Menu Close

Author: Tinku Tara

given-sin-x-sin-y-2sin-x-y-x-y-0-find-the-value-of-tan-x-2-tan-y-2-

Question Number 86168 by jagoll last updated on 27/Mar/20 $$\mathrm{given}\: \\ $$$$\mathrm{sin}\:\mathrm{x}+\mathrm{sin}\:\mathrm{y}\:=\:\mathrm{2sin}\:\left(\mathrm{x}+\mathrm{y}\right)\: \\ $$$$\mathrm{x}+\mathrm{y}\:\neq\:\mathrm{0} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{tan}\:\frac{\mathrm{x}}{\mathrm{2}}\:\mathrm{tan}\:\frac{\mathrm{y}}{\mathrm{2}}\:=\: \\ $$ Answered by john santu last…

Question-20626

Question Number 20626 by NECx last updated on 29/Aug/17 Answered by $@ty@m last updated on 30/Aug/17 $$\frac{\mathrm{2}}{{log}_{{a}} {x}}+\frac{\mathrm{1}}{{log}_{{a}} {ax}}+\frac{\mathrm{3}}{{log}_{{a}} {a}^{\mathrm{2}} {x}}=\mathrm{0} \\ $$$$\frac{\mathrm{2}}{{log}_{{a}} {x}}+\frac{\mathrm{1}}{{log}_{{a}} {ax}}+\frac{\mathrm{1}}{{log}_{{a}}…

x-3-2022x-2021-0-1-x-1-x-

Question Number 151699 by iloveisrael last updated on 22/Aug/21 $$\:\:\:\:\underset{{x}^{\mathrm{3}} +\mathrm{2022}{x}−\mathrm{2021}=\mathrm{0}} {\sum}\left(\frac{\mathrm{1}+{x}}{\mathrm{1}−{x}}\right)\:=? \\ $$ Answered by mr W last updated on 22/Aug/21 $${x}^{\mathrm{3}} +\mathrm{2022}{x}−\mathrm{2021}=\mathrm{0} \\…

If-x-1-f-x-f-1-x-1-x-1-find-f-x-

Question Number 86160 by jagoll last updated on 27/Mar/20 $$\mathrm{If}\:\left(\mathrm{x}−\mathrm{1}\right)\:\mathrm{f}\left(\mathrm{x}\right)\:+\:\mathrm{f}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)\:=\:\frac{\mathrm{1}}{\mathrm{x}−\mathrm{1}} \\ $$$$\mathrm{find}\:\mathrm{f}\left(\mathrm{x}\right)\: \\ $$ Commented by john santu last updated on 27/Mar/20 $${replace}\:{x}\:{by}\:\frac{\mathrm{1}}{{x}} \\ $$$$\Rightarrow\left(\frac{\mathrm{1}}{{x}}−\mathrm{1}\right){f}\left(\frac{\mathrm{1}}{{x}}\right)+{f}\left({x}\right)=\:\frac{\mathrm{1}}{\frac{\mathrm{1}}{{x}}−\mathrm{1}}…

Question-20625

Question Number 20625 by mondodotto@gmail.com last updated on 29/Aug/17 Commented by $@ty@m last updated on 30/Aug/17 $${it}\:{seems}\:{something}\:{missing}\:{in}\:{the}\: \\ $$$${question}\:{because}\:{in}\:'{if}'\:{part},\:{there} \\ $$$${is}\:'>{c}'\:{but}\:{there}\:{is}\:{no}\:'{c}'\:{in}'{prove}\:{that}'\:{part}. \\ $$ Answered by…