar/20 $$\mathrm{dear}\:\mathrm{prof}\:\mathrm{mr}\:\mathrm{mjs}.\:\mathrm{what}\:\mathrm{the}\:\mathrm{super} \\…