Question Number 20239 by tammi last updated on 24/Aug/17 $$\int\frac{\left(\mathrm{2}{x}+\mathrm{3}\right){dx}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{7}}} \\ $$ Answered by $@ty@m last updated on 25/Aug/17 $$=\int\frac{\mathrm{2}{x}+\mathrm{4}−\mathrm{1}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{7}}}{dx} \\ $$$$=\int\frac{\mathrm{2}{x}+\mathrm{4}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{7}}}{dx}−\int\frac{{dx}}{\:\sqrt{\left({x}+\mathrm{2}\right)^{\mathrm{2}}…
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Question Number 20238 by tammi last updated on 24/Aug/17 $$\int\frac{{dx}}{{x}^{\mathrm{2}} −{x}+\mathrm{1}} \\ $$ Commented by tammi last updated on 24/Aug/17 $${this}\:{answer}\:{is}\frac{\mathrm{2}}{\:\sqrt{\mathrm{3}}}\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{2}{x}−\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right)+{c} \\ $$$${i}\:{know}\:{the}\:{answer}\:{but}\:{can}\:{not}\:{solve}\:{this}\:{prblm}..{help} \\…
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Question Number 20237 by tammi last updated on 24/Aug/17 $$\int\frac{{e}^{\mathrm{tan}^{−\mathrm{1}} {x}} }{\mathrm{1}+{x}^{\mathrm{2}} }{dx} \\ $$ Commented by Tinkutara last updated on 24/Aug/17 $$\mathrm{Same}\:\mathrm{as}\:\mathrm{Q}.\:\mathrm{20164}. \\ $$…
Question Number 20235 by naziri1920@gmail.com last updated on 24/Aug/17 $$ \\ $$$${if}\:\:\:\:\:\:\:\:{t}_{\left({m}+\mathrm{1}\right)} =\mathrm{2}{t}_{\left({n}+\mathrm{1}\right)} \\ $$$${so}\:{proof} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{t}_{\left(\mathrm{3}{m}+\mathrm{1}\right)} =\mathrm{2}{t}_{\left({m}+{n}+\mathrm{1}\right)\:\:\:\:\:\:} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{help}\:{please}……… \\ $$$$ \\ $$$$ \\…
Question Number 151307 by mathdanisur last updated on 19/Aug/21 $$\mathrm{if}\:\:\mathrm{x}\sqrt{\mathrm{x}}\:-\:\mathrm{26}\sqrt{\mathrm{x}}\:=\:\mathrm{5} \\ $$$$\mathrm{find}\:\:\mathrm{x}\:-\:\mathrm{5}\sqrt{\mathrm{x}}\:=\:? \\ $$ Answered by MJS_new last updated on 20/Aug/21 $${x}\sqrt{{x}}−\mathrm{26}\sqrt{{x}}−\mathrm{5}=\mathrm{0} \\ $$$$\left(\sqrt{{x}}+\mathrm{5}\right)\left({x}−\mathrm{5}\sqrt{{x}}−\mathrm{1}\right)=\mathrm{0} \\…
Question Number 85766 by jagoll last updated on 24/Mar/20 $$\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{1}−\mathrm{sin}\:\left(\mathrm{x}+\mathrm{2y}\right) \\ $$ Commented by jagoll last updated on 24/Mar/20 $$\mathrm{u}\:=\:\mathrm{x}+\mathrm{2y} \\ $$$$\frac{\mathrm{du}}{\mathrm{dx}}\:=\:\mathrm{1}+\mathrm{2}\frac{\mathrm{dy}}{\mathrm{dx}} \\ $$$$\frac{\mathrm{2dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{du}}{\mathrm{dx}}−\mathrm{1}\:\Rightarrow\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\left[\:\frac{\mathrm{du}}{\mathrm{dx}}−\mathrm{1}\right] \\…
Question Number 151300 by mathdanisur last updated on 19/Aug/21 $$\mathrm{5}\:\centerdot\:\mathrm{6},\mathrm{02}\centerdot\mathrm{10}^{\mathrm{23}} \:=\:?\:\left(\mathrm{solution}\right) \\ $$$$\left.\mathrm{a}\left.\right)\mathrm{3},\mathrm{01}\centerdot\mathrm{10}^{\mathrm{24}} \:\:\:\mathrm{b}\right)\mathrm{3},\mathrm{01}\centerdot\mathrm{10}^{\mathrm{22}} \\ $$ Answered by puissant last updated on 19/Aug/21 $$\mathrm{5}×\mathrm{6},\mathrm{02}.\mathrm{10}^{\mathrm{23}} =\mathrm{3},\mathrm{1}.\mathrm{10}^{\mathrm{24}}…