Question Number 85513 by niroj last updated on 22/Mar/20 $$\:\boldsymbol{\mathrm{Solve}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{following}}\:\boldsymbol{\mathrm{equation}}: \\ $$$$\:\:\left(\frac{\boldsymbol{\mathrm{dy}}}{\boldsymbol{\mathrm{dx}}}\right)^{\mathrm{2}} +\mathrm{2}\boldsymbol{\mathrm{y}}\:\boldsymbol{\mathrm{cot}}\:\boldsymbol{\mathrm{x}}\:\frac{\boldsymbol{\mathrm{dy}}}{\boldsymbol{\mathrm{dx}}}\:=\:\boldsymbol{\mathrm{y}}^{\mathrm{2}} \\ $$ Answered by mr W last updated on 22/Mar/20 $$\frac{{dy}}{{dx}}=−{y}\:\mathrm{cot}\:{x}\pm\sqrt{{y}^{\mathrm{2}} \mathrm{cot}^{\mathrm{2}}…
Question Number 19976 by Tinkutara last updated on 19/Aug/17 $$\mathrm{Three}\:\mathrm{vectors}\:\overset{\rightarrow} {{A}},\:\overset{\rightarrow} {{B}}\:\mathrm{and}\:\overset{\rightarrow} {{C}}\:\mathrm{add}\:\mathrm{up}\:\mathrm{to} \\ $$$$\mathrm{zero}.\:\mathrm{Find}\:\mathrm{which}\:\mathrm{is}\:\mathrm{false}. \\ $$$$\left({a}\right)\:\left(\overset{\rightarrow} {{A}}×\overset{\rightarrow} {{B}}\right)×\overset{\rightarrow} {{C}}\:\mathrm{is}\:\mathrm{not}\:\mathrm{zero}\:\mathrm{unless}\:\overset{\rightarrow} {{B}},\:\overset{\rightarrow} {{C}} \\ $$$$\mathrm{are}\:\mathrm{parallel} \\…
Question Number 151045 by mathdanisur last updated on 17/Aug/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 19970 by Tinkutara last updated on 19/Aug/17 $$\mathrm{The}\:\mathrm{velocity}-\mathrm{time}\:\mathrm{graph}\:\mathrm{of}\:\mathrm{a}\:\mathrm{body}\:\mathrm{is} \\ $$$$\mathrm{shown}\:\mathrm{in}\:\mathrm{figure}.\:\mathrm{The}\:\mathrm{displacement} \\ $$$$\mathrm{covered}\:\mathrm{by}\:\mathrm{the}\:\mathrm{body}\:\mathrm{in}\:\mathrm{8}\:\mathrm{seconds}\:\mathrm{is} \\ $$ Commented by Tinkutara last updated on 19/Aug/17 Commented by…
Question Number 151043 by mathdanisur last updated on 17/Aug/21 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{system}: \\ $$$$\begin{cases}{\boldsymbol{\mathrm{y}}\:=\:\frac{\mathrm{2x}}{\mathrm{1}−\mathrm{x}^{\mathrm{2}} }}\\{\boldsymbol{\mathrm{z}}\:=\:\frac{\mathrm{2y}}{\mathrm{1}−\mathrm{y}^{\mathrm{2}} }}\\{\boldsymbol{\mathrm{x}}\:=\:\frac{\mathrm{2z}}{\mathrm{1}−\mathrm{z}^{\mathrm{2}} }}\end{cases} \\ $$ Answered by john_santu last updated on 18/Aug/21 $$\mathrm{x}=\mathrm{y}=\mathrm{z}\:\Rightarrow\mathrm{x}=\frac{\mathrm{2x}}{\mathrm{1}−\mathrm{x}^{\mathrm{2}}…
Question Number 151042 by mathdanisur last updated on 17/Aug/21 $$\mathrm{if}\:\:\sqrt{\sqrt[{\mathrm{3}}]{\mathrm{9}}\:−\:\mathrm{1}}\:+\:\sqrt{\sqrt[{\mathrm{3}}]{\mathrm{16}}\:−\:\sqrt[{\mathrm{3}}]{\mathrm{4}}}\:=\:\sqrt{\boldsymbol{\mathrm{x}}}\:\:;\:\:\boldsymbol{\mathrm{x}}\in\mathbb{Z} \\ $$$$\mathrm{find}\:\:\boldsymbol{\mathrm{x}}=? \\ $$ Commented by MJS_new last updated on 18/Aug/21 $${x}\notin\mathbb{Z} \\ $$ Terms…
Question Number 151037 by qaz last updated on 17/Aug/21 $$\underset{\mathrm{r}=\mathrm{1},\mathrm{r}\neq\mathrm{s}} {\overset{\mathrm{n}} {\sum}}\:\:\underset{\mathrm{s}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\frac{\mathrm{rs}}{\mathrm{n}\left(\mathrm{n}−\mathrm{1}\right)}\overset{?} {=}\frac{\left(\mathrm{n}+\mathrm{1}\right)\left(\mathrm{3n}+\mathrm{2}\right)}{\mathrm{12}} \\ $$ Answered by mindispower last updated on 17/Aug/21 $$=\underset{{r}=\mathrm{1}}…
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Question Number 85503 by john santu last updated on 22/Mar/20 $$\frac{{dy}}{{dx}}\:=\:\mathrm{sec}\:\left({x}+{y}\right)\: \\ $$ Answered by mr W last updated on 22/Mar/20 $${u}={x}+{y} \\ $$$$\frac{{du}}{{dx}}=\mathrm{1}+\frac{{dy}}{{dx}} \\…
Question Number 85500 by oustmuchiya@gmail.com last updated on 22/Mar/20 $${The}\:{function}\:{of}\:\boldsymbol{\mathrm{f}}\:{and}\:\boldsymbol{\mathrm{g}}\:{are}\:{defined}\:{by}\:\boldsymbol{\mathrm{f}}:\boldsymbol{\mathrm{g}}\rightarrow\frac{{x}}{\boldsymbol{\mathrm{b}}{x}−\mathrm{2}},\:{x}\:\neq\:\frac{\mathrm{2}}{\boldsymbol{\mathrm{b}}}\:{and}\:\boldsymbol{\mathrm{b}}\:\neq\:\mathrm{0},\:{where}\:\boldsymbol{\mathrm{a}}\:{and}\:\boldsymbol{\mathrm{b}}\:{are}\:{real}\:{numbers}\:\boldsymbol{\mathrm{g}}:\boldsymbol{\mathrm{x}}\:\rightarrow\mathrm{2}{x}−\mathrm{11} \\ $$$$\left({a}\right)\:{If}\:\boldsymbol{\mathrm{f}}\left(\mathrm{2}\right)=\:\frac{-\mathrm{1}}{\mathrm{2}}\:{and}\:\boldsymbol{\mathrm{f}}^{−\mathrm{1}} \left(\mathrm{1}\right)\:=\:-\mathrm{1},\:{find}\:\boldsymbol{\mathrm{a}}\:{and}\:\boldsymbol{\mathrm{b}}\:{and}\:{write}\:{down}\:{the}\:{expression}\:{for}\:\boldsymbol{\mathrm{f}}\:{in}\:{terms}\:{of}\:\boldsymbol{\mathrm{x}} \\ $$$$\left(\boldsymbol{\mathrm{b}}\right)\:\boldsymbol{\mathrm{F}}{ind}\:{the}\:{value}\:{of}\:\boldsymbol{\mathrm{x}}\:{for}\:{which}\:\boldsymbol{\mathrm{fg}}\left(\boldsymbol{\mathrm{x}}\right)=\:\frac{-\mathrm{1}}{\mathrm{2}} \\ $$ Answered by john santu last updated on 22/Mar/20…