Question Number 20810 by Tinkutara last updated on 03/Sep/17 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{triples}\:\left({a},\:{b},\:{c}\right)\:\mathrm{of} \\ $$$$\mathrm{positive}\:\mathrm{integers}\:\mathrm{such}\:\mathrm{that} \\ $$$$\left(\mathrm{i}\right)\:{a}\:<\:{b}\:<\:{c}\:<\:\mathrm{10}\:\mathrm{and}\:\left(\mathrm{ii}\right)\:{a},\:{b},\:{c},\:\mathrm{10}\:\mathrm{form} \\ $$$$\mathrm{the}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{a}\:\mathrm{quadrilateral}? \\ $$ Commented by Tinkutara last updated on 04/Sep/17…
Question Number 151876 by tabata last updated on 23/Aug/21 Answered by Olaf_Thorendsen last updated on 23/Aug/21 $$\mathrm{A}\:=\:\mathrm{0}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{3}}{\mathrm{5}}+\frac{\mathrm{2}}{\mathrm{3}}+\frac{\mathrm{5}}{\mathrm{7}}+… \\ $$$$\mathrm{A}\:=\:\frac{\mathrm{0}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{2}}{\mathrm{4}}+\frac{\mathrm{3}}{\mathrm{5}}+\frac{\mathrm{4}}{\mathrm{6}}+\frac{\mathrm{5}}{\mathrm{7}}+… \\ $$$$\mathrm{A}\:=\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{n}}{{n}+\mathrm{2}}\:\:\:\mathrm{diverges} \\ $$…
Question Number 86343 by jagoll last updated on 28/Mar/20 $$\mathrm{Dear}\:\mathrm{mr}\:\mathrm{w}.\:\mathrm{i}\:\mathrm{want}\: \\ $$$$\mathrm{discuss}\:\mathrm{for}\:\mathrm{equation} \\ $$$$\mathrm{find}\:\mathrm{minimum}\:\mathrm{and}\:\mathrm{maximum}\:\mathrm{value} \\ $$$$\mathrm{of}\:\mathrm{xy}\:+\mathrm{2}\:\mathrm{with}\:\mathrm{constraint} \\ $$$$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}\:} =\:\mathrm{6}. \\ $$$$\mathrm{my}\:\mathrm{way}\:\left(\mathrm{short}\:\mathrm{cut}\right) \\ $$$$\Rightarrow\:\mathrm{x}^{\mathrm{2}} \:=\:\mathrm{y}^{\mathrm{2}}…
Question Number 86341 by redmiiuser last updated on 28/Mar/20 $${Can}\:{anyone}\:{pls}\:{check}\: \\ $$$${question}\:{no}.\:\mathrm{76808} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 86339 by frempongfaustina24@gmail.com last updated on 28/Mar/20 $$\mathrm{4}^{{x}} +\mathrm{6}^{{x}} =\mathrm{9}^{{x}} \\ $$$$ \\ $$$$ \\ $$ Answered by jagoll last updated on 28/Mar/20…
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Question Number 86337 by frempongfaustina24@gmail.com last updated on 28/Mar/20 $$\left[\mathrm{4}\right. \\ $$ Commented by MJS last updated on 28/Mar/20 $$\mathrm{no}. \\ $$$$\mathrm{7} \\ $$ Terms…
Question Number 20800 by Tinkutara last updated on 03/Sep/17 $$\mathrm{If}\:\mathrm{Re}\left(\frac{{z}\:+\:\mathrm{4}}{\mathrm{2}{z}\:−\:\mathrm{1}}\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}},\:\mathrm{then}\:{z}\:\mathrm{is}\:\mathrm{represented} \\ $$$$\mathrm{by}\:\mathrm{a}\:\mathrm{point}\:\mathrm{lying}\:\mathrm{on} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{A}\:\mathrm{circle} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{An}\:\mathrm{ellipse} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{A}\:\mathrm{straight}\:\mathrm{line} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{No}\:\mathrm{real}\:\mathrm{locus} \\ $$ Commented by ajfour…
Question Number 20799 by Tinkutara last updated on 03/Sep/17 $$\mathrm{If}\:{z}^{\mathrm{2}} \:+\:{z}\mid{z}\mid\:+\:\mid{z}\mid^{\mathrm{2}} \:=\:\mathrm{0},\:\mathrm{then}\:\mathrm{locus}\:\mathrm{of}\:{z}\:\mathrm{is} \\ $$ Answered by ajfour last updated on 03/Sep/17 $${let}\:{z}={re}^{{i}\theta} \\ $$$$\Rightarrow\:\:{r}^{\mathrm{2}} {e}^{\mathrm{2}{i}\theta}…
Question Number 20798 by ANTARES_VY last updated on 03/Sep/17 $$\begin{cases}{\mathrm{4}\boldsymbol{{x}}−\boldsymbol{{y}}=\mathrm{11}}\\{\mathrm{2}\boldsymbol{{y}}+\mathrm{5}\boldsymbol{{x}}=\mathrm{5}}\\{\boldsymbol{{x}}−\mathrm{2}\boldsymbol{{z}}=\mathrm{9}}\end{cases}\:\:\:\:\boldsymbol{{z}}+\boldsymbol{{y}}−\boldsymbol{{x}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com