Question Number 86472 by Chi Mes Try last updated on 28/Mar/20 Answered by TANMAY PANACEA. last updated on 28/Mar/20 $$\int_{−\mathrm{1}} ^{\mathrm{1}} {xdx}−\int_{−\mathrm{1}} ^{\mathrm{1}} \left[{x}\right]{dx} \\…
Question Number 152010 by RB95 last updated on 25/Aug/21 Commented by RB95 last updated on 25/Aug/21 $$ \\ $$$${Slt} \\ $$$${Pouviez}\:{vous}\:{m}'{aider}? \\ $$ Answered by…
Question Number 20936 by Tinkutara last updated on 08/Sep/17 $$\mathrm{A}\:\mathrm{graph}\:\mathrm{of}\:{x}\:\mathrm{versus}\:{t}\:\mathrm{is}\:\mathrm{shown}\:\mathrm{in}\:\mathrm{Figure}. \\ $$$$\mathrm{Choose}\:\mathrm{correct}\:\mathrm{alternatives}\:\mathrm{from}\:\mathrm{below}. \\ $$$$\left({a}\right)\:\mathrm{The}\:\mathrm{particle}\:\mathrm{was}\:\mathrm{released}\:\mathrm{from} \\ $$$$\mathrm{rest}\:\mathrm{at}\:{t}\:=\:\mathrm{0} \\ $$$$\left({b}\right)\:\mathrm{At}\:{B},\:\mathrm{the}\:\mathrm{acceleration}\:{a}\:>\:\mathrm{0} \\ $$$$\left({c}\right)\:\mathrm{At}\:{C},\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{and}\:\mathrm{the} \\ $$$$\mathrm{acceleration}\:\mathrm{vanish} \\ $$$$\left({d}\right)\:\mathrm{Average}\:\mathrm{velocity}\:\mathrm{for}\:\mathrm{the}\:\mathrm{motion} \\…
Question Number 20935 by Tinkutara last updated on 08/Sep/17 $$\mathrm{If}\:\mid{z}\:+\:\omega\mid^{\mathrm{2}} \:=\:\mid{z}\mid^{\mathrm{2}} \:+\:\mid\omega\mid^{\mathrm{2}} ,\:\mathrm{where}\:{z}\:\mathrm{and}\:\omega \\ $$$$\mathrm{are}\:\mathrm{complex}\:\mathrm{numbers},\:\mathrm{then} \\ $$$$\left(\mathrm{1}\right)\:\frac{{z}}{\omega}\:\mathrm{is}\:\mathrm{purely}\:\mathrm{real} \\ $$$$\left(\mathrm{2}\right)\:\frac{{z}}{\omega}\:\mathrm{is}\:\mathrm{purely}\:\mathrm{imaginary} \\ $$$$\left(\mathrm{3}\right)\:{z}\bar {\omega}\:+\:\bar {{z}}\omega\:=\:\mathrm{0} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{amp}\left(\frac{{z}}{\omega}\right)\:=\:\frac{\pi}{\mathrm{2}}…
Question Number 20934 by Tinkutara last updated on 08/Sep/17 $$\mathrm{If}\:{z}\:\mathrm{satisfies}\:\mid{z}\:−\:\mathrm{1}\mid\:<\:\mid{z}\:+\:\mathrm{3}\mid,\:\mathrm{then}\:\omega\:= \\ $$$$\mathrm{2}{z}\:+\:\mathrm{3}\:−\:{i}\:\mathrm{satisfies} \\ $$$$\left(\mathrm{1}\right)\:\mid\omega\:−\:\mathrm{5}\:−\:{i}\mid\:<\:\mid\omega\:+\:\mathrm{3}\:+\:{i}\mid \\ $$$$\left(\mathrm{2}\right)\:\mid\omega\:−\:\mathrm{5}\mid\:<\:\mid\omega\:+\:\mathrm{3}\mid \\ $$$$\left(\mathrm{3}\right)\:\mathrm{Im}\:\left({i}\omega\right)\:>\:\mathrm{1} \\ $$$$\left(\mathrm{4}\right)\:\mid\mathrm{arg}\left(\omega\:−\:\mathrm{1}\right)\mid\:<\:\frac{\pi}{\mathrm{2}} \\ $$ Commented by Tinkutara…
Question Number 20933 by Tinkutara last updated on 08/Sep/17 $$\mathrm{If}\:{z}\:\mathrm{is}\:\mathrm{a}\:\mathrm{complex}\:\mathrm{number}\:\mathrm{satisfying} \\ $$$${z}\:+\:{z}^{−\mathrm{1}} \:=\:\mathrm{1},\:\mathrm{then}\:{z}^{{n}} \:+\:{z}^{−{n}} ,\:{n}\:\in\:{N},\:\mathrm{has} \\ $$$$\mathrm{the}\:\mathrm{value} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{2}\left(−\mathrm{1}\right)^{{n}} ,\:\mathrm{when}\:{n}\:\mathrm{is}\:\mathrm{a}\:\mathrm{multiple}\:\mathrm{of}\:\mathrm{3} \\ $$$$\left(\mathrm{2}\right)\:\left(−\mathrm{1}\right)^{{n}−\mathrm{1}} ,\:\mathrm{when}\:{n}\:\mathrm{is}\:\mathrm{not}\:\mathrm{a}\:\mathrm{multiple}\:\mathrm{of} \\ $$$$\mathrm{3}…
Question Number 20932 by Tinkutara last updated on 08/Sep/17 $$\mathrm{If}\:{a},\:{b},\:{c}\:\mathrm{are}\:\mathrm{real}\:\mathrm{numbers}\:\mathrm{and}\:{z}\:\mathrm{is}\:\mathrm{a} \\ $$$$\mathrm{complex}\:\mathrm{number}\:\mathrm{such}\:\mathrm{that},\:{a}^{\mathrm{2}} \:+\:{b}^{\mathrm{2}} \:+\:{c}^{\mathrm{2}} \\ $$$$=\:\mathrm{1}\:\mathrm{and}\:{b}\:+\:{ic}\:=\:\left(\mathrm{1}\:+\:{a}\right){z},\:\mathrm{then}\:\frac{\mathrm{1}\:+\:{iz}}{\mathrm{1}\:−\:{iz}} \\ $$$$\mathrm{equals}. \\ $$$$\left(\mathrm{1}\right)\:\frac{{b}\:−\:{ic}}{\mathrm{1}\:−\:{ia}} \\ $$$$\left(\mathrm{2}\right)\:\frac{{a}\:+\:{ib}}{\mathrm{1}\:+\:{c}} \\ $$$$\left(\mathrm{3}\right)\:\frac{\mathrm{1}\:−\:{c}}{{a}\:−\:{ib}} \\…
Question Number 152001 by otchereabdullai@gmail.com last updated on 25/Aug/21 $$\mathrm{Four}\:\mathrm{members}\:\mathrm{of}\:\mathrm{a}\:\mathrm{school}'\mathrm{s}\:\mathrm{first}\:\mathrm{eleven} \\ $$$$\mathrm{criket}\:\mathrm{team}\:\mathrm{are}\:\mathrm{also}\:\mathrm{in}\:\mathrm{the}\:\mathrm{first}\:\mathrm{fourteen} \\ $$$$\mathrm{rugby}\:\mathrm{team}.\:\mathrm{How}\:\mathrm{many}\:\mathrm{members}\:\mathrm{play} \\ $$$$\mathrm{for}\:\mathrm{at}\:\mathrm{least}\:\mathrm{one}\:\mathrm{of}\:\mathrm{the}\:\mathrm{two}\:\mathrm{teams} \\ $$ Answered by mr W last updated on…
Question Number 152000 by Olaf_Thorendsen last updated on 25/Aug/21 $$\bullet\:{Histoire}\:{de}\:{code}\:{secret}\: \\ $$$$ \\ $$$$\mathrm{Vous}\:\hat {\mathrm{e}tes}\:\mathrm{un}\:\mathrm{espion}\:\mathrm{et}\:\mathrm{vous}\:\mathrm{souhaitez} \\ $$$$\mathrm{assister}\:\:\grave {\mathrm{a}}\:\mathrm{une}\:\mathrm{r}\acute {\mathrm{e}union}\:\mathrm{secr}\grave {\mathrm{e}te}\:\mathrm{dans}\:\mathrm{une} \\ $$$$\mathrm{une}\:\mathrm{ambassade}\:\mathrm{ou}\:\mathrm{le}\:\mathrm{garde}\:\mathrm{demande} \\ $$$$\mathrm{un}\:\mathrm{mot}\:\mathrm{de}\:\mathrm{passe}… \\…
Question Number 20927 by amaresh pradhan last updated on 08/Sep/17 $$\left({a}+{b}\right)×\left({a}+{b}\right) \\ $$ Answered by Joel577 last updated on 08/Sep/17 $$=\:\left({a}\:+\:{b}\right)^{\mathrm{2}} \:=\:{a}^{\mathrm{2}} \:+\:\mathrm{2}{ab}\:+\:{b}^{\mathrm{2}} \\ $$…