Question Number 86399 by Power last updated on 28/Mar/20 Commented by Prithwish Sen 1 last updated on 28/Mar/20 $$\mathrm{put}\:\mathrm{x}=\mathrm{2asin}^{\mathrm{2}} \mathrm{t} \\ $$$$\mathrm{and}\:\mathrm{simplify}. \\ $$ Commented…
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Question Number 151934 by john_santu last updated on 24/Aug/21 Answered by MJS_new last updated on 25/Aug/21 $$\mathrm{3}\left({x}^{\mathrm{2}} −\mathrm{1}\right)=\left(\mathrm{3}+\mathrm{4}\sqrt{{x}+\mathrm{1}}\right){x} \\ $$$$\Rightarrow \\ $$$${x}_{\mathrm{1}} =−\frac{\mathrm{11}}{\mathrm{18}}+\frac{\sqrt{\mathrm{13}}}{\mathrm{18}} \\ $$$${x}_{\mathrm{2}}…
Question Number 86397 by M±th+et£s last updated on 28/Mar/20 $$\int\frac{{dx}}{{sin}^{\mathrm{2}} \left({x}\right)+{tan}^{\mathrm{2}} \left({x}\right)}\:{dx} \\ $$ Commented by Prithwish Sen 1 last updated on 28/Mar/20 $$−\mathrm{cotx}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\mid\mathrm{tan}^{\mathrm{2}} \mathrm{x}+\frac{\mathrm{1}}{\mathrm{2}}\mid+\mathrm{C}…
Question Number 20857 by Joel577 last updated on 05/Sep/17 $$\int\:\sqrt{\mathrm{sin}\:{x}}\:+\:\sqrt{\mathrm{cos}\:{x}}\:{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 20851 by j.masanja06@gmail.com last updated on 04/Sep/17 $${if}\:\left({x}+{y}\right)^{{m}+{n}} ={x}^{{m}} {y}^{{n}} ,{show}\:{that}\:\frac{{dy}}{{dx}}=\frac{{y}}{{x}} \\ $$ Answered by ajfour last updated on 04/Sep/17 $${taking}\:{logarithm}\:{on}\:{both}\:{sides}: \\ $$$$\left({m}+{n}\right)\mathrm{ln}\:\left({x}+{y}\right)={m}\mathrm{ln}\:{x}+{n}\mathrm{ln}\:{y}…
Question Number 20850 by j.masanja06@gmail.com last updated on 04/Sep/17 $${given}\:{that}\:{y}={log}\sqrt{\frac{\mathrm{1}+{cos}^{\mathrm{2}} {x}}{\mathrm{1}−{e}^{\mathrm{2}{x}} }},{find} \\ $$$$\frac{{dy}}{{dx}} \\ $$ Answered by Hitler last updated on 05/Sep/17 $$\frac{−{sinxcosx}+\left(\mathrm{1}+{sinxcosx}+{cos}^{\mathrm{2}} {x}\right){e}^{\mathrm{2}{x}}…
Question Number 20849 by j.masanja06@gmail.com last updated on 04/Sep/17 $${The}\:{time}\:{period},{T}\:\:{of}\:{pendulum}\:{of} \\ $$$${length}\:{l}\:{is}\:{given}\:{by}\:{T}=\mathrm{2}\Pi\sqrt{\frac{{l}}{{g}}}{where} \\ $$$$\:{l}\:{amd}\:{g}\:{are}\:{constant}.{Find}\:{the}\: \\ $$$${approximate}\:{percentage}\:{increase}\: \\ $$$${in}\:{time}\:{T},\:{when}\:{the}\:{length}\:{of}\: \\ $$$${pendulum}\:{increases}\:{by}\:\mathrm{4\%} \\ $$ Answered by mrW1…