Question Number 151426 by peter frank last updated on 21/Aug/21 $$\mathrm{Express}\:\frac{\mathrm{1}}{\mathrm{5}×\mathrm{9}}\:\mathrm{in}\:\mathrm{partial}\:\mathrm{fraction} \\ $$ Answered by liberty last updated on 21/Aug/21 $$\:\frac{\mathrm{1}}{\mathrm{n}\left(\mathrm{n}+\mathrm{4}\right)}=\frac{\mathrm{a}}{\mathrm{n}}+\frac{\mathrm{b}}{\mathrm{n}+\mathrm{4}}\: \\ $$$$\mathrm{a}=\:\left[\frac{\mathrm{1}}{\mathrm{n}+\mathrm{4}}\:\right]_{\mathrm{n}=\mathrm{0}} =\frac{\mathrm{1}}{\mathrm{4}} \\…
Question Number 151421 by peter frank last updated on 21/Aug/21 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \mathrm{log}\:\left(\mathrm{1}+\mathrm{tan}\:\mathrm{x}\right)\mathrm{dx} \\ $$ Commented by puissant last updated on 21/Aug/21 $${x}=\frac{\pi}{\mathrm{4}}−{t}\:\rightarrow\:{dx}=−{dt} \\ $$$${Q}=\int_{\frac{\pi}{\mathrm{4}}}…
Question Number 151423 by peter frank last updated on 21/Aug/21 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{\mathrm{dx}}{\mathrm{1}+\mathrm{tan}\:^{\mathrm{5}} \mathrm{x}} \\ $$ Answered by Olaf_Thorendsen last updated on 21/Aug/21 $$\mathrm{I}\:=\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}}…
Question Number 20349 by Tinkutara last updated on 25/Aug/17 $$\mathrm{A}\:\mathrm{ball}\:\mathrm{rolled}\:\mathrm{on}\:\mathrm{ice}\:\mathrm{with}\:\mathrm{a}\:\mathrm{velocity}\:\mathrm{of} \\ $$$$\mathrm{14}\:\mathrm{ms}^{−\mathrm{1}} \:\mathrm{comes}\:\mathrm{to}\:\mathrm{rest}\:\mathrm{after}\:\mathrm{travelling} \\ $$$$\mathrm{40}\:\mathrm{m}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{friction}. \\ $$$$\left(\mathrm{Given},\:{g}\:=\:\mathrm{9}.\mathrm{8}\:\mathrm{m}/\mathrm{s}^{\mathrm{2}} \right) \\ $$ Commented by Tinkutara last updated…
Question Number 20346 by Tinkutara last updated on 25/Aug/17 $$\mathrm{To}\:\mathrm{paint}\:\mathrm{the}\:\mathrm{side}\:\mathrm{of}\:\mathrm{a}\:\mathrm{building},\:\mathrm{painter} \\ $$$$\mathrm{normally}\:\mathrm{hoists}\:\mathrm{himself}\:\mathrm{up}\:\mathrm{by}\:\mathrm{pulling}\:\mathrm{on} \\ $$$$\mathrm{the}\:\mathrm{rope}\:{A}\:\mathrm{as}\:\mathrm{in}\:\mathrm{figure}.\:\mathrm{The}\:\mathrm{painter}\:\mathrm{and} \\ $$$$\mathrm{platform}\:\mathrm{together}\:\mathrm{weigh}\:\mathrm{200}\:\mathrm{N}.\:\mathrm{The} \\ $$$$\mathrm{rope}\:{B}\:\mathrm{can}\:\mathrm{withstand}\:\mathrm{300}\:\mathrm{N}.\:\mathrm{Find}\:\mathrm{the} \\ $$$$\mathrm{maximum}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{the}\:\mathrm{painter}. \\ $$ Commented by Tinkutara…
Question Number 151418 by mathdanisur last updated on 20/Aug/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{last}\:\mathrm{three}\:\mathrm{digits}: \\ $$$$\mathrm{49}^{\mathrm{303}} \:\centerdot\:\mathrm{3993}^{\mathrm{202}} \:\centerdot\:\mathrm{39}^{\mathrm{606}} \\ $$ Answered by Olaf_Thorendsen last updated on 21/Aug/21 $${x}\:=\:\mathrm{49}^{\mathrm{303}} .\mathrm{3993}^{\mathrm{202}}…
Question Number 20344 by Tinkutara last updated on 25/Aug/17 $$\mathrm{Determine}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{with}\:\mathrm{which}\:\mathrm{block} \\ $$$${B}\:\mathrm{rises}\:\mathrm{in}\:\mathrm{figure}\:\mathrm{if}\:\mathrm{the}\:\mathrm{end}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cord}\:\mathrm{at} \\ $$$${A}\:\mathrm{is}\:\mathrm{pulled}\:\mathrm{down}\:\mathrm{with}\:\mathrm{a}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{2}\:\mathrm{m}/\mathrm{s}. \\ $$ Commented by Tinkutara last updated on 25/Aug/17 Commented by…
Question Number 151415 by ArielVyny last updated on 20/Aug/21 $$\int_{\mathrm{0}} ^{\infty} \frac{{ln}\left({x}\right){arctg}\left({x}\right)}{{x}\left({x}^{\mathrm{2}} +\mathrm{1}\right)}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 85875 by sakeefhasan05@gmail.com last updated on 25/Mar/20 $$\int\left(\frac{\mathrm{1}}{\mathrm{7}\left[\mathrm{1}−\frac{\mathrm{1}}{\mathrm{7}}\mathrm{e}^{\mathrm{x}} \right]}\right)\:\mathrm{dx} \\ $$ Answered by TANMAY PANACEA. last updated on 25/Mar/20 $$\frac{\mathrm{1}}{\mathrm{7}}\int\frac{{e}^{−{x}} {dx}}{{e}^{−{x}} −\frac{\mathrm{1}}{\mathrm{7}}}\:\left(\boldsymbol{{multiply}}\:\boldsymbol{{N}}_{{r}} {and}\:{D}_{{r}}…
Question Number 20338 by Tinkutara last updated on 25/Aug/17 $$\mathrm{Why}\:\mathrm{Al}_{\mathrm{2}} \mathrm{O}_{\mathrm{3}} \:\mathrm{is}\:\mathrm{amphoteric}\:\mathrm{while}\:\mathrm{B}_{\mathrm{2}} \mathrm{O}_{\mathrm{3}} \\ $$$$\mathrm{is}\:\mathrm{acidic}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com